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601.

Two parallel lines meet each other at some point.

Answer»

The correct answer is False.

602.

Fill in the blanks to make the statements true:In Fig., points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then(a) AD = AB + ______(b) AD = AC + ______(c) mid point of AE is ______(d) mid point of CE is ______(e) AE = ______ × AB.

Answer»

(a) AD = AB + BD

Where, BD = BC + CD

(b) AD = AC + CD

(c) mid point of AE is c

(d) mid point of CE is D

(e) AE = 4 × AB. [given]

603.

Fill in the blank,In Fig. 9.1, the line segments PQ and RQ have been marked on a line l such that PQ = AB and RQ = CD. Then AB – CD =__________.

Answer»

Then AB – CD = PR

604.

In the following figure, PQ is parallel to BC and `PQ:BC =1 :3`. If the area of the triangle ABC is `144 cm^2`, then what is the area of the triangle APQ? A. `48 cm ^2`B. `36cm ^2`C. `16 cm ^2`D. `9cm^2`

Answer» Correct Answer - C
The ratio of areas of two similar triangles equal to the ratio of the squares of their corresponding sides.
605.

A cyclic polygon has n sides such that each of its interior angle measures `144^(@)`. What is the measures of the angle subtended by each of its side at the geometrical center of the polygon.A. `144^(@)`B. `30^(@)`C. `36^(@)`D. `54^(@)`

Answer» Correct Answer - C
Find the number of sides of the polygon, anlge subtended at the center `=360^(@)/n`.
606.

In `DeltaPQR and Delta ABC`, `angleQ=angleB=90^(@),PQ=AB, and QR=BC`. Which of the following property can be used to prove the congruence of `DeltaPQR` and `DeltaABC` ?A. SSSB. RHSC. ASAD. SAS

Answer» Correct Answer - D
Given `PQ=AB, QR=BC, angle Q=angleB=90^(@)`.
Basically by using SAS congruence property. ` DeltaPQR~=ABC`.
Hence, the correct option is (d).
607.

In two triangles ABC an DEF,`angle A=angleD`. The sum of the angles A and B is equal to the sum of the angles D and E. If `BC=6` cm and `EF=8cm`, find the ratio of the areas of the triangles, ABC and DEF.A. `3:4 `B. `4:3`C. `9:16`D. `16:9`

Answer» Correct Answer - C
The ratio of areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.
608.

A man travels on a bicycle, 10 km east from the starting point A to reach point B, then the cycles 15 km south to reach point C. Find the shortest distance between A and C.A. 25 kmB. 5kmC. `25sqrt(13) km`D. `5sqrt(13) km`

Answer» Correct Answer - D
Apply Pythagoras theorem.
609.

In the following figure, PQ is parallel to BC and `PQ:BC =1 :3`. If the area of the triangle ABC is `144 cm^2`, then what is the area of the triangle APQ? A. `48 cm ^2`B. `36cm ^2`C. `16 cm ^2`D. `9cm^2`

Answer» Correct Answer - C
The ratio of areas of two similar triangles equal to the ratio of the squares of their corresponding sides.
610.

In triangle ABC , sides AB and AC are extended to D and E, respectively, such that `AB=BD` and AC =CE`, Find DE, if `BC=6 cm`.A. 3 cmB. 6cmC. 9 cmD. 12 cm

Answer» Correct Answer - C
Apply basic proportionality theorem.
611.

Using the information given, name the right angles in each part of Fig.is RS⊥RW?

Answer»

The correct answer is ∠RTW and ∠RTS

612.

Using the information given, name the right angles in each part of Fig.AC⊥ CD?

Answer»

The correct answer is ∠ACD.

613.

Using the information given, name the right angles in each part of Fig.AE⊥ CE?

Answer»

The correct answer is ∠AEC.

614.

In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is(A) 1 (B) 2 (C) 3 (D) 4

Answer»

(C) 3

We have, ∠BAC = 90° and AD ⊥ BC

∵ ∠BDA = ∠CDA = ∠BAC = 90°

∴ There are 3 right triangles formed in the given figure.

615.

A polygon has prime number of sides. Its number of sides is equal to the sum of the two least consecutive primes. The number of diagonals of the polygon is(A) 4 (B) 5 (C) 7 (D) 10

Answer»

(B) 5

The two least consecutive prime numbers are, 2 and 3

Sum of two numbers = 2 + 3 = 5

By using formula = n(n – 3)/2

= 5(5 – 3)/2

= (5 × 2)/2

= 10/2

= 5

616.

Using the information given, name the right angles in each part of Fig.AC⊥ BD?

Answer» The correct answer is ∠AED,∠AEB,∠BEC and ∠DEC.
617.

Using the information given, name the right angles in each part of Fig.is AC⊥ BD?

Answer»

The correct answer is ∠ACD and ∠ACB

618.

In Fig., AB = BC and AD = BD = DC. The number of isosceles triangles in the figure is(A) 1 (B) 2 (C) 3 (D) 4

Answer»

(C) 3

∵ We have, AB = BC and AD = BD = DC.

∴ ∆ ABD, ∆ BDC and ∆ ABC all are isosceles triangles.

∴ There are 3 isosceles triangles formed in the given figure.

619.

In Fig, if AC ⊥ BD , then name all the right angles.

Answer»

There are four right angles. 

They are: ∠APD , ∠APB, ∠BPC and ∠CPD.

620.

Find out the incorrect statement, if any, in the following: An angle is formed when we have (a) two rays with a common end-point (b) two line segments with a common end-point (c) a ray and a line segment with a common end-point

Answer»

The correct answer is (b) and (c)

621.

In Fig, PQ ⊥ AB and PO = OQ. Is PQ the perpendicular bisector of line segment AB? Why or why not?

Answer»

PQ is not the perpendicular bisector of line segment AB, because AO ≠ BO. [Note: AB is the perpendicular bisector of line segment PQ].

622.

In Fig. 2.1, PQ ⊥ AB and PO = OQ. Is PQ the perpendicular bisector of line segment AB? Why or why not?

Answer»

PQ is not the perpendicular bisector of line segment AB, because AO ≠ BO. [Note: AB is the perpendicular bisector of line segment PQ].

PQ is not the perpendicular
bisector of line segment AB,
because AO ≠ BO. [Note: AB is the
perpendicular bisector of line
segment PQ].
623.

If line PQ || line m, then line segment PQ || m

Answer»

The correct answer is True.

624.

The number of independent measurement required to construct an isosceles trapezium is three.

Answer» Correct Answer - True
625.

Number of independent measurement required to construct a triangle is ______

Answer» Correct Answer - 3
626.

Construct a parallelogram PQRS, when `PQ=3.7 cm, QR=2.3cm, and PR=4.8cm`.

Answer» Steps:
1. Draw a line segment PQ=3.7 cm.
2. Draw an arc with P as the centre and a radius of 4.8 cm.
3. With Q as the centre and a radius of 2.3 cm, draw another arc to intersect the previous are of step 2 at R and join QR.
4. With R as the centre , draw an arc of radius 3.7 cm.
5. With P as the centre, draw another arc of radius 2.3 cm to intersect the arc in step 4 at S. Join RS and PS.
PQRS is the required parallelogram.
627.

In Fig. 2.39, (a) What is AE + EC? (b) What is AC – EC? (c) What is BD – BE? (d) What is BD – DE?

Answer»

(a) AC (b) AE (c) ED (d) BE

628.

In the adjoining figure, O is the centre of the circle. AB is an arc of the circle and `/_AOB=80^(@)`. Find `/_ACB`.

Answer» The angle made by an arc at the centre of a circle is twice the angle made by the arc point on the remaining part of the circle.
`/_AOB=2 /_ACB`
`implies 2 /_ACB=80^(@)`
`implies /_ACB =40^(@)`
629.

The number of independent measurement required to construct a circle is two.

Answer» Correct Answer - False
630.

Centroid of a triangle divides its median in the ratio of 1:2 from the vertex.

Answer» Correct Answer - False
631.

Find out the incorrect statement, if any, in the following: An angle is formed when we have (a) two rays with a common end-point (b) two line segments with a common end-point (c) a ray and a line segment with a common end-point

Answer»

All the three statements (a), (b) and (c) are incorrect.

∵ The common initial point of two rays forms an angle.

632.

The point of concurrence of altitudes of a triangle is called orthocentre.

Answer» Correct Answer - True
633.

In which of the following figures,(a) perpendicular bisector is shown?(b) bisector is shown?(c) only bisector is shown?(d) only perpendicular is shown?

Answer»

(a) Figure (ii) shows the perpendicular bisector

(b) Figure (ii) and (iii) shows the bisector.

(c) Figure (iii) shows only the bisector.

(d) Figure (i) shows only the perpendicular.

634.

The point of concurrence of medians of a triangle is called centroid.

Answer» Correct Answer - True
635.

The image of a point lying on a line l with respect to the line of symmetry l lies on _______.

Answer»

The image of a point lying on a line l with respect to the line of symmetry l lies on ɭ

636.

Given below are some figures. Choose the image of the given figure with respect to the given line from the given choices. A. B. C. D.

Answer» Correct Answer - a
637.

What is common in the following figures (i) and (ii)?Is figure (i) that of triangle ? if not, why?

Answer»

Both the figures (i) and (ii) have 3 line segments.
No, Fig. (i) is not a triangle since the three line segments does not form a closed figure.

638.

If two rays intersect, will their point of intersection be the vertex of an angle of which the rays are the two sides?

Answer»

Yes

If two rays intersect, will their point of intersection be the vertex of an angle of which the rays are the two sides.

639.

In given figure,(a) is AC + CB = AB ?(b) is AB + AC= CB ?(c) is AB + BC = CA ?

Answer»

(a) Yes, AC + CB = AB

(b) No, AB – AC = CB

(c) No, AB – BC = CA

640.

In Fig. 2.38, (a) is AC + CB = AB? (b) is AB + AC = CB? (c) is AB + BC = CA?

Answer»

(a) Yes  (b) No (c) No

.

641.

In given figure,(a) name any four angles that appear to be acute angles.(b) name any two angles that appear to be obtuse angles.

Answer»

(a) Acute angles : ∠ADE, ∠AEB, ∠ABE and ∠ECD.

(b) Obtuse angles : ∠BCD and ∠BAD.

642.

In the following, CDEF is a cyclic quadrilateral. `bar(CG)` and `bar(DH)` are the angle bisectors of `angleC` and `angleD` respectively. If `angleE=100^(@)` and `angleF=110^(@)`, then find `angleCPD`.

Answer» In a cyclic quadrilateral, opposite angles are supplementary.
643.

The angle subtended by a minor arc in its alternate segment is…………….A. acuteB. obtuseC. `90^(@)`D. reflex angle.

Answer» Correct Answer - A
Angle subtended by a minor arc is always less than `90^(@)`.
644.

A tower of height 60 m casts a 40 m long shadow on the ground. At the same time, a needle of height 12 m casts a `x` cm long shadow the ground. Find `x`A. 6B. 8C. 10D. 14

Answer» Correct Answer - B
Join,BD, ABDE is a cyclic quadrilateral.
645.

A pole of height 14 m casts a 10 m long shadow on the ground. At the same time, a tower casts a 70 m long shadow on the ground. Find the height of the tower.A. 50 mB. 78 mC. 90 mD. 98 m

Answer» Correct Answer - D
Use the concept of similar triangles.
646.

Find the distance between the helicopter and the ship.

Answer»

From the figure AS is the distance between the helicopter and the ship.

∆ APS is a right angled triangle, by Pythagoras theorem,

AS2 = AP2 + PS2

= 802 + 1502

= 6400 + 22500 = 28900 = 1702

∴ The distance between the helicopter and the ship is 170 m

647.

How many edges, faces and vertices are there in a sphere?

Answer»

No edges, No faces and No vertices.

648.

ABCD is a rhombus, in which the length of the diagonals AC and BD are 6 cm and 8cm, respectively. Find the perimeter of the rhombus ABCD.

Answer» Correct Answer - 20 cm
649.

In a parallelogram PQRS, the bisectors of `/_P` and `/_Q` meet on RS.If the perimeter PQRS is 13.5 cm, then find the measure of QRA. 4.5 cmB. 2.25 cmC. 3 cmD. 3.75cm

Answer» Correct Answer - b
650.

If the three angles of a triangle are in the ratio 3 : 5 : 4, then find them.

Answer»

Given three angles of the triangles are in the ratio 3 : 5 : 4. 

Let the three angle be 3x, 5x and 4x. 

By angle sum property of a triangle, we have 

3x + 5x + 4x = 180° 

12x = 180° 

x = \(\frac{180°}{12}\)

x = 15° 

∴ The angle are 3x = 3 x 15° 

= 45° 

5x = 5 x 15° 

= 75°

4x = 4 x 15° 

= 60° 

Three angles of the triangle are 45°, 75°, 60°