1.

Find the number of integral ordered pairs `(x,y)` satisfying the equation `log(3x+2y)=logx+logy.`

Answer» We have `log(3x+2y)=logx+logyimplies3x+2y=xyimplies3x+2y-xy=0`
hence `y(x-2)=3ximpliesy=(3x)/(x-2)(x, y inN)`
`therefore"Possible ordered pairs are "(3,9),(4,6),(5,5),(8,4).`
and (0,0) and (1,-3) etc. rejected. Ans]


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