6. For what values of k the equation 4x2-2 (k+1)x + (k+1) =0 hareal an

1.	6. For what values of k the equation 4x2-2 (k+1)x + (k+1) =0 hareal and equal roots.
Answer» 4x^2-2( k+1)x+( k+1)=0, k^2-2k-3=0; k^2-3k+k-3=0,; k( k-3)+1( k-3); ( k+1)( k-3)=0; k=-1 & 3 k=-1&3 is the correct answer for this question a= 4, b= 2(k+1), C= (k+1)condition for real and equal root b^2-4ac=0{2(k+1)^2-4×4(k+1)=04(k+1)^2=16(k+1)(k+1)= 4k+1=4k= 4-1=3 ((-2)(k+1))^2-(4)(4)(k+1)=04(k+1)(k+1)=16(k+1)k+1=4k=3

6. For what values of k the equation 4x2-2 (k+1)x + (k+1) =0 hareal and equal roots.

Answer»

4x^2-2( k+1)x+( k+1)=0, k^2-2k-3=0; k^2-3k+k-3=0,; k( k-3)+1( k-3); ( k+1)( k-3)=0; k=-1 & 3

k=-1&3 is the correct answer for this question

a= 4, b= 2(k+1), C= (k+1)condition for real and equal root b^2-4ac=0{2(k+1)^2-4×4(k+1)=04(k+1)^2=16(k+1)(k+1)= 4k+1=4k= 4-1=3

((-2)(k+1))^2-(4)(4)(k+1)=04(k+1)(k+1)=16(k+1)k+1=4k=3