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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(0) Zero hasreciprocal |
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Answer» Zero has no reciprocal. Explanation:Zero does not have a reciprocal because no real number multiplied by 0 produces 1. |
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| 2. |
7) Reciprocal of |
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Answer» Reciprocal of 7/-5 is -5/7 |
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| 3. |
write the reciprocal of following -7/1/ |
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Answer» Reciprocal of -7/1=-1/7 Reciprocal of -7/1=-1/7 is the correct answer. this is a right answer plz like my answers I like yours answer 1/7 is right answer hoga -1/7 will be the answer reciprocal of -7/1=-1/7 -1/7 is the correct answer 1/7 is rigjt answer of this question reciprocal -7/1= -1/7 is right answer -1/7 is the correct answer reciprocal of -7/1 = -1/7 |
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| 4. |
Is this an obtuse angle? |
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Answer» No, visual inspection gives that it acute angle not obtuse Thank u |
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| 5. |
13. Points A (-6, 10, B (-4, 6) and C (3, -8) are29collinear such that ĐĐ--AC |
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Answer» AB=√(-6+4)²+(10-6)² =√4+16=√20=2√5AC=√(-6-3)²+(10+8)²=√81+324=√405=9√5now AB /AC=2/9or, AB=2/9AC |
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| 6. |
1. Draw an angle and lábėl it às 2BAC. CL2. Draw an obtuse angle. Bisect it. Measure each of the angles so obtained.nrntractar, draw an angle of measure 108°. With this angle |
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Answer» kon sa btaya h bhai |
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| 7. |
supliment of an obtuse angle is-? |
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Answer» The supplement of obtuse angle is an acute angle. |
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| 8. |
66) In the figure, the sum of angles x and y isA) a right angleB) an acute anglee an obtuse angleD) a straight angleIn the given square based pyramid number of face |
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Answer» Option (C) is correct. option. c) is. correct |
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| 9. |
esibers I to 6 carry I mark each.Find the nature of the roots of the quadratic equation 4x2+ 43x +3 0. |
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Answer» For this find the discriminanthenceD=b^2-4ac=(4√3)^2-4*3*4=16*3-16*3=0as discriminant is 0 hence roots are equal and real |
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| 10. |
3. Find the roots of the quadratic equation 4x2 + 4 /3x+30, if they exist, by the method of completing4the square. |
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| 11. |
What value ofm for which two roots of the quadratic equation 4x2+4(3m-1)x+(m+7)-0reciprocal to each other. |
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Answer» EQUATION-x²+x(2m-2)+(m+5) If the roots are to be real and equal then the value of discriminant(D) is to be 0. D=0 (2m-2)²-4(m+5)=0 4m²-12m-16=0 Taking 4 as common, we get- m²-3m-4=0 m²+4m-m-4=0 m(m+4)-1(m+4)=0 (m-1)(m+4)=0 Therefore m=1 or m=-4 |
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| 12. |
solve by factorisation:x2 +Ha/a+b + a+b/a]x +1-0 |
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| 13. |
nd the average rainfall during the010 1611 |
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Answer» Average annual rainfallfor a place is generallycalculatedby averaging the last 30-35 years ofannual rainfall.Annual rainfallis the sum of dailyrainfall, that can becalculatedfrom raingauge records. Here, whilecalculating average annual rainfallone must take the length of period into account |
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| 14. |
In Fig. 6.48, ACB = 90° and CD perpendicular AB prove thatBC^2 /AC^2 = BD/AD |
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| 15. |
AC289 |
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| 16. |
25. In AABC, angle B is obtuse angle, angle D 90. Prove that AC^2=AB^2+ BC^2 + 2AB.BD. |
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| 17. |
Q.12 If α, β are the roots of quadratic equation 4x2 + 3x + 7, Them find the value of |
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| 18. |
For what values of k does the quadratic equation 4x2 -12x-k 0 haveno real roots? |
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Answer» 4x^2 - 12x - k = 0 The roots of quadratic equation arex= (-b ±√(b^2-4ac))/2a If b^2-4ac is less than zero the roots are not real. a = 4, b = -12, c = -k b^2 - 4ac < 0(-12)^2 - 4(4)(-k) < 0144 + 16k < 016k < -144k < - 144/16k < - 9 In interval notation: (-∞, - 9) |
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| 19. |
1. Find the values of k for which the quadratic equation 4x +5kx+ 25 0 hasequal roots.c equation 4x2 +5kx 25has |
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| 20. |
23. Find the roots of the quadratic equation 4x2+43x +30, if they exist, by the method ofthe square. |
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| 21. |
6. For what values of k the equation 4x2-2 (k+1)x + (k+1) =0 hareal and equal roots. |
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Answer» 4x^2-2( k+1)x+( k+1)=0, k^2-2k-3=0; k^2-3k+k-3=0,; k( k-3)+1( k-3); ( k+1)( k-3)=0; k=-1 & 3 k=-1&3 is the correct answer for this question a= 4, b= 2(k+1), C= (k+1)condition for real and equal root b^2-4ac=0{2(k+1)^2-4×4(k+1)=04(k+1)^2=16(k+1)(k+1)= 4k+1=4k= 4-1=3 ((-2)(k+1))^2-(4)(4)(k+1)=04(k+1)(k+1)=16(k+1)k+1=4k=3 |
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| 22. |
3 Tn theADP0 |
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Answer» OP perpendicular XY So, /_XOQ= /_QOY (each 90 degree)------------> (i) /_QOP=/_XOQ- /_XOP--------------> (ii) /_QOP = /_POY- /_QOY --------------> (iii) But, /_QOP= /_ QOY- /_XOP[from (i)] adding (ii) and (iii) 2/_QOP=/_QOY - /_XOP+ /_POY-/_QOY=> 2/_QOP= /_POY - /_XOP |
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| 23. |
In AABC, if AD is the median, then show that AB+AC2(ADP+BD) |
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| 24. |
T कु छिकलिपटचाासादामरत शपकाफेििट्िफिटेनिलिकाटमभवलाकर्रिक रन PN;m.;mw G BR <Ets KNS । 2 ’ |
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Answer» 8 is a answer. . |
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| 25. |
V3If sec26(1+sin)(1-sin θ)-k,then find the value of k.F (450 -os 450)3) |
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| 26. |
g bR G s o न की i कर २ जन कल जन पर कर लक बा लिन P मा का न el eyनगद ३A |
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Answer» From which book have you taken this question? Please tell us so that we can provide you faster answer. |
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| 27. |
280°Fig. Q. 10Fig. Q. IIFig. Q. 1212. In the given figure, pll g and rIIs. Find the angles a, b and c. |
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| 28. |
AR/AR-15-MTH/OS-07-MT-I15.The roots of the equation 4x2 + kx + 3 =are real and equal. What is the valueof k ? |
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Answer» The equation is 4x²+kx+3 = 0 now for real and equal roots ∆ = b²-4ac= 0 => (k)²-(4*4*3) = 0=> k² = 48=> k = ±√48 = ±4√3 |
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| 29. |
LW IR N G W W SRRली उत्तरीय प्रश्न-(क) जीवन में किन्हें लक्ष्य की प्राप्ति होती हैं? समझाकर लिखिए।औ कुल U &G हरि MLl br L0 vl |
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Answer» जिनके जीवन में कुछ लक्ष्य होता है क्योंकि बिना लक्ष्य के जीवन का कुछ मतलब नहीं अपने लक्ष्य को प्राथमिकता देजब कोई व्यक्ति अपने किसी लक्ष्य को हासिल करने के लिए कार्य करता है तो वह अपने लक्ष्य को ही प्राथमिकता देता है इसीलिए यदि आप भी अपने लक्ष्य को प्राप्त करना चाहते है तो इसके लिए सबसे पहले आप अपने किसी अन्य काम को छोड़ कर अपन लक्ष्य की प्राप्ति के लिए किये गए कामो को प्राथमिकता दे | |
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| 30. |
प् नये 0५ 2-८० श्रकद i कपउन न ः न 4U Ao. 'f =~ol?’ ottt , Her ol= | हनन |
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Answer» Given: 2x²-3x+k .........(1 Let the 2 zeroes be α & 1/α Quadratic form : ax²+bx+c.........( 2 On comparing eq 1 & eq 2 we get a=2 ,b = -3, c= k Product of zeroes = α × 1/α = 1 Product of zeroes= c/a 1= k/ 2 K= 2 Like if you find it useful |
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| 31. |
. Find the vaive of k foos which one oot of the uasratic eyation |
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| 32. |
हे... एल राहै 2 3:07g 2% 15.4 |8 का मान ज्ञात कीजिए । |
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| 33. |
G 2q %-82 |
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| 34. |
p² g ² + 2 pq so +5²8 |
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Answer» (pq+sr)² is the right answer |
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| 35. |
-डे ४४ 1G 28 9 No- q O |
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| 36. |
पक yalwofk, (a) 8 a Zewo g =E‘ 2 - कव द G e | L |
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Answer» For (-a) to be zero we must put (-a) in the place of xa²-2a²-k=0-a²= Kvalue of K should be -a² |
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| 37. |
Note: the cutis a quarter+10 cm20 cm |
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Answer» 1\2*b*h use this to help u |
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| 38. |
In Fig. 1, O is the centre of the circle, PQ is a chord and PT is tangent to the circle at P.If< POQ = 70°, find < TPQ70°(Fig. -1) |
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| 39. |
QeFind He vaiveol =l + 9 = oo |
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| 40. |
In Fig. 1, AOB is a diameter of a circle with centre O and AC is a tangent to the circleat A. If LBOC-130°, then find ACO.Fig. 1 |
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Answer» angle AOC = 180° - 130° = 50° angle OAC = 90° Reason : AC is tangent to radius. Therefore, AOC + ACO + OAC = 180° ACO = 180° - 140° = 40° |
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| 41. |
In Fig. 1. AOB is a diameter of a circle with centre O and AC is a tangent to the circleat A. If <BOC= 130°, then find Aco.Fig. 1 |
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| 42. |
0) 860*0+1आ 0 12 इन, (8०८ 0-(्ा8)-अवर बान दिमाव का नियि। |
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| 43. |
13. Use Euclid's Division Algorithm to find the HCF of 92690, 7378 and 7161 |
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Answer» By Euclid’s division algorithm, 92690 = 7378 x 12 + 41547378 = 4154 x 1+ 32244154 = 3224 x 1 + 9303224 = 930 x 3 + 434930 = 434 x 2 + 62434 = 62 x 7 + 0 Therefore, HCF (92690, 7378) = 62 7161 = 62 x 115 + 3162 = 31 x 2 + 0 Therefore, HCF(7161, 62) = 31 Hence, HCF (92690, 7378, 7161) = 31 |
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| 44. |
Three rolls of cello-tape cost 48. At thesame rate, the cost of 12 rolls of cello tape is |
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Answer» 3 are of 48so 12 are of (12×48)/3=4×48=192 sir I have one more can u solve |
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| 45. |
0. The length of a rectangle is 7 more than its breadth. If the permeter is 34 cm, then the length of the recta(a) 7 cm(c) 17 cm(b)(d)10 cm20 cm |
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Answer» Answer:c)17cmExplanation Given :l=7+bp=54cm Now perimeter of rectangle=2(l+b) =2(7+b+b) 54=2(7+2b)27=7+2b20=2bb=10 cm Thus l=7+b =7+10 =17cm |
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| 46. |
(1) Draw seg PQ of length 7 cm. Divide it in the ratio 3: 2. |
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Answer» The line of 7cm length is divided in 3:2 ratio. So, one length would be (3/5)*7= 4.2cm. Other length = (2/5)*7= 2.8cm Please hit the like button if this helped you |
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| 47. |
(1) Draw seg PQ of length 7 cm. Divide it in the ratio 3 : 2. |
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| 48. |
In Fig. 1043, ABCD is a trapezium such that ABIDC. Find 4D and C andverify that sum of the four angles is 360.4070%Fig. 10.43 |
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Answer» Given, AB || DC Then,angle A + angle C = 180°(cointerior angles)angle C = 180 - 40 = 140° angle B + angle D = 180°(cointerior angles)angle D = 180 - 70 = 110° Now, angle A + angle B + angle C + angle D = 40 + 70 + 140 + 110= 360 Therefore, sum of all angles of trapezium is 360° |
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| 49. |
Fig. 10.38in Fig. 10.39. A. B, C and D are four points on acircle. AC and BD intersect at a point E suchthat BEC = 130° and ECD = 20°. Find4BAC.D)13021C.360Fig. 10.39 |
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| 50. |
13. Prove that sum of the quadrilateral is 360?fig 1.5 |
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