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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6651. |
Calculus |
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| 6652. |
Can you plz understand me suplimentry exercise ch i |
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| 6653. |
Prove that sin^2A+sin^2(60+A)+sin^2(60-A)=3/2 |
| Answer» {tex}\\begin{array}{l}LHS=\\sin^2A+\\sin^2(60^\\circ+A)+\\sin^2(60^\\circ-A)\\\\=\\sin^2A+\\frac12\\left[1-\\cos2(60^\\circ+A)\\right]+\\frac12\\left[1-\\cos2(60^\\circ-A)\\right]\\\\\\;\\;\\;\\;\\;\\;\\;\\;\\lbrack\\sin ce\\;\\;\\sin^2\\theta=\\frac12(1-\\cos2\\theta)\\;\\;\\rbrack\\\\=\\sin^2A+1-\\frac12\\left[\\cos(120^\\circ+2A)+\\cos(120^\\circ-2A)\\right]\\\\=\\sin^2A+1-\\frac12\\times2\\cos\\frac{(120^\\circ+2A)+(120^\\circ-2A)}2.\\cos\\frac{(120^\\circ+2A)-(120^\\circ-2A)}2\\\\\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\sin ce\\;\\;\\cos\\;C\\;+\\;\\cos\\;D=2.\\cos\\frac{C+D}2.\\cos\\frac{C-D}2\\\\=\\sin^2A+1-\\cos120^\\textdegree.\\cos2A\\\\=\\sin^2A+1+\\frac12.\\left(1-2\\sin^2A\\right)\\\\=\\sin^2A+1+\\frac12-\\sin^2A\\\\=\\frac32=RHS\\end{array}{/tex} | |
| 6654. |
what is the max. value of sinx cosx |
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| 6655. |
Solution of tan -pie/18 |
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| 6656. |
Cos20.cos40.cos60.cos80 |
| Answer» It is there in Mathematic | |
| 6657. |
Why cosec is reciprocal of sine |
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| 6658. |
2cos +sin4 |
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| 6659. |
What is a domain and range of functions sin cos tan cot sec cosec |
| Answer» Sin: Domain:- RRange:- [-1,1]Cos:Domain:- RRange:- [-1,1]Tan:Domain:- R-{(2n+1)pie/2}Range:-RCosec:Domain:- R-{n×pie}Range:- R-(-1,1)Sec:Domain:- R-{(2n-1)pie/2}Range:- R-(-1,1)Cot:Domain:- R-{n×pie}Range:- R | |
| 6660. |
Sin c+ sin d = |
| Answer» 2sin c+d/2.cos c-d/2 | |
| 6661. |
Limit x-0 sin³x/x Limit x-0 sinx³/x |
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| 6662. |
Last year questions paper |
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| 6663. |
if f(x) = 9^x upon 9^x+3 then f (x) + f ( 1-x) |
| Answer» 1 | |
| 6664. |
24 +32 |
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| 6665. |
7+77+777+7777+77777+---------+n. Solv3 the series |
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| 6666. |
Values of trigonometric ratios |
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| 6667. |
Complex numbers |
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| 6668. |
Jsksnskx |
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| 6669. |
Find the square root of the complex numbers:- 5 - 12 iota |
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| 6670. |
Sin,255 |
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| 6671. |
4X2 +3X+3= |
| Answer» Not understand questions | |
| 6672. |
{tex}[i^{18}+(1/i)^{25}]^3{/tex} |
| Answer» ={(i^2)^9-[(i)^2]^12.i}^3=[-i-(-1)^12.i]^3=(-i-i)^3=(-2i)^3=-8(i^3)=8i | |
| 6673. |
2nç3:ñç3=12:1 |
| Answer» n=5 so u can solve it now | |
| 6674. |
COSX+COSX=COS2X+COS4X |
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| 6675. |
What is DE- MORGAN\'S LAWS ( Sets) |
| Answer» (A intersection B)\'=A\'UB\' | |
| 6676. |
1212+562 |
| Answer» 1774 | |
| 6677. |
How many no\'s. Greater than 20000 can be formed by using 0,1,2,3,4 with no repetition allowed |
| Answer» 72 | |
| 6678. |
Modulus |
| Answer» √asquare+bsquare | |
| 6679. |
if a(1/b+1/c),b(1/a+1/c),c(1/a+1/b) are in A.p,prove that a,b,c are in a.p |
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| 6680. |
Write down domain & range 1+2/1+3 |
| Answer» Wrong question | |
| 6681. |
3*5/8+6-2=? |
| Answer» 5.8(approx) | |
| 6682. |
In triangle ABC ,if c=3.4cm ,A=25° ,B=85°, find a,b and angle C |
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| 6683. |
Tan15 degree + cos 15 degree=4 |
| Answer» Tan15°+cos15°=2root2-root3+2+root3/2root2+root3 | |
| 6684. |
Cos 1 degree. Cos 2degree.................. Cos 100degree |
| Answer» The answer is zero. Since cos 1. Cos2...... Cos90...... Cos 100. = 0 | |
| 6685. |
tan15 degree + cos 15 degree =4 |
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| 6686. |
If tan A × tan B = root under a-b/a+b then prove that (a-b cos 2A) × (a-b cos 2B)= a×a-b×b |
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| 6687. |
Why rectangle have 360 degree sum of angle |
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| 6688. |
prove that the centre of three circles are collinear |
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| 6689. |
Find the value of tanπ÷8 |
| Answer» Let twice th e angle so 2×tanπ\\8=1so 2t/1-tsquare,=√2-1 | |
| 6690. |
Rhg |
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| 6691. |
2n |
| Answer» If it is question of induction then for n=m 2m <(m+2) for n=m+1, 2 (m+1)=2m+1, <(m+2)+1 <(m+1)+2 which gives 2 (m+1)<(m+1+2) by pmi it is true | |
| 6692. |
By mathematical induction show that n(nsquare +11) is divisble by 6 |
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| 6693. |
434+432 |
| Answer» 866 | |
| 6694. |
a=cos¥+isin¥,find the value of 1+a/1-a |
| Answer» Bxjwjckde | |
| 6695. |
Sin A + cosB _cos C |
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| 6696. |
Value of sin22.5° |
| Answer» According to the rational root theorem, the possible rational roots are ±1, ±2, ±4, and ±8.5)To find the exact value of sin(22.5 degrees), we write this as a half angle.sin(45 / 2) | |
| 6697. |
Limits |
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| 6698. |
Cos4x = cos2x |
| Answer» Cos2(2X )=cos2xPut the formula is cod 2x On LHS side LEt 2x=x | |
| 6699. |
What is value of sine 10° |
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| 6700. |
Complex numbers exercise miscellaneous q.no.17 |
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