Explore topic-wise InterviewSolutions in .

Correct option is B) radio

• Suresh: Hi Ramesh Where are you going?
• Ramesh: I am going to my office.
• Suresh: Could you do me a favour? On your way could you please drop me to my college?
• Ramesh: So sorry Suresh, won’t be able to, It is getting late for me to go to the office. Don’t think otherwise.
• Suresh: It is OK. No problem. I will take an auto.

• Suma: Hi, Shobha, are you drawing?
• Shobha: Oh Suma, please come in. I was writing an article.
• Suma: Shobba, you asked me to drop you to the market yesterday. But I couldn’t, as was in a hurry to go to the hospital I am really sorry.
• Shobha: It’s okay. Don’t feel bad about it.
• Suma: You were busy. Hope I have not disturbed you.
• Shobha: Not at all, would you like to have some coffee? 
• Suma: No, thanks. I had it just a while ago.

Correct option is A) Do, please

Correct option is A) than

• Ashok: Excuse me, would you please close the window?
• Co-passenger: Pardon me. I was reading the book. Did you say something? 
• Ashok: Would you mind closing the window?
• Co-passenger: Sure, sir By the by, where are you from?
• Ashok: I’m from Mysore.
• Co-passenger: Oh’ It is a beautiful city. It is famous for KRS garden, palace, etc.
• Ashok: Yes, sir. Have you been to Mysore?
• Co-passenger: I have visited it many times. It is a lovely city

Correct option is A) Could

Correct option is C) it

Correct option is D) it

Correct option is C) them

Correct option is C) pond

¹⁷C_{2t +1} = ¹⁷C_{3t– 5}

⇒ 2t + 1 = 3t – 5 or (2t + 1) + (3t – 5) = 17

⇒ 1 + 5 – t or 5t = 21

⇒ t = 6 or t = 21/5

which is not an integer

∴ t = 6.

Given equation is f(x) = x³ + 3x² – 7x + 6 = 0

Required equation is f(√x) = 0

⇒ x√x + 3x – 7√x + 6 = 0

⇒ √x(x – 7) = – (3x + 6)

Squaring on both sides,

⇒ x(x – 7)² = (3x + 6)²

⇒ x(x² – 14x + 49) = 9x² + 36 +36x

⇒ x³ – 14x² + 49x – 9x² – 36x – 36 = 0

i.e. x³ – 23x² + 13x – 36 = 0

−p + 2q + 3r)²  

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

(−p + 2q + 3r)² = (−p)² + (2q)² + (3r)² + 2(−p)(2q) + 2(2q)(3r) + 2(−p)(3r)

= p² + 4q² + 9r² – 4pq +12qr – 6rp

Let AB be the chord with vertex A( 0,0) Given α = 45°

equation of of AB = ( y - 0) = tan 45( x - 0)

y = x then y = 4a ⇒ x = 4a

∴ B = ( 4a , 4a)
Length of chord AB = 4√2a.

Solution:
No.
Justification:
Consider the positive integer 3q + 1, where q is a natural number.
=> (3q + 1)² = 9q² + 6q + 1
= 3(3q² + 2q) + 1
= 3m + 1, where m is an integer.
Thus (3q + 1)² cannot be expressed in any other form apart from 3m + 1.

Required length = H.C.F. of 495 cm, 900 cm and 1665 cm. 

495 = 3² x 5 x 11, 

900 = 2² x 3² x 5² , 

1665 = 3² x 5 x 3⁷. 

H.C.F. = 32 x 5 = 45. 

Hence, required length = 45 cm.

Given:

Marked price is 40% above cost price.

Successive discount of 20% is given

Selling price of the item is Rs. 4480

Concept:

Successive discount means discount on the discounted price.

Formula:

Mp = (100 + x)% of Cp

Sp = {Mp × (100 – y)%} × (100 – y)%}

Where Mp = marked price

Cp = cost price

x = percentage above cost price Mp is marked

Sp = selling price

y = successive discounts given

Calculation:

Let the Cp of the item be x

Mp = 140% of x = 1.4x

Sp = (1.4x × 80%) × 80%

⇒ Sp = 1.12x × 80%

⇒ Sp = 0.896x

0.896x = 4480

⇒ x = 4480/0.896

⇒ x = 5000

∴ Cost Price is Rs. 5000

Given:

Loss% on the CP (a) = 10%

Less weight (b) = 20%

Formula Used:

Profit%/Loss% = (b ± a)/(100 – b) × 100

Calculations:

As, a = 10% and b = 20%

Then,

⇒ Profit%/Loss% = (b ± a)/(100 – b) × 100

⇒ (20 – 10)/(100 –20) × 100

⇒ 10/80 × 100

⇒ 12.5%

The dealer’s profit% is 12.5%.

Here, we need to note that:

If there is a loss of a% on the CP, then we have the formula:

Dealer's profit% = [(b - a)/(100 – b)] × 100

And if there is a profit of a% on the CP, then we have the formula:

Dealer's Loss% = [(b + a)/(100 – b)] × 100

GIVEN:

Marked price = Rs. 1500

And

Selling price = Rs. 1173

First discount = 15%

CONCEPT:
Basic concept of discount.

FORMULA USED:

Discount = [(MP – SP)/MP] × 100

CALCULATION:

Overall discount

= [(1500 – 1173)/1500] × 100

= 21.8%

Suppose 2^nd discount = x%

So,

15 + x – 15x/100 = 21.8

⇒ 0.85x = 6.8

⇒ x = 8

∴ Second discount = 8%

Given:

A dishonest shopkeeper sells the rice using a weight 20% less than the true weight and makes a profit of 30%.

Formula used:

P = S.P – C.P

P% = (P/C.P) × 100

P → Profit

C.P → Cost price

S.P → Selling price

Calculations:

Let CP of 1000 gm be Rs. 1000

So, cost price of 800 gm = 1000 × (100 – 20)/100 = Rs. 800

Selling price of 1000 gm = 1000 × (100 + 30)/100 = Rs. 1300

The shopkeeper is gaining 1300 – 800 = Rs. 500

Profit% = [500/800] × 100 = 62.5%

Correct answer is (D) All of the above

m=2004!

=1×2×3×4×...........2004×2005⁰×2006⁰×2007⁰×2008⁰×2009⁰

n=2005×2006×2007×2008×2009×1⁰×2⁰×3⁰×4⁰............×2004⁰

LCM=1×2×3×......×2004×2005×....

2009=2009!

HCF=1×1×1....=1

Correct answer is (A) mol.litre^-1 sec^-1 

Correct answer is (B) 3

Correct answer is (C) 16 minutes

Salmonella typhi is causative organism of Enteric fever.

a. Corynebacterium diphtheriae

b. Gall bladder

Food can become contaminated by people who have gastro, if they do not wash their hands properly after going to the toilet and before handling food. Bacteria which can cause gastro are often present on raw foods such as meats, poultry and eggs.

Diphtheria is an example of Toxaemia.

e. Meningitis

a. Bacteraemia in first week

Bacterial gastroenteritis commonly results from the consumption of food or water that has become contaminated with bacteria or their toxins. It can cause a range of symptoms, including diarrhea, abdominal cramping, nausea, and vomiting.

d. All of these

b. Endotoxins 

c. V.cholera Parahaenolyticus