1.

In the adjoining figure, O is the centre of the circle. AB is an arc of the circle and `/_AOB=80^(@)`. Find `/_ACB`.

Answer» The angle made by an arc at the centre of a circle is twice the angle made by the arc point on the remaining part of the circle.
`/_AOB=2 /_ACB`
`implies 2 /_ACB=80^(@)`
`implies /_ACB =40^(@)`


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