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2. Find the root of the equation. 16x-1027= |
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Answer» 16x - 10/x= 27 (16x(x) - 10)/x = 27 16x² -10= 27x 16x²-27x-10=0 16x²-32x +5x-10=0 [By middle term splitting] 16x(x-2)+5(x-2)=0 (16x+5) (x-2)=0 16x+5=0 or x-2=0 16x=-5 , x=-5/16; x=2 Hence, the two roots of the equation are x= -5/16 & x=2. Like my answer if you find it useful! |
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