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l=rthetatheta=l/r=1/3radians

Ans :- Noise pollution, also known as environmental noise or sound pollution, is the propagation of noise with harmful impact on the activity of human or animal life. The average noise level of 97.60 dB obtained exceeded the WHO value of 50 dB allowed for residential areas.

Noise pollution can causehypertension, highstresslevels, tinnitus,hearing loss, sleep disturbances, and other harmful effects. Sound becomes unwanted when it either interferes with normal activities such as sleeping, conversation, or disrupts or diminishes one's quality of life.

a) is correct ans. 4√3

Digestionis the breakdown of large insolublefoodmolecules into small water-soluble food molecules so that they can be absorbed into the wateryblood plasma. In certain organisms, these smaller substances are absorbed through thesmall intestineinto theblood stream. Digestion is a form ofcatabolismthat is often divided into two processes based on how food is broken down: mechanical and chemical digestion. The termmechanical digestionrefers to the physical breakdown of large pieces of food into smaller pieces which can subsequently be accessed bydigestive enzymes. Inchemical digestion,enzymesbreak down food into the small molecules the body can use.



The rational numbers (ℚ) are included in thereal numbers(ℝ). On the other hand, they include theintegers(ℤ), which in turn include thenatural numbers(ℕ)

Inmathematics, arational numberis anynumberthat can be expressed as thequotientorfractionp/qof twointegers, anumeratorpand a non-zerodenominatorq.[1]Sinceqmay be equal to1, every integer is a rational number. Thesetof all rational numbers, often referred to as "the rationals", thefield of rationalsor thefield of rational numbersis usually denoted by a boldfaceQ(orblackboard bold{\displaystyle \mathbb {Q} }, Unicode ℚ);[2]it was thus denoted in 1895 byGiuseppe Peanoafterquoziente, Italian for "quotient".

Thedecimal expansionof a rational number always either terminates after a finite number ofdigitsor begins torepeatthe same finitesequenceof digits over and over. Moreover, any repeating or terminating decimal represents a rational number. These statements hold true not just forbase 10, but also for any other integerbase(e.g.binary,hexadecimal).

Areal numberthat is not rational is calledirrational. Irrational numbers include√2,π,e, andφ. The decimal expansion of an irrational number continues without repeating. Since the set of rational numbers iscountable, and the set of real numbers isuncountable,almost allreal numbers are irrational.[1]

Rational numbers can beformallydefined asequivalence classesof pairs of integers(p,q)such thatq≠ 0, for theequivalence relationdefined by(p1,q1) ~ (p2,q2)if, and only ifp1q2=p2q1. With this formal definition, the fractionp/qbecomes the standard notation for the equivalence class of(p,q).

Rational numbers together withadditionandmultiplicationform afieldwhich contains theintegersand is contained in any field containing the integers. In other words, the field of rational numbers is aprime field, and a field hascharacteristic zeroif and only if it contains the rational numbers as a subfield. FiniteextensionsofQare calledalgebraic number fields, and thealgebraic closureofQis the field ofalgebraic numbers.[3]

Inmathematical analysis, the rational numbers form adense subsetof the real numbers. The real numbers can be constructed from the rational numbers bycompletion, usingCauchy sequences,Dedekind cuts, or infinitedecimals.

16×3600+64×60 solve the answer

Probablity of red =0/4=0

cosA+sinA=√2cosAsquaring both the sides =>(cosA+sinA)²=2cos²A=>cos²A+sin²A+2sinAcosA=2cos²A=>cos²A-2cos²A+2sinAcosA= -sin²A=> -cos²A+2sinAcosA= -sin²A=> cos²A-2sinAcosA=sin²Aadding sin²A on both the sides => cos²A+sin²A-2sinAcosA=2sin²A=> (cosA-sinA)²=2sin²A=> cosA-sinA=√2sinA

thanks

this picture is not good okkkk so second pic next time

This picture is correct cleaner

absent = 7/40

present = 33/40

cos7A+cos5A = 2cos(7A+5A)/2×cos(7A-5A)/2 = 2cos6AcosA sin7A-sin5A = 2cos(7A+5A)/2×sin(7A-5A)/2 = 2cos(6A)sinA

on diving both 2cos6A gets cancelled, and we get = cosA/sinA = cotA

80 और 10 कोंडो का युग्म एक समकोण ( 90 ) होता है।

80"+10" कोणो का युग्म पूरक हैं l

80 10 kono ka yog mein ek sampurn 90 degree hota hai

tq

3:4=3/4=0.755:7=5/7=0.71

Therefore 3:4 is larger than 5:7

The Gandhara School of art had also developed in first century AD along with Mathura School during reign of Kushana emperor Kanishka. Both Shakas and Kushanas were patrons of Gandhara School, which is known for thefirst sculptural representations of the Buddha in human form. The art of the Gandhara school wasprimarily Mahayanaandshows Greco-Roman influence.

start date is 1st September and end date is 20 December.so number of days= 30(September) + 31 (October) + 30 (November) + 20 (December)=111 days

X^2+y^2+z^2=

R^2Cos^2alphasin^2beta + r^2cos^2alphacos^2beta+ R^2sin^2 alpha

R^2[Cos^2alpha(sin^2beta+ cos^2 beta)+sin^2 alpha]

R^2[Cos^2 alpha + sin^2 alpha]=r^2

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let x be the initial populationthen after 4% migrated to Mumbai population=x-4%of x=x-0.04x=0.96xafter 15% left village population=0.96x-15%×0.96x=0.816xalso remaining population=35700.816x=3570x=4375

Sadabhau sold 300 grafts of mango at Rs.250 each.

=>Total cost of all grafts of mango=300×Rs 250=Rs.75000

In this transaction, Sadabhau got 2% commission.

∴Amount of commission did he receive=2% of Rs.75000=Rs. 1500

Option 4 is correct.

Commission = 2% of (250*300)= 2% of Rs. 75000= 2/100 * 75000= Rs.1500

Let the wage of 1 man be rs x and the wage of 1 boy be rs y.

Now, 10x+8y=37......(1)

and, 4x=1+6y

also, 4x-6y=1.........(2)

So,(1)×2; 20x + 16y = 74.....(3)(2) ×5; 20x - 30y = 5........(4)

(3)-(4);46y = 69y= 1.5x=2.5

So, the wage of each man is rs 2.5 while the wage of each boy is rs 1.5.

A=2B3B= 4cA/B = 2/1---(multiply by 4)and B/C= 4/3A/B= 8/4now अनुपात 8:4:3 hoga

Money earned in 7 days=rs. 672Money earned in 1 day= 672÷7=rs.96Money earned in 18 days=96×18=rs. 1728

Money earned in 7 days=rs. 672Money earned in 1 day= 672÷7=rs.96Money earned in 18 days=96×18=rs. 1728

let labourer wage be l and supervisor be shence60+l=s, s-l=605s+7l=1500....givenhencemultiply equation 1 by 77s-7l=4205s+7l=1500adding 1 and 212s=1920s=160rupeeshencelaborer wage =100rupees