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If 17C2t + 1 = 17C3t – 5,find t. |
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Answer» 17C2t +1 = 17C3t– 5 ⇒ 2t + 1 = 3t – 5 or (2t + 1) + (3t – 5) = 17 ⇒ 1 + 5 – t or 5t = 21 ⇒ t = 6 or t = 21/5 which is not an integer ∴ t = 6. |
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