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for a number to be divisible by 11

the sum of digits at odd place - sum of digits of even place , should be equal to multiple of 11

here the number is. 3178965 sum of odd place digits = 3+7+9+5 = 24 sum of even place digits = 1+8+6= 15

difference = 24-15 = 9 and since 9 is not a multiple of 11 so, the number is not a multiple of 11

-709- (-5020+2320)= -709-2700=1991

the answer is the questionthe answer is 1991

yes it is divisibleas test of divisibility of 5 is the number rahould end with 0 or 5

but all method

rest two questions is not complete.. please post it again

1+0+8 = 9

9 is divisible by 3

So, 108 is divisible by 3.

Divisibility of 2: The last digit of number must be 0,2,4,6 or 8

Number=3142Last digit is 2So, 3142 is divisible by 2

AB || DC we have<A + <D = 180°

angle D= 180-40= 140also

<B + <C = 180°

angle c= 110

∆ABC A-18,B-54,C-108

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apka yeh answer wrong hai

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2- once place should be even3- sum of all digits should be divisible by 34- last two digits should be divisible by 45- once place should be 0,56- number is divisible by 2,38- last three digits should be divisible by 89- sum of all digits should be divisible by 910- once place should be 011- subtract the numbers odd and even

70°,70°,110° is the correct answer of the given question

Length of each side of cube = 5 cmNow, 3 cubes are joined end to end.So, the length of the resulting cuboid will be = 5+5+5 = 15 cmBut, the breadth and height will remain the same.So, Breadth = 5 cm and Height = 5 cmSurface area of the cuboid = 2(LB + BH +HL)= 2(15*5 + 5*5 + 5*15)= 2(75 + 25 + 75)= 2*175Surface area of the cuboid = 350 sq cm

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Solution:Apply remainder theorem=>x – a =0=> x = aReplace x by a we get=> x3– ax2+ 6x – a=>( a)3-a(a)2+ 6(a) - a=> a3sup> – a3+ 6a – a=> 5aRemainder is 5a

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To prove that√5 is irrational numberLet us assume that√5 is rationalThen√5 =a/b(a and b are co primes, with only 1 common factor and b≠0)⇒√5 = a/b(cross multiply)⇒ a =√5b⇒ a² = 5b² ------->α⇒ 5/a²(by theorem if p divides q then p can also divide q²)⇒ 5/a ----> 1⇒ a = 5c(squaring on both sides)⇒ a² = 25c² ---->βFrom equationsα andβ⇒ 5b² = 25c²⇒ b² = 5c²⇒ 5/b²(again by theorem)⇒ 5/b-------> 2

we know that a and b are co-primes having only 1 common factor but from 1 and 2 we can that it is wrong.This contradiction arises because we assumed that√5 is a rational number∴ our assumption is wrong∴√5 is irrational number

It can be observed that

Radius (r) of cylindrical part = Radius (r) of hemispherical part = 2.8/2 = 1.4 cm

Length of each hemispherical part = Radius of hemispherical part = 1.4 cm

Length (h) of cylindrical part = 5 − 2 × Length of hemispherical part

= 5 − 2 × 1.4 = 2.2 cm

Volume of one gulab jamun = Vol. of cylindrical part + 2 × Vol. of hemispherical part

πr^2h+2*2/3πr^3=πr^2h+4/3πr^322/7*1.4*1.4*2.2+4/3*22/7*1.4*1.4*1.4=25.04cm^3Volume of 45 gulab jamuns =45 x 25.05 = 1,127.25 cm^3

Volume of sugar syrup = 30% of volume

= 30/100 x1127.25

= 338.17 cm^3

= 338 cm^3

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first line explain it sakte h samaj me bhi aa that mujhe

A.P main common difference same hain na.matlab a, b, c AP main hai tho.

d = b-a = c-b

ab b-a = c-b => 2b = a+c

|11 14 17|D= |12 15 18| |13 16 19|

R₃→R₃-R₂ and R₂→R₂-R₁|11 3 3||12 3 3|=D|13 3 3|

R₃→R₃-R₂

|11 3 0||12 3 0|=D|13 3 0|D=0

to find smallest 7 digit numberlet 7 digit number be x so first take leadt 7 digit number ie 1000000

dividide 1000000/532 =1879.6so the next number ie 1880 is dicisible by 532

ie 1880 ×532 = 1000160 is the amswer

least 7 digit number

1000160 is right answerMay this help you

1000160is the smallest 7digits no which is divisible by 532

1000160 is correct answer hai

1000160 is the smallest 7digits no which is divisible by 532

1000160 is the right answer

1000160 is the right answer

The first marble can be put into the pockets in 6 ways, so can the second and third. Thus, the number of ways in which the child can put the marbles

= 6 X 6 X 6 = 216 ways

Total number of Outcome (Cards) = 52

First eliminate half the deck, so as to get rid of the black cards. This leaves,

1/2× 52 = 26 Cards

However, two king were already gotten rid of when all the black cards were removed, leaving only two black king.Thus, we take two black king away from our remaining cards,

26 - 2 = 24

∴ Number of Favourable Outcomes = 24

P(getting neither a black nor a king) = 24/52

= 6/13

We know product of roots = c/aSo product of root is -25B) -25 Option is correct