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13. Points A (-6, 10, B (-4, 6) and C (3, -8) are29collinear such that АВ--AC

Answer»

AB=√(-6+4)²+(10-6)² =√4+16=√20=2√5AC=√(-6-3)²+(10+8)²=√81+324=√405=9√5now AB /AC=2/9or, AB=2/9AC



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