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Find the number of integral ordered pairs `(x,y)` satisfying the equation `log(3x+2y)=logx+logy.` |
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Answer» We have `log(3x+2y)=logx+logyimplies3x+2y=xyimplies3x+2y-xy=0` hence `y(x-2)=3ximpliesy=(3x)/(x-2)(x, y inN)` `therefore"Possible ordered pairs are "(3,9),(4,6),(5,5),(8,4).` and (0,0) and (1,-3) etc. rejected. Ans] |
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