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In Fig. 1, AOB is a diameter of a circle with centre O and AC is a tangent to the circleat A. If LBOC-130°, then find ACO.Fig. 1 |
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Answer» angle AOC = 180° - 130° = 50° angle OAC = 90° Reason : AC is tangent to radius. Therefore, AOC + ACO + OAC = 180° ACO = 180° - 140° = 40° |
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