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| 1. |
sin thita + cos thita = √2 find the value of sin |
| Answer» {tex}\\begin{array}{l}\\sin\\theta+\\cos\\theta=\\sqrt2\\\\\\Rightarrow\\frac1{\\sqrt2}\\sin\\theta+\\frac1{\\sqrt2}\\cos\\theta=1\\\\\\Rightarrow\\cos\\left(\\theta-\\frac\\pi4\\right)=\\cos\\;0\\\\\\Rightarrow\\theta-\\frac\\pi4=2n\\pi\\;\\;\\;\\;\\;\\lbrack n\\in set\\;of\\;integers\\;\\rbrack\\\\\\Rightarrow\\theta=2n\\pi\\;+\\frac\\pi4\\end{array}{/tex}{tex}\\sin\\theta=\\sin\\;\\left(2n\\pi\\;+\\frac\\pi4\\right)\\;\\;\\;=\\sin\\frac\\pi4=\\frac1{\\sqrt2}{/tex} | |