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square of (-10) is 100and cube of (-5) is -125hence adding both100-125=-25

3t3 = 5t5tn=a+(n-1)d3(a+2d)=5(a+4d)3a+6d=5a+20d-14d=2aa=-7dt8=a+7d=-7d+7d=0

Let the areas be 2x and 3x.So, 2x=1/2×base×height.Height is same in both cases, so let it be h.So, 2x=1/2×6×hTherefore x=3h/23x=1/2×b×hPutting value of x,3×3h/2=bh/2h/2 gets cancelled,3×3=b=>b=9

Base of the bigger triangle is 9. It cam be done simply by comparing the ratios, but i elaborated for understanding.

Four small circle having radius=rbigger circles radius is=RCircumference of circle is =2×π×r4×2πr=2πRR=4rArea=area of bigger circle/area of small circleArea=π×R×R/π×r×rArea=(R/r)^2(put value of R in given )=4×4=16

If a number exceed by 25% of itself = 60.

then 100% or the number will be 60 x 4 = 240.

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1, 3, 5, ,,,,,; d=a2-a2=5-3=2; n=

3x+ 5= 443x= 44--5 =39/3x=13

7th term = (a+6d) 11th term = (a+10d)(a+6d)7 since 7th term of the ap is 7 times and the same for 11th term(a+6d)7=(A+10d)11 (given)7a + 42d =11a +110d (on solving)7a - 11a = 110d - 42d-4a = -68da= -17d

we know 18th term = (a+17d)................................. (i)now we substitute the value of a in (i)which emplies, -17d + 17d = 0

7th term = (a+6d) 11th term = (a+10d)(a+6d)7 since 7th term of the ap is 7 times and the same for 11th term(a+6d)7=(A+10d)11 (given)7a + 42d =11a +110d (on solving)7a - 11a = 110d - 42d-4a = -68da= -17d

we know 18th term = (a+17d)................................. (i)now we substitute the value of a in (i)which emplies, -17d + 17d = 0

Let the no. be x.

so,

5x=60+5

5x=65

x=65/5

x=13

0.062363 is correct answer

thank

14

thank u

Let the no. be nReciprocal of no. = 1/nThen as per given condition

n = 1/n + 8/3n = (3 + 8n)/3n

3n^2 - 8n - 3 = 03n^2 - 9n + n - 3 = 03n(n - 3) + 1(n-3)=0(3n +1)(n-3)=0n = - 1/3, 3

Number is 3

YES THEY are following this theorem as 5^2=3^2+4^2so YES

1 x=42 x=13 x=3

1 x=42 x=13 x=3

Given 16x - 10/x = 27⇒ (16x²- 10)/x = 27⇒ 16x² - 10 = 27x⇒ 16x² - 10 - 27x = 0⇒ 16x² - 27x -10 = 0⇒ 16x² - 32x + 5x - 10 = 0⇒ 16x(x - 2) + 5(x - 2) = 0⇒ (x - 2) (16x +5 ) =0⇒ (x-2) = 0 or (16x + 5) = 0⇒ x = 2 or 16x = -5⇒ x = 2 or x = -5/16∴ x = 2 , -5/16

16x - 10/x= 27

(16x(x) - 10)/x = 27

16x² -10= 27x

16x²-27x-10=0

16x²-32x +5x-10=0

[By middle term splitting]

16x(x-2)+5(x-2)=0

(16x+5) (x-2)=0

16x+5=0 or x-2=0

16x=-5 , x=-5/16; x=2

Hence, the two roots of the equation are x= -5/16 & x=2.

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1/10th of 7.2 is 0.72

so 7.2 exceeds 0.72 by = 7.2-0.72 = 6.48

3/4 X 128 = 96 does not "exceed"3/4 X 129 = 96.75 ... is greater than,or exceeds 128

1-2√6/3a= 1b = -2√6/3= -2√2/√3

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Answer:



Step-by-step explanation:



=

=

= $16x^{3}(x^{2}-3^{2})$

=$16x+3)(x-3)$

/*Byalgebraicidentity:



Therefore,



Step-by-step explanation:16x5 − 144x3

= 16x3(x2 − 9)

= 16 x3 [(x)2 − (3)2]

= 16 x3(x − 3) (x + 3) [a2 − b2 = (a − b) (a + b)]

areaof asectorof a circle is ½ r² ∅,=1/2*r^2*120*π/180=24πhencer^2=24*2*180/120=72r=√72=6√2cm

solve

Suppose72*14= 1008nowयदि हम1008/112 करे तो हमको 9 मिलेगाअतः option c is right

thanks