651 + Interview Questions in GEOMETRY IN GENERAL AWARENESS Page 11 InterviewSolution

501.	In the above figure, `/_ ABD =20^(@), /_ BDC =110^(@)` and `/_ DCA =30^(@)` . What is the value of `/_ BAC` ?A. `30^(@)`B. `60^(@)`C. `90^(@)`D. `120^(@)`
Answer» Correct Answer - b (i) Sume of the angles in a quadrilateral is `360^(@)`. (ii) Reflex `/_BDC =360^(@) -/_ BDC`. (iii) `/_ BAC= 360^(@) - ( /_ ABD +` Reflex `/_BDC + /_ DCA )`. (iv) Then find the required angle.

Discussion

502.	In the figure below (not to scale), `bar(MR )_\|_ bar(MP), bar(MQ) _\|_ bar(MN)`, and `bar(MS)` is bisector of `/_ RMQ` . If `/_ PMN=50^(@)` , then find the measure of `/_ RMS`. A. `25^(@)`B. `20^(@)`C. `30^(@)`D. `35^(@)`
Answer» Correct Answer - a (i) Find `/_QMP` using `/_ QMP = /_QMN- /_PMN`. (ii) Find `/_ RMQ ` using `/_ RMQ= 90^(@)- /_ QMP`. (iii) Now `/_RMS =(1)/(2) /_ RMQ`

Discussion

503.	The interior angle made by the side in a parallelogram is 90° then the parallelogram is a (1) rhombus (2) rectangle (3) trapezium (4) Kite
Answer» (2) rectangle If one angle of a parallelogram is 90°, then it is a rectangle

503.

The interior angle made by the side in a parallelogram is 90° then the parallelogram is a (1) rhombus (2) rectangle (3) trapezium (4) Kite

Answer»

(2) rectangle

If one angle of a parallelogram is 90°, then it is a rectangle

Discussion

504.	A regular polygon has N sides where `N lt 10`. Each of its interior angles is an integer in degrees. How many such polygons are possible ?A. 7B. 6C. 8D. 5
Answer» Correct Answer - B Sum of the interior angles `=[180(N-2)]^(@)`. Each interior angle`=[(180(N-2))/(N)]`. For this to be an integer, N must divide `180(N-2)` exactly. `N lt 10` `:.`N can be 3 or 4 or 5 or 6 or 8 or 9. `:.` The polygon ahs 6 possibilities. Hence, the correct option is (b).

Discussion

505.	ABC and DEF are triangles. Consider the following : I. `angleA=40^(@), angleB=60^(@), angleC=80^(@),AB=5cm, and BC=6cm` II. `angleD=angleF,angleE=80^(@),DF=6cm, and EF=8cm` Which of the following can be concluded ?A. (I) is not possible.B. (II) is not possible.C. Both (I) and (II) are possible.D. Both (I) and (II) are not possible.
Answer» Correct Answer - D I and II violate the rule that in a triangle the side opposite to greater angle is greater. Hence, the correct option is (d).

Discussion

506.	Construct a circumcircle for the triangle ABC in which AB=3 cm, BC=3.5 cm , and AC=3.5 cm.
Answer» Steps: 1. Construct the triangle ABC with AB=3 cm, BC=3.5 cm, and AC=3.5 cm. 2. Draw the perpendicular bisectors of `bar(AB), bar(BC), and bar(AC)` and mark their point of concurrence as S. 3. With S as the centre and with SA (or) SB (or) SC as radius, draw a circle. This is due the required circumcircle.

Discussion

507.	In the figure below, `2angleP=angleQOR`. OQ and OR are bisectors of `angleQ and angleR` respectively. Find `angleP`. A. `60^(@)`B. `70^(@)`C. `40^(@)`D. `80^(@)`
Answer» Correct Answer - A `2 angleP=angleQOR` In `DeltaPQR, angleP+angleQ+angleR=180^(@)" "`.(1) `implies angleQ+ angleR=180^(@)-angleP` In `DeltaOQR, angleOQR+ angleQOR+ angleORQ=180^(@)`. `implies (angleQ)/(2)+2 angleP+(angleR)/(2)=180^(@)" "` (2). `implies 2angleP+(180^(@)-angleP)/(2)=180^(@)` `angleP=60^(@)` Hence, the correct option is (a).

Discussion

508.	In a triangle PQR, PQ=QR, A and B are the mid-points of `bar(QR)` and `bar(PR)` respectively. A circle passes through P,Q, A and B. Then which of the following is necessarily true?A. `triangle` is equilateralB. `triangle` is right isoscelesC. PQ is a diameterD. Both a) and c)
Answer» Correct Answer - D i) Draw the figure and mark the point on it. ii) Join BQ, now BQ is the median to PR. Since PQ=QR, BQ is also the altitude to PR. iii) PBQ is a right triangle, right angled at B. Thus, PQ is the diameter. iv) Joining PA, we get another right triangle PAQ which is right angled at A. PBQ and PAQ are congruent angles. iv) PR=QR, so `trianglePQR` is an equilateral triangle.

Discussion

509.	The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is (1) 40° (2) 35° (3) 50° (4) 45°
Answer» (2) 35° 3x – 40 + x + 20 + 2x- 10 – 180° ⇒ 6x = 210 ⇒ x = 35°

509.

The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is (1) 40° (2) 35° (3) 50° (4) 45°

Answer»

(2) 35°

3x – 40 + x + 20 + 2x- 10 – 180° ⇒ 6x = 210 ⇒ x = 35°

Discussion

510.	Find the supplement of each of the following angles (i) 58° (ii) 148° (iii) 120°
Answer» (i) The supplement of 58° = 180° – 58° = 122° (ii) The supplement of 148° = 180° – 148° = 32° (iii) The supplement of 120° = 180° – 120° = 60°

510.

Find the supplement of each of the following angles (i) 58° (ii) 148° (iii) 120°

Answer»

(i) The supplement of 58° = 180° – 58° = 122°

(ii) The supplement of 148° = 180° – 148° = 32°

(iii) The supplement of 120° = 180° – 120° = 60°

Discussion

511.	The complement of an angle exceeds the angle by 60°. Then the angle is equal to (1) 25° (2) 30° (3) 15° (4) 35°
Answer» (3) 15° 90 - x - x = 60° 2x = 30° x = 15°

511.

The complement of an angle exceeds the angle by 60°. Then the angle is equal to (1) 25° (2) 30° (3) 15° (4) 35°

Answer»

(3) 15°

90 - x - x = 60°

2x = 30°

x = 15°

Discussion

512.	In the figure above, PQRS is a parallelogram and G is the centroid of the triangle PQR . A is the point of intersection of the diagonals PR and SQ. If AG=3 cm, then find the length of SQ.
Answer» Correct Answer - 18 cm

Discussion

513.	In the above figure, PQR is a straight line and `anglePQS: angleSQR=7:5`. Find `angleSQR`.
Answer» Correct Answer - D Let `anglePQS and angleSQR` be `7x^(@) and 5x^(@)`, respectively. `anglePQS +SQR=180^(@)( :. "PQR is a straight line. ")` `7x^(@)+5x^(@)=180^(@)` `x^(@)=15^(@)`. `angleSQR=5x^(@)=75^(@)` Hence, the correct option is (d)

Discussion

514.	In the given figure (not to scale), O is the center of the circle. If PB=PC, `anglePBO-25^(@)` and `angleBOC-130^(@)`, then find `angleABP+angleDCP`. A. `10^(@)`B. `30^(@)`C. `40^(@)`D. `50^(@)`
Answer» Correct Answer - B I)As `PB=PC, anglePBO=anglePCO`. ii) As `angleBOC=130^(@), angleBAC=angleBDC=65^(@)`

Discussion

515.	In the given figure, P,Q,R and S are concylic points, and O is the mid-point of the diameter QS. If `angleQPR=25^(@)`, then find `angleSQR`. A. `130^(@)`B. `120^(@)`C. `75^(@)`D. `100^(@)`
Answer» Correct Answer - A Given, `angleQPR=25^(@)`. Since, QS is the diameter, `angleQPS=90^(@)`. `rArr angleSPR = 90-25^(@)=65^(@)` `therefore angleSOR=2 xx 65^(@)=130^(@)`.

Discussion

516.	In a polygon, the greatest angle is `110^(@)` and all the angles are distinct in integral measures (in degrees). Find the maximum number of sides it can have.A. 4B. 5C. 6D. 7
Answer» Correct Answer - B i) As the greatest interior angle is `110^(@)`, the least exterior angle is `(180^(@)-110^(@))`. ii) Sum of all the exterior angles `=360^(@)`. iii) All exterior angles are distinct.

Discussion

517.	In the given figure, (not to scale), the points M,R, N,S and Q are concylic. Find `anglePQR+angleOPR + angleNMS + angleOSN`, if O is the center of the circle. A. `90^(@)`B. `180^(@)`C. `270^(@)`D. Data is inadequate.
Answer» Correct Answer - B i)` anglePQR=1/2(anglePOR), angleNMS = 1/2(angleNOS)` ii) If `angleOPR=x`, then `angleROP=180^(@)-2x`.

Discussion

518.	In the given figure (not to scale), AC is the diameter of the circle and `angleADB=20^(@)`, then find `angleBPC`. A. `50^(@)`B. `70^(@)`C. `90^(@)`D. `110^(@)`
Answer» Correct Answer - D i) Join DC and use properties of cyclic quadrilateral. ii) Use `angleADC=90^(@)` and find `angleBDC`. iii) BDCP is cyclic.

Discussion

519.	In the given figure (not to scale), O is the center of the circle `C_(1)` and AB is the diameter of the circle `C_(2)`. Quadrilateral PQRS is inscribed in the circle with center O. Find `angleQRS`. A. `105^(@)`B. `115^(@)`C. `135^(@)`D. `145^(@)`
Answer» Correct Answer - C i) As AB is the diameter, `angleAOB=90^(@)`. ii) `angleQPS=1/2(angleQOS)`. iii) PQRS is a cyclic quadrilateral.

Discussion

520.	If two sides of a triangles are 7 cm and 10 cm, then the largest possible integer value of the third side is _________.
Answer» Correct Answer - 16 cm `10-7 lt x lt 10 +7`

Discussion

521.	The sides of a triangle are 2006 cm, 6002 cm and m cm, where m is a positive integer. Find the number of such possible triangles.A. 1B. 2006C. 3996D. 4011
Answer» Correct Answer - D From the inequality of triangles, we have: `6002+2006 gt m` and `6002-2006 lt m` `rArr 3996 lt m lt 8008` Since m is an integer, it can take `(8008-3996-1)` or 4011 values.

Discussion

522.	Name the vertices and the line segments in Fig. 2.27. Fig.2.27
Answer» Vertices-A,B,C,D and E; line segment AB,AC,AD,AE,BE,CD,DE

Discussion

523.	Name the points and then the line segments in each of the following figures (Fig. 2.33): Fig.2.33
Answer» The correct answer is A,B,C,D,E,F,AB,CD,EF.

Discussion

524.	Name the points and then the line segments in each of the following figures (Fig. 2.32). Fig.2.32
Answer» The correct answer is A,B,C,D,E,AB,BC,CD,DE,EA.

Discussion

525.	In Fig., BCDE is a square and a 3D shape has been formed by joining the point A in space with the vertices B, C, D and E. Name the 3D shape and also its (i) vertices, (ii) edges and (iii) faces.
Answer» The 3D shape formed is a square pyramid. (i) Vertices are A, B, C, D and E. (ii) Edges are AB, AC, AD, AE, BC, CD, DE and EB. (iii) Faces are: square BCDE and triangles ABC, ACD, ADE and ABE.

525.

In Fig., BCDE is a square and a 3D shape has been formed by joining the point A in space with the vertices B, C, D and E. Name the 3D shape and also its (i) vertices, (ii) edges and (iii) faces.

Answer»

The 3D shape formed is a square pyramid.

(i) Vertices are A, B, C, D and E.

(ii) Edges are AB, AC, AD, AE, BC, CD, DE and EB.

(iii) Faces are: square BCDE and triangles ABC, ACD, ADE and ABE.

Discussion

526.	In Fig. 2.4, BCDE is a square and a 3D shape has been formed by joining the point A in space with the vertices B, C, D and E. Name the 3D shape and also its (i) vertices, (ii) edges and (iii) faces.
Answer» The 3D shape formed is a square pyramid. (i) Vertices are A, B, C, D and E. (ii) Edges are AB, AC, AD, AE, BC, CD, DE and EB. (iii) Faces are: square BCDE and triangles ABC, ACD, ADE and ABE.

Discussion

527.	Write the measure of smaller angle formed by the hour and the minute hands of a clock at 7 O’ clock. Also, write the measure of the other angle and also state what types of angles these are.
Answer» Measure of the required angle = 30° + 30° + 30° + 30° + 30° = 150° Measure of the other angle = 360° – 150° = 210° Angle of measure 150° is an obtuse angle and that of 210° is a reflex angle.

527.

Write the measure of smaller angle formed by the hour and the minute hands of a clock at 7 O’ clock. Also, write the measure of the other angle and also state what types of angles these are.

Answer»

Measure of the required angle = 30° + 30° + 30° + 30° + 30° = 150°

Measure of the other angle = 360° – 150° = 210°

Angle of measure 150° is an obtuse angle and that of 210° is a reflex angle.

Discussion

528.	Write the measure of smaller angle formed by the hour and the minute hands of a clock at 7 O’ clock. Also, write the measure of the other angle and also state what types of angles these are.
Answer» Measure of the required angle = 30° + 30° + 30° + 30° + 30° = 150° Measure of the other angle = 360° – 150° = 210° Angle of measure 150° is an obtuse angle and that of 210° is a reflex angle.

528.

Write the measure of smaller angle formed by the hour and the minute hands of a clock at 7 O’ clock. Also, write the measure of the other angle and also state what types of angles these are.

Answer»

Measure of the required angle = 30° + 30° + 30° + 30° + 30° = 150°

Measure of the other angle = 360° – 150° = 210°

Angle of measure 150° is an obtuse angle and that of 210° is a reflex angle.

Discussion

529.	In the figure above ( not to scale ), ABCD is a rectangle, E is the mid - point of CD. If CD=24 cm and AD=5 cm, then find the perimeter of `DeltaABE`.
Answer» Correct Answer - 50 cm

Discussion

530.	If all the sides of a polygon ABCDE are equal, then `/_A = /_C.` ( Yes `//` No `//` May or May not be )
Answer» Correct Answer - May or May not be

Discussion

531.	In the figure below, `m\|\|l\|\|n` and `bar(PT)\|\|bar(QR)`. If `/_ TUV =x,/_QRS =gamma` and `/_ QVW =z`, then which of the following is necessarily true ? A. `xgt gamma =z`B. `x lt gamma =z`C. `x= gamma =z`D. Cannot be determined
Answer» Correct Answer - c (i) Extend RQ to cut UV on line m . (ii) Extends TP to meed 1 at a point say G. (iii) `/_ TGV =x, /_ TGV = /_ QVW ` and `z = /_ VRS` ( as they are correspongind angles )

Discussion

532.	In the figure below ( not to scale) `bar(CD)\|\|bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is
Answer» Correct Answer - `1:2`

Discussion

533.	In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@) = 2 gamma^(@)`, then `( x^(@)+z^(@)) : gamma^(@)` is
Answer» Correct Answer - `7:2`

Discussion

534.	Which of the following is/ are true ? (a) All triangles are similar. (b) All circles are similar. (c) All squares are similar.
Answer» Correct Answer - 2 and 3 N/A

Discussion

535.	In the following figure, `angle ABC= 90^@, BC =10cm, CD =6cm` , then AD=______________.
Answer» Correct Answer - `(32)/(3) cm` N/A

Discussion

536.	Two equal chords of a circle are always paralllel. (True/False).
Answer» Correct Answer - False N/A

Discussion

537.	In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?
Answer» Correct Answer - CD

Discussion

538.	In a circle, chord PQ subteds an angle of `80^@` at the centre and chord RS subteds `100^@` , then which chord is longer ?
Answer» Correct Answer - RS N/A

Discussion

539.	The distances of two chords AB and CD from the centre of a circle are 6 cm and 8 cm respectively. Then, which chord is longer?
Answer» Correct Answer - AB

Discussion

540.	The point which is equidistant from all the points on the circumference of a circle is called _______
Answer» Correct Answer - centre of the circle

Discussion

541.	The number of lines of symmetry in a protractor is (A) 0 (B) 1 (C) 2 (D) more than 2
Answer» The correct answer is (B) 1

Discussion

542.	Fill in the blank.(A) A protractor has __________ line/lines of symmetry(B) A 30o - 60o - 90o set-square has ________ line/lines of symmetry(C) A 45o - 45o - 90o set-square has _______ line/lines of symmetry.
Answer» (A) A protractor has one line/lines of symmetry (B) A 30o - 60o - 90o set-square has no line/lines of symmetry (C) A 45o - 45o - 90o set-square has one line/lines of symmetry.

542.

Fill in the blank.(A) A protractor has ____ line/lines of symmetry(B) A 30o - 60o - 90o set-square has line/lines of symmetry(C) A 45o - 45o - 90o set-square has _ line/lines of symmetry.

Answer»

(A) A protractor has one line/lines of symmetry

(B) A 30o - 60o - 90o set-square has no line/lines of symmetry

(C) A 45o - 45o - 90o set-square has one line/lines of symmetry.

Discussion

543.	Fill in the blank,The number of lines of symmetry in Fig. 9.11 is__________.
Answer» The number of lines of symmetry in Fig. 9.11 is 5

Discussion

544.	In the figure above, PQRS is a square , `anglePTR=110^(@)`, then find `angleTPS`.
Answer» Correct Answer - `20^(@)`

Discussion

545.	In the figure above, ABCD is a square and PQCD is a rectangle. Find `anglePRC`.
Answer» Correct Answer - `135^(@)`

Discussion

546.	In the figure above ( not to scale ), `DeltaACB~=DeltaACH~=DeltaBCH`. Find `angleBCH`.
Answer» Correct Answer - `120^(@)`

Discussion

547.	In the figure above, if l//m, then what type of a triangle is ABC ?
Answer» Correct Answer - isosceles triangle

Discussion

548.	In a `DeltaABC, angleB=90^(@) and AC=8sqrt(2)`. If AB=BC, then find AB.
Answer» Correct Answer - 8 cm

Discussion

549.	In the figure above, BC=AC, CD=CE. If `angleABC=50^(@)`, then find `angleCED`.
Answer» Correct Answer - `40^(@)`

Discussion

550.	Draw a circle of radius 6cm using ruler and compasses. Draw one of its diameters. Draw the perpendicular bisector of this diameter. Does this perpendicular bisector contain another diameter of the circle?
Answer» Does this perpendicular bisector contain another diameter of the circle - Yes

Discussion

Explore topic-wise InterviewSolutions in .

In the above figure, `/_ ABD =20^(@), /_ BDC =110^(@)` and `/_ DCA =30^(@)` . What is the value of `/_ BAC` ?A. `30^(@)`B. `60^(@)`C. `90^(@)`D. `120^(@)`

In the figure below (not to scale), `bar(MR )_|_ bar(MP), bar(MQ) _|_ bar(MN)`, and `bar(MS)` is bisector of `/_ RMQ` . If `/_ PMN=50^(@)` , then find the measure of `/_ RMS`. A. `25^(@)`B. `20^(@)`C. `30^(@)`D. `35^(@)`

The interior angle made by the side in a parallelogram is 90° then the parallelogram is a (1) rhombus (2) rectangle (3) trapezium (4) Kite

A regular polygon has N sides where `N lt 10`. Each of its interior angles is an integer in degrees. How many such polygons are possible ?A. 7B. 6C. 8D. 5

Construct a circumcircle for the triangle ABC in which AB=3 cm, BC=3.5 cm , and AC=3.5 cm.

In the figure below, `2angleP=angleQOR`. OQ and OR are bisectors of `angleQ and angleR` respectively. Find `angleP`. A. `60^(@)`B. `70^(@)`C. `40^(@)`D. `80^(@)`

In a triangle PQR, PQ=QR, A and B are the mid-points of `bar(QR)` and `bar(PR)` respectively. A circle passes through P,Q, A and B. Then which of the following is necessarily true?A. `triangle` is equilateralB. `triangle` is right isoscelesC. PQ is a diameterD. Both a) and c)

The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is (1) 40° (2) 35° (3) 50° (4) 45°

Find the supplement of each of the following angles (i) 58° (ii) 148° (iii) 120°

The complement of an angle exceeds the angle by 60°. Then the angle is equal to (1) 25° (2) 30° (3) 15° (4) 35°

In the figure above, PQRS is a parallelogram and G is the centroid of the triangle PQR . A is the point of intersection of the diagonals PR and SQ. If AG=3 cm, then find the length of SQ.

In the above figure, PQR is a straight line and `anglePQS: angleSQR=7:5`. Find `angleSQR`.

In the given figure (not to scale), O is the center of the circle. If PB=PC, `anglePBO-25^(@)` and `angleBOC-130^(@)`, then find `angleABP+angleDCP`. A. `10^(@)`B. `30^(@)`C. `40^(@)`D. `50^(@)`

In the given figure, P,Q,R and S are concylic points, and O is the mid-point of the diameter QS. If `angleQPR=25^(@)`, then find `angleSQR`. A. `130^(@)`B. `120^(@)`C. `75^(@)`D. `100^(@)`

In a polygon, the greatest angle is `110^(@)` and all the angles are distinct in integral measures (in degrees). Find the maximum number of sides it can have.A. 4B. 5C. 6D. 7

In the given figure, (not to scale), the points M,R, N,S and Q are concylic. Find `anglePQR+angleOPR + angleNMS + angleOSN`, if O is the center of the circle. A. `90^(@)`B. `180^(@)`C. `270^(@)`D. Data is inadequate.

In the given figure (not to scale), AC is the diameter of the circle and `angleADB=20^(@)`, then find `angleBPC`. A. `50^(@)`B. `70^(@)`C. `90^(@)`D. `110^(@)`

In the given figure (not to scale), O is the center of the circle `C_(1)` and AB is the diameter of the circle `C_(2)`. Quadrilateral PQRS is inscribed in the circle with center O. Find `angleQRS`. A. `105^(@)`B. `115^(@)`C. `135^(@)`D. `145^(@)`

If two sides of a triangles are 7 cm and 10 cm, then the largest possible integer value of the third side is _________.

The sides of a triangle are 2006 cm, 6002 cm and m cm, where m is a positive integer. Find the number of such possible triangles.A. 1B. 2006C. 3996D. 4011

Name the vertices and the line segments in Fig. 2.27. Fig.2.27

Name the points and then the line segments in each of the following figures (Fig. 2.33): Fig.2.33

Name the points and then the line segments in each of the following figures (Fig. 2.32). Fig.2.32

In Fig., BCDE is a square and a 3D shape has been formed by joining the point A in space with the vertices B, C, D and E. Name the 3D shape and also its (i) vertices, (ii) edges and (iii) faces.

In Fig. 2.4, BCDE is a square and a 3D shape has been formed by joining the point A in space with the vertices B, C, D and E. Name the 3D shape and also its (i) vertices, (ii) edges and (iii) faces.

Write the measure of smaller angle formed by the hour and the minute hands of a clock at 7 O’ clock. Also, write the measure of the other angle and also state what types of angles these are.

Write the measure of smaller angle formed by the hour and the minute hands of a clock at 7 O’ clock. Also, write the measure of the other angle and also state what types of angles these are.

In the figure above ( not to scale ), ABCD is a rectangle, E is the mid - point of CD. If CD=24 cm and AD=5 cm, then find the perimeter of `DeltaABE`.

If all the sides of a polygon ABCDE are equal, then `/_A = /_C.` ( Yes `//` No `//` May or May not be )

In the figure below, `m||l||n` and `bar(PT)||bar(QR)`. If `/_ TUV =x,/_QRS =gamma` and `/_ QVW =z`, then which of the following is necessarily true ? A. `xgt gamma =z`B. `x lt gamma =z`C. `x= gamma =z`D. Cannot be determined

In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@) = 2 gamma^(@)`, then `( x^(@)+z^(@)) : gamma^(@)` is

Which of the following is/ are true ? (a) All triangles are similar. (b) All circles are similar. (c) All squares are similar.

In the following figure, `angle ABC= 90^@, BC =10cm, CD =6cm` , then AD=______________.

Two equal chords of a circle are always paralllel. (True/False).

In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

In a circle, chord PQ subteds an angle of `80^@` at the centre and chord RS subteds `100^@` , then which chord is longer ?

The distances of two chords AB and CD from the centre of a circle are 6 cm and 8 cm respectively. Then, which chord is longer?

The point which is equidistant from all the points on the circumference of a circle is called _______

The number of lines of symmetry in a protractor is (A) 0 (B) 1 (C) 2 (D) more than 2

Fill in the blank.(A) A protractor has __________ line/lines of symmetry(B) A 30o - 60o - 90o set-square has ________ line/lines of symmetry(C) A 45o - 45o - 90o set-square has _______ line/lines of symmetry.

Fill in the blank,The number of lines of symmetry in Fig. 9.11 is__________.

In the figure above, PQRS is a square , `anglePTR=110^(@)`, then find `angleTPS`.

In the figure above, ABCD is a square and PQCD is a rectangle. Find `anglePRC`.

In the figure above ( not to scale ), `DeltaACB~=DeltaACH~=DeltaBCH`. Find `angleBCH`.

In the figure above, if l//m, then what type of a triangle is ABC ?

In a `DeltaABC, angleB=90^(@) and AC=8sqrt(2)`. If AB=BC, then find AB.

In the figure above, BC=AC, CD=CE. If `angleABC=50^(@)`, then find `angleCED`.

Draw a circle of radius 6cm using ruler and compasses. Draw one of its diameters. Draw the perpendicular bisector of this diameter. Does this perpendicular bisector contain another diameter of the circle?

Fill in the blank.(A) A protractor has ____ line/lines of symmetry(B) A 30o - 60o - 90o set-square has line/lines of symmetry(C) A 45o - 45o - 90o set-square has _ line/lines of symmetry.