In the given figure (not to scale), O is the center of the circle. If – InterviewSolution

1.	In the given figure (not to scale), O is the center of the circle. If PB=PC, `anglePBO-25^(@)` and `angleBOC-130^(@)`, then find `angleABP+angleDCP`. A. `10^(@)`B. `30^(@)`C. `40^(@)`D. `50^(@)`
Answer» Correct Answer - B I)As `PB=PC, anglePBO=anglePCO`. ii) As `angleBOC=130^(@), angleBAC=angleBDC=65^(@)`

Discussion

No Comment Found

Related InterviewSolutions

PQR and XYZ are triangles. The perimeter of each triangle is 12 cm. PQR is an equilateral XY=4 cm and YZ=ZX. Both the triangles are __________A. congruentB. similar but not congruentC. similarD. Both (a) and (c )
Distance between two circles with R and r is d units. If `d^2=R^2+r^2` , then the two circles __________(intersect at one point/ do not intersect /intersect at two distinct points).
If two circles touch each otner externally, then the number of transverse common tangents is __________.
If two circles intersect at two distinct points , then the number of common tangents is __________.
There are no congruent figures which are similar. (True/False).
Identify the pairs of shapes which are similar and congruent.
Check whether given sides are the sides of right – angled triangles, using Pythagoras theorem,8, 15, 1712, 13, 1530, 40, 509, 40, 4124, 45, 51
In the figure, DA = DC and BA = BC. Are the triangles DBA and DBC congruent? Why?
State Pythagoras theorem.
The area of the trapezium is ……..