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In the given figure, BDLBC, DELAB and ACLBC. Provethat BE/DE = AC/BC. |
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Answer» In the triangle DEB and triangle ACD.angle DEB=Angle ABC (you can see if you have the picture).anlge DEB = angle ACD (each is of 90)therefor we can easily say that triangle DEB= triangle ACB ( according to AA rule)Hence BE/BC =AC/DEAnd then now we can have BE/DE = AC/BC |
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