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Find the number which exceeds its reciprocal by 2Find the 7 term from tha nnd |
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Answer» Let the no. be nReciprocal of no. = 1/nThen as per given condition n = 1/n + 8/3n = (3 + 8n)/3n 3n^2 - 8n - 3 = 03n^2 - 9n + n - 3 = 03n(n - 3) + 1(n-3)=0(3n +1)(n-3)=0n = - 1/3, 3 Number is 3 |
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