Arg(z-1)=arg(z+3i) then find x-1:y

1.	Arg(z-1)=arg(z+3i) then find x-1:y
Answer» Let z=x+iy X+iy-1=x+iy+3i and (y=imaginary number along with iota and x=constant number I.e 3,4 etc)TanA=y÷x ,tanA=y÷xTanA=y÷x-1 and TanA=y+3÷x(Comparing both sides)Y÷x-1= y+3÷x( cross multiplication after we get )3x-3-y=03(x-1)=yX-1÷y=1÷3(X-1):y=1:3

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