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3. Find the value of Sin25°cos 65°tan 23°cot 670llr at P ARi a cmmon |
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Answer» Sin 25 = cos(90 - 25) = cos 65. Tan 23 = cot(90 - 23) = cot 67. Given, sin 25/cos 65 + tan 23/cot67 = cos65/cos65 + cot67/cot67 = 1 + 1 = 2. |
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