1.

If 17C2t + 1 = 17C3t – 5,find t.

Answer»

17C2t +1 = 17C3t– 5

⇒ 2t + 1 = 3t – 5 or (2t + 1) + (3t – 5) = 17

⇒ 1 + 5 – t or 5t = 21

⇒ t = 6 or t = 21/5

which is not an integer

∴ t = 6.



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