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| 6601. |
Find the 7th term in the expansion of a/b (-b/2a²)¹² |
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| 6602. |
3643+63 |
| Answer» 3706 | |
| 6603. |
In linear enequalities,how change the symbol? |
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| 6604. |
If H1,H2,.....Hn be n harmonic means between a and b,then H1+a/H1-a + Hn+b/Hn+b is equal to?? |
| Answer» We\xa0have,a,\xa0H1,H2,.......Hn,b\xa0in\xa0H.P.⇒1a,1H1,1H2,......1Hn,1bThere\xa0are\xa0n+2\xa0terms⇒1b=1a+(n+2−1)d⇒1b−1a=(n+1)d⇒(n+1)d=a−bab⇒d=(a−b)(n+1)ab1H1=1a+d⇒aH1=1+ad⇒1+aH1=1+1+ad⇒H1+aH1=2+ad\xa0;equation(i)Again1H1=1a+d⇒aH1=1+ad⇒−ad=1−aH1⇒−ad=H1−aH1;equation(ii)equation(ii)÷equation(i),\xa0we\xa0get,H1−aH1+a=−ad2+ad\xa0;equation(A)Now\xa01b=1Hn+d⇒1=bHn+bd⇒1−bHn=bd⇒bd=Hn−bHn\xa0;equation(iii)Again1b=1Hn+d⇒1=bHn+bd⇒1+1=1+bHn+bd⇒2−bd=Hn+bHn⇒Hn+bHn=2−bd\xa0;equation(iv)equation(iii)÷equation(iv)⇒Hn−bHn+b=bd2−bd\xa0;equation(B)equation(A)+equation(B)⇒H1−aH1+a+Hn−bHn+b=−ad2+ad+bd2−bd⇒H1−aH1+a+Hn−bHn+b=d(b2−bd−a2+ad)⇒H1−aH1+a+Hn−bHn+b=d⎛⎝⎜⎜b2−b(a−b)(n+1)ab−a2+a(a−b)(n+1)ab⎞⎠⎟⎟=d⎛⎝⎜⎜b2−(a−b)(n+1)a−a2+(a−b)(n+1)b⎞⎠⎟⎟=(a−b)(n+1)ab{ab(n+1)2(n+1)a−(a−b)−ab(n+1)2(n+1)b−(a−b)}=(a−b)ab(n+1)(n+1)ab{12(n+1)a−(a−b)−12(n+1)b−(a−b)}=(a−b)(n+1)ab[2(n+1)b−(a−b)−2(n+1)a+(a−b){2(n+1)a−(a−b)}{2(n+1)b−(a−b)}]=(a−b)(n+1)ab[2(n+1)b−2(n+1)a{2(n+1)a−(a−b)}{2(n+1)b−(a−b)}]=(a−b)ab[2b−2a{2(n+1)a−(a−b)}{2(n+1)b−(a−b)}] | |
| 6605. |
What is the range |
| Answer» Class interval 5-10Lower limit is 5 upper limit is 10 | |
| 6606. |
What is degree measure and how to calculate it ! |
| Answer» Degree measure=180/π ×radian measure | |
| 6607. |
Tan(60 -x) + tan(60 + x) = 2cos2x + 1/2cos2x - 1 |
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| 6608. |
Sqare root of -4 |
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Answer» 2 iota Square root of any number is always positive 2 |
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| 6609. |
if tanA+tanB+tanC= 0 then cotA.cotB.cotC= |
| Answer» 1 | |
| 6610. |
-400 degree how to make with protactor |
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| 6611. |
SecA-cosecA=4/3. Find the value of sina-cosa |
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| 6612. |
Set-builder form A=[2,4,6,8.....] |
| Answer» X:X Belongs to N, N=2n | |
| 6613. |
What is the som of 5root3 |
| Answer» 15 | |
| 6614. |
1-cos theta = |
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Answer» Sin theta Sin theta÷2 |
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| 6615. |
Arg(z-1)=arg(z+3i) then find x-1:y |
| Answer» Let z=x+iy X+iy-1=x+iy+3i and (y=imaginary number along with iota and x=constant number I.e 3,4 etc)TanA=y÷x ,tanA=y÷xTanA=y÷x-1 and TanA=y+3÷x(Comparing both sides)Y÷x-1= y+3÷x( cross multiplication after we get )3x-3-y=03(x-1)=yX-1÷y=1÷3(X-1):y=1:3 | |
| 6616. |
The cost of 7 notebook is 259/4.find the cost of 1 note book |
| Answer» Cost of 7 notebook =259/7=64.74and the cost of 1 notebook =64.74/7 | |
| 6617. |
General solution of sin2x - sin4x + sin6x = 0 |
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| 6618. |
What is a co-domain |
| Answer» All the elements of set \'B\' are called co-domain of the function. | |
| 6619. |
What is permunation |
| Answer» A permutation is a arrangements in a definite order of a number of objects taken some or all at a time | |
| 6620. |
For z=2+3i verify the followingz double bar=z |
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| 6621. |
√3 into. √3 |
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Answer» 3 3 3 |
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| 6622. |
1+2+3+.....+n |
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| 6623. |
Square root of 76533 |
| Answer» 276.65 | |
| 6624. |
What is the formula of sin(a+b) |
| Answer» sin(A + B) = sin A cos B + cos A sin B. | |
| 6625. |
In how many of distinct permutations of the letter in MISSISSIPPI do the four I not come together |
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| 6626. |
Cosec (90+A)+ x cosA cot (90+A) = sin(90+A) |
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| 6627. |
find tn for the following A.P.s1). 4,9,14,19 |
| Answer» 5n-1 | |
| 6628. |
Cos36 |
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| 6629. |
Add 678542567866.87656 |
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| 6630. |
What is the locys of the center of the circle ?(please explain with diagram) |
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| 6631. |
Solve:- Sin2x – Sin4x + Sin6x = 0 |
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| 6632. |
Value of i 654 |
| Answer» -1 | |
| 6633. |
4cos12cos48cos72=cos36 |
| Answer» LHS =\xa04cos12cos48cos72 = 2 ( 2 cos\xa012cos48) cos 72 = 2 ( cos 60 + cos\xa036 ) cos 72 = 2cos 72 ( cos 60 + cos 36) = 2cos72cos60\xa0+ 2 cos72cos36 = 2 cos\xa072 * 1/2 + ( 2cos72 cos 36) = cos 72 + cos 108 + cos 36 = cos 72 + cos ( 180 - 72) + cos 36 = cos 72 - cos 72 + cos 36 = cos 36 = RHS\xa0Read more on Brainly.in - https://brainly.in/question/2057801#readmore | |
| 6634. |
sin10sin50sin60sin70 |
| Answer» Sin 10°*Sin (60°-10°)*√3/2*Sin (60°+10°)=√3/2 [1/4 Sin (3*10°)]=√3/2*1/8=√3/16 | |
| 6635. |
x\\4< (5x–2)/3 – (7x–3)/5 |
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| 6636. |
11°27\'16" convert into radian |
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| 6637. |
How we have to prove cos(A+B)+COS(A-B) PLEASE TELL WITH DIAGRAM |
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| 6638. |
Cosx÷sinx |
| Answer» cot(x) | |
| 6639. |
What is root 1 |
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| 6640. |
How can we solve supplementary material of trigonometry |
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| 6641. |
If sin (x+y) =3/5 and sin ( x-y ) then find value of cos4x |
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| 6642. |
How we can easily learn trignometry formula |
| Answer» By simply using tricks in it | |
| 6643. |
7!/8!= |
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Answer» 1/8 1/8 |
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| 6644. |
√2+√2+2cos4© |
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| 6645. |
Prove that:(B^2-c^2)cotA+(c^2-a^2)cotB+(a^2-b^2)cotC=0 |
| Answer» {tex}\\begin{array}{l}\\left(b^2-c^2\\right).cotA+\\left(c^2-a^2\\right).cotB+\\left(a^2-b^2\\right).cotC\\\\=\\left(b^2-c^2\\right)\\frac{R\\left(b^2+c^2-a^2\\right)}{abc}+\\left(c^2-a^2\\right).\\frac{R\\left(c^2+a^2-b^2\\right)}{abc}+\\left(a^2-b^2\\right).\\frac{R\\left(a^2+b^2-c^2\\right)}{abc}\\\\=\\frac R{abc}\\left[b^4-c^4-a^2b^2+c^2a^2+c^4-a^4-b^2c^2+a^2b^2+a^4-b^4-c^2a^2+b^2c^2\\right]\\\\=0\\\\\\;\\lbrack\\;Formula\\;used:\\;\\;\\mathrm{co}t\\;A=\\frac{R\\left(b^2+c^2-a^2\\right)}{abc},\\;cot\\;B=\\frac{R\\left(c^2+a^2-b^2\\right)}{abc},\\;cot\\;C=\\frac{R\\left(a^2+b^2-c^2\\right)}{abc}\\;\\;\\;\\rbrack\\end{array}{/tex} | |
| 6646. |
Find the value of sin 75 |
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Answer» *3+1/2*2 let * is root under Sin (45+30)=sin45cos30+cos45sin30=(1/*2)×(*3/2)+(1/*2)×(1/2)=(3/*2)+(1/*2)=(4/*2)=2*2Let * be under root sin 75 = sin(45+30) =sin45cos30 +cos45sin30 Putting the values we will get the value of sin75 |
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| 6647. |
sin thita + cos thita = √2 find the value of sin |
| Answer» {tex}\\begin{array}{l}\\sin\\theta+\\cos\\theta=\\sqrt2\\\\\\Rightarrow\\frac1{\\sqrt2}\\sin\\theta+\\frac1{\\sqrt2}\\cos\\theta=1\\\\\\Rightarrow\\cos\\left(\\theta-\\frac\\pi4\\right)=\\cos\\;0\\\\\\Rightarrow\\theta-\\frac\\pi4=2n\\pi\\;\\;\\;\\;\\;\\lbrack n\\in set\\;of\\;integers\\;\\rbrack\\\\\\Rightarrow\\theta=2n\\pi\\;+\\frac\\pi4\\end{array}{/tex}{tex}\\sin\\theta=\\sin\\;\\left(2n\\pi\\;+\\frac\\pi4\\right)\\;\\;\\;=\\sin\\frac\\pi4=\\frac1{\\sqrt2}{/tex} | |
| 6648. |
1-2=¿ |
| Answer» -1 | |
| 6649. |
Tan 15 ke value |
| Answer» ({tex}\\sqrt{3}{/tex}-1)/({tex}\\sqrt{3}{/tex}+1) | |
| 6650. |
value of sin18 with prove |
| Answer» | |