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In the adjoining figure, O is the centre of the circle. AB is an arc of the circle and `/_AOB=80^(@)`. Find `/_ACB`. |
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Answer» The angle made by an arc at the centre of a circle is twice the angle made by the arc point on the remaining part of the circle. `/_AOB=2 /_ACB` `implies 2 /_ACB=80^(@)` `implies /_ACB =40^(@)` |
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