In the given figure (not to scale), AC is the diameter of the circle a – InterviewSolution

1.	In the given figure (not to scale), AC is the diameter of the circle and `angleADB=20^(@)`, then find `angleBPC`. A. `50^(@)`B. `70^(@)`C. `90^(@)`D. `110^(@)`
Answer» Correct Answer - D i) Join DC and use properties of cyclic quadrilateral. ii) Use `angleADC=90^(@)` and find `angleBDC`. iii) BDCP is cyclic.

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