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23951.

Prove that 1/ cosec x + cot x – 1/sin x = 1/sin x –1/ cosec x–cot x

Answer»

In order to show that,

\(\frac1{(coses\,x+cot\,x)}-\frac1{sin\,x}=\frac1{sin\,x}-\frac1{(coses\,x-cot\,x)}\)

it is sufficient to show

\(\frac1{coses\,x+cot\,x}+\frac1{(coses\,x-cot\,x)}=\frac1{sin\,x}+\frac1{sin\,x}\)

\(\Rightarrow\frac1{coses\,x+cot\,x}+\frac1{(coses\,x-cot\,x)}=\frac2{sin\,x}\;\;...(i)\)

Now, LHS of above is

\(\frac1{(coses\,x+cot\,x)}+\frac1{(coses\,x-cot\,x)}\) \(=\frac{(coses\,x-cot\,x)+(coses\,x+cot\,x)}{(coses\,x-cot\,x)(coses\,x+cot\,x)}\)

\(=\frac{2\,coses\,x}{coses^2x-cot^2x}\) [∵ (a+b)(a-b) = a2 - b2)

\(=\frac{2\,coses\,x}1=\frac2{sin\,x}\) = RHS of (i)

Hence, \(\frac1{(coses\,x+cot\,x)}+\frac1{(coses\,x-cot\,x)}=\frac1{sin\,x}+\frac1{sin\,x}\)

or \(\frac1{(coses\,x+cot\,x)}-\frac1{sin\,x}=\frac1{sin\,x}-\frac1{(coses\,x-cot\,x)}.\)

23952.

3. What is the value of the series\[\left(1-\frac{1}{2 !}+\frac{1}{4 !}-\cdots\right)^{2}+\left(1-\frac{1}{3 !}+\frac{1}{5 !}-\cdots\right)^{2} ?\]

Answer» Given expression

= {(e+e^-1)/2}^2+{e-e^-1)/2}^2

=1/4×2(e^2+e^-2)

=1/2(e^2+e^-2)
23953.

Make a research of the story "Makato and the Cowrie Shell" retold and translated by Supannee Khanchanathiti. Write a summary based on how you understand the story

Answer»
A young boy named Makato was an orphan, and didn't have any way to support himself, so he worked hard doing whatever jobs that he could to survive. Makato was a very hard worker, and people noticed that. He would dream of going on an adventure to a bigger place where the land was fertile, and the people were kind, and he was encouraged to do that. One day, when he had prepared enough, he set out. It took him a month to get to the bigger town, and when he arrived he asked a woman for water. He told her that he had come such a long way because he wanted to see the king, who he had heard was kind. He worked with the king's elephants, and he started working for her. After some time working, he did encounter the king, and during the encounter he picked up a cowrie shell that was lying on the road and offered it to the king (Cowrie shells were used for money, but just one was practically worthless). When Makato offered the shell to the King, the King said he could keep it, and so Makato pondered what he could do to honor the king's gift. He saw some lettuce seeds at a stall in the market and thought that he could grow them. He asked the woman about them, and she let him have as many as would stick to his finger in return for his treasured cowrie shell. Furthermore, he grew the lettuces, and next time he saw the king, he gave one to him, telling him he grew them from the shell the king had given him. The king was impressed, gave him a job in the castle, and he eventually grew up and married the daughter of the king
A young boy named Makato was an orphan, and didn't have any way to support himself, so he worked hard doing whatever jobs that he could to survive. Makato was a very hard worker, and people noticed that. He would dream of going on an adventure to a bigger place where the land was fertile, and the people were kind, and he was encouraged to do that. One day, when he had prepared enough, he set out. It took him a month to get to the bigger town, and when he arrived he asked a woman for water. He told her that he had come such a long way because he wanted to see the king, who he had heard was kind. He worked with the king's elephants, and he started working for her. After some time working, he did encounter the king, and during the encounter he picked up a cowrie shell that was lying on the road and offered it to the king (Cowrie shells were used for money, but just one was practically worthless). When Makato offered the shell to the King, the King said he could keep it, and so Makato pondered what he could do to honor the king's gift. He saw some lettuce seeds at a stall in the market and thought that he could grow them. He asked the woman about them, and she let him have as many as would stick to his finger in return for his treasured cowrie shell. Furthermore, he grew the lettuces, and next time he saw the king, he gave one to him, telling him he grew them from the shell the king had given him. The king was impressed, gave him a job in the castle, and he eventually grew up and married the daughter of the king
A young boy named Makato was an orphan, and didn't have any way to support himself, so he worked hard doing whatever jobs that he could to survive. Makato was a very hard worker, and people noticed that. He would dream of going on an adventure to a bigger place where the land was fertile, and the people were kind, and he was encouraged to do that. One day, when he had prepared enough, he set out. It took him a month to get to the bigger town, and when he arrived he asked a woman for water. He told her that he had come such a long way because he wanted to see the king, who he had heard was kind. He worked with the king's elephants, and he started working for her. After some time working, he did encounter the king, and during the encounter he picked up a cowrie shell that was lying on the road and offered it to the king (Cowrie shells were used for money, but just one was practically worthless). When Makato offered the shell to the King, the King said he could keep it, and so Makato pondered what he could do to honor the king's gift. He saw some lettuce seeds at a stall in the market and thought that he could grow them. He asked the woman about them, and she let him have as many as would stick to his finger in return for his treasured cowrie shell. Furthermore, he grew the lettuces, and next time he saw the king, he gave one to him, telling him he grew them from the shell the king had given him. The king was impressed, gave him a job in the castle, and he eventually grew up and married the daughter of the king
A young boy named Makato was an orphan, and didn't have any way to support himself, so he worked hard doing whatever jobs that he could to survive. Makato was a very hard worker, and people noticed that. He would dream of going on an adventure to a bigger place where the land was fertile, and the people were kind, and he was encouraged to do that. One day, when he had prepared enough, he set out. It took him a month to get to the bigger town, and when he arrived he asked a woman for water. He told her that he had come such a long way because he wanted to see the king, who he had heard was kind. He worked with the king's elephants, and he started working for her. After some time working, he did encounter the king, and during the encounter he picked up a cowrie shell that was lying on the road and offered it to the king (Cowrie shells were used for money, but just one was practically worthless). When Makato offered the shell to the King, the King said he could keep it, and so Makato pondered what he could do to honor the king's gift. He saw some lettuce seeds at a stall in the market and thought that he could grow them. He asked the woman about them, and she let him have as many as would stick to his finger in return for his treasured cowrie shell. Furthermore, he grew the lettuces, and next time he saw the king, he gave one to him, telling him he grew them from the shell the king had given him. The king was impressed, gave him a job in the castle, and he eventually grew up and married the daughter of the king
23954.

Roosevelt said, “All we have to fear is fear itself.” Do you agree? Why/why not?

Answer»

The quote, “All we have to fear is fear itself”, by the American President, Franklin D Roosevelt, it is absolutely true. It is only the fear of consequences which prevents us from taking an action and hampers our progress. William Douglas’ fear of drowning makes him develop an aversion to water. Hence, he avoids going near water bodies or indulge in water sports. When he is able to overcome his fear with the help of the instructor, he succeeds. Likewise, there are numerous incidents around us that show how fear cripples the mind of an individual and society, and acts as a barrier to growth.

The other lessons in the textbook also support the view. The bangle makers of Firozabad in ‘Lost Spring’ fear that the police would put them in jail, so they accept their exploitation, and do not organise themselves into cooperatives. It is only when we are able to overcome our fear, that we can step ahead and progress in life.

23955.

From where did the peddler get the idea of the world being a rattrap?

Answer»

The peddler lived a dull and monotonous life. He had no family, no money and no relatives. He was a vagabond. So, being alone most of the time, he used to go on thinking. While thinking about the rattrap, he suddenly got the idea of the world being a rattrap.

23956.

Why did the peddler derive pleasure from his idea of the world as a rattrap?

Answer»

The world had never been kind to the poor peddler. Wherever he went, he was greeted with sour faces and was turned or chased away. Therefore, he derived pleasure from thinking ill of the world in this way. Moreover, he perhaps envied those whose lot was better than his and was rather amused to think that someday they too would be tempted by the bait and be caught in the Rattrap.

23957.

In what sense was the world a big rattrap according to the peddler? ORWhy did the peddler think that the world was a rattrap?

Answer»

The peddler was an extremely poor man who earned his living by selling rattraps he made himself from the materials he got by begging. His mind, thus, was always preoccupied with rattraps. One day, he suddenly thought of the whole world was a big rattrap. He felt that the shelter, food, clothes, riches and joys that the world provided were all baits set to entrap man just as a rattrap offered cheese or meat to entrap rats. As soon as one was trapped, everything came to an end.

23958.

Who was rattrap

Answer»

The Rattrap is a story about a rattrap seller who leads a very poor life as his earnings are very low. He has to resort to thievery and begging to make both ends meet. He is alone in this whole world and leads a miserable life. So he starts knitting up various kinds of thoughts.

23959.

(ii) \( \frac{x}{3}+\frac{2 y}{5}-x y+7 \)find numerical coefficient of each term

Answer»

f(x, y) = x/3 + 2/5 y - xy + 7

coefficient of x = 1/3,

coefficient of y = 2/5,

coefficient of xy = -1 and

constant term = 7.

23960.

\( 16-a^{6}+4 a^{3} b^{3}-4 b^{6} \)

Answer»

Its not mentioned in the question that we have to factorise or not.

From the best of my knowledge i am factorising it.

16 - a6 + 4 a3b3 - 4b6

= 16 - {(a3)2 - 2.a3.2b3 + (2b3)3}

= (4)2 - (a- b3)2

= { 4 + (a3 +  b3) }  { 4 - (a3 + b3) } 

= (4 + a3 + b3) (4 - a3 - b3)  

= {4 + (a + b) (a2 - ab + b2 )} {4 + (a−b)(a+ ab + b2)}

23961.

Directions: In the following question, two statements are numbered as Quantity I and Quantity II. On solving these statements, we get quantities I and II respectively. Solve both quantities and choose the correct option.Quantity I: A shopkeeper bought 5 lollypops in one rupee and marks them up by 25%. If he allows a 12% discount, then how many lollypops should he sell at Rs.22?Quantity II: A shopkeeper bought 4 lollypops in one rupee and marks them up by 26%. If he allows a 10% discount, then how many lollypops should he sell at Rs.28.35?1. Quantity I < Quantity II2. Quantity I = Quantity II3. Quantity I ≥ Quantity II4. Quantity I > Quantity II5. Quantity I ≤ Quantity II

Answer» Correct Answer - Option 2 : Quantity I = Quantity II

Calculation:

Quantity I:

Cost of each lollypop = 1/5

Marked price per lollypop = 125% of 1/5

Discount = 12%

∴ Selling Price per lollypop = 88% of 125% of 1/5

⇒ (88 × 125)/(100 × 100 × 5)

⇒ 0.22

In Rs. 0.22 anyone can buy 1 lollypop.

Thus, in Rs. 22 anyone can buy = 1/0.22 × 22

⇒ 100

Quantity II:

Cost of each lollypop = 1/4

Marked price per lollypop = 124% of 1/4

Discount = 10%

∴ Selling Price per lollypop = 90% of 126% of 1/4

⇒ (90 × 126)/(100 × 100 × 4)

⇒ 0.2835

In Rs. 0.22 anyone can buy 1 lollypop.

Thus, in Rs. 22 anyone can buy = 1/0.2835 × 28.35

⇒ 100

Quantity I = Quantity II
23962.

Directions: In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.The ratio of P’s income to Q’s income is 4 : 5 and the difference between their income are Rs 20,000.Quantity A: P saves 30% of his income then what is his expenditure?Quantity B: Q spends 45% of his income then what is his saving?1. Quantity A ≥ Quantity B2. Quantity A ≤ Quantity B3. Quantity A = Quantity B or no relationship can be established4. Quantity A > Quantity B5. Quantity A < Quantity B

Answer» Correct Answer - Option 4 : Quantity A > Quantity B

Calculation:

Let P’s income be 4x and Q’s income be 5x.

∴ According to the question

⇒ 5x – 4x = 20,000

⇒ x = 20,000

∴ P’s income = 80,000

∴ Q’s income = 1,00,000

Quantity A:

P’s expenditure = 70% of 80,000

⇒ 56,000

Quantity B:

Q’s saving = 55% of 1,00,000

⇒ 55,000

Quantity A > Quantity B
23963.

If -1&lt; x &lt; 1, then 2 tan-1 x =?(a) sin-12x/1+x2 (b) sin-12x/1-x2 (c) sin-11-x2/1+x2 (d) sin-11+x2/1-x2

Answer»

(a) sin-12x/1+x2

23964.

d/dx[sin2x]=?(a) 2sinx cosx (b) 2sinx   (c) cos2x (d) sinx cosx

Answer»

(a) 2sinx cosx

23965.

If median is 31 and arithmetic mean is33 then the value of mode will be

Answer»

mode=3median-2mean

mode=3×31-2×33

mode=93-66

mode = 27

23966.

(i) A, B, C, D, E, F, G and H are eight students each having a different height (ii) D is shorter than A but taller than G. (iii) E is taller than H but shorter than C. (iv) B is shorter than D but taller than F. (v) C is shorter than G. (vi) G is not as tall as F. How many of them are definitely shorter than F?A. ThreeB. FourC. FiveD. Data inadequate

Answer» Correct Answer - B
(i)AgtDgtG , (ii)CgtEgtH , (iii)DgtBgtF , (iv)GgtC , (v)F gt G
From all the statements
AgtDgtBgtFgtGgtCgtEgtH
G,C,E and H are shorter than F
23967.

Let `X`be the setconsisting of the first 2018 terms of the arithmetic progression `1, 6, 11 , ddot,`and `Y`be the setconsisting of the first 2018 terms of the arithmetic progression `9, 16 , 23 , ddot`. Then, thenumber of elements in the set `XuuY`is _____.

Answer» Correct Answer - 3748
Here `X={1,6,11, …, 10086}" "[because a_(n)=a+(n-1)d]`
and `Y={9,16,23, …, 14128}`
`X cap Y=[16,51,86, …}`
`t_(n) " of " X cap Y` is less than or equal to 10086
`therefore t_(n)=16+(n-1)35 le 10086 rArr n le 288.7`
`therefore n=288`
`because n (X cap Y) =n(X) +n(Y)-n(X cap Y)`
` therefore n(X cap Y)=2018 +2018+288=3748`
23968.

How to write a perfect essay on cleanliness?

Answer»

Cleanliness meaning is “to keep clean and to avoid dirt”. The practice to clean everything is cleanliness. There are different types of cleanliness, the cleaning of clothes, the cleaning to house; the cleaning of streets, the cleaning of ourselves etc. the most important is to clean ourselves because if we do not care for our cleanliness, we do not bother about the cleaning of surroundings. We feel the importance of cleanliness only when we do practice of cleaning ourselves. The practice of hand washing and bathing is necessary to keep ourselves clean. The person who keeps his self dirty, he also keeps his environment dirty and filthy. So to clean the environment, one should practice cleanliness by his own.

The cleaning of environment is very important. The environment is may be your home, your school, or your office. Some people has habit to throw things on road, this is illegal and a hurdle for cleanliness. The cleaning environment puts healthy effects on our mind and body, while a dirty environment puts very bad affects on our health and mind. Almost all the diseases are caused by the infectious agents in the environment and these infectious agents are very active in dirty and filthy environments. Many diseases like hepatitis, diarrhea, cholera, flu etc are caused by the dirty environments. Hepatitis is very dangerous disease and is usually transferred by the use of unsterilized instruments. Even some doctors do not care about cleanliness and throw the hospital waste near hospital or houses. This carelessness is causing fatal diseases.

All of us should clean our environment by throwing the garbage in some isolated place far away from the populated areas. if we clean our homes then we should also clean our streets because we live there, and dirty streets impose bad affects on our mind and health. There is a need to teach about the importance of cleanliness on national and international levels.

Keep the environment clean for yourself and for the nation.

First you should know how to write perfect essay which will boost you to write perfect essay on any subject.

Some of the tips that should be taken care of while writing an essay:


1. Get started by brainstorming(Gathering Information).

Brainstorming about subject, traits and defining your words in perfect manner.

2. Let your first draft flow.

After you've gathered your notes, create an outline to organize your essay and decide where you want examples to appear. Now you're ready to write your first draft. Don't worry about making it perfect. Just get your ideas flowing and your thoughts down on paper. You'll fix mistakes and improve the writing in later drafts.

3. Develop three essay parts

  • Introduction: One paragraph that introduces your essay.
  • Body: Several paragraphs explaining the main idea with examples.
  • Conclusion: One paragraph that summarizes and ends the essay.

4. Be specific

Give your essay focus by figuring out how the question relates to the subject and then taking a specific angle. Make sure everything you write supports that viewpoint.

5. Be honest​

The essay question might ask you about your views on the subject. Don't be tempted to write what you think the reader want to hear; answer the question honestly.

6. Proofread and make corrections.

Read your essay over carefully to check for typos and spelling and grammar errors. It's best to ask someone who hasn't seen it yet to take a look as well. They're likely to see mistakes you won't catch.

*Hope this will help you the best.

23969.

The displacement (in metre) of a particle moving along x-axis is given by = 18 + 5 2 . Calculate: Instantaneous acceleration.

Answer»

using diffrentiation method
x = 18t + 5t2
dx / dt = 18 + 10t
v = 18 + 10t 
t = 2 sec
v = 18 + 10 * 2 
= 18 + 20 
= 38 m / sec
t = 3 sec
v = 18 + 10 * 3
= 18 + 20
= 48 m / s
v(av) = 38 + 48/ 2 
= 43 m/swc
dv / dt = 10
a = 10 m/ s

23970.

Consider the statement : `" P(n) : n^(2)-n+41` is prime." Then, which one of the following is true?A. Both P(3) and P(5) are true.B. P(3) is false but P(5) is true.C. Both P(3) and P(5) are false.D. P(5) is false but P(3) is true.

Answer» Correct Answer - A
Given statement is "`P(n):n^(2)-n+41` is prime".
Clearly `(P(3):3^(2)-3+41=9-3+41`
`=47` which is a prime number.
and `P(5):5^(2) -5+41=25-5+41=61,`
which is also a prime number.
` therefore ` Both P(3) and P(5) are true.
23971.

In a group of data, there are n observations, `x,x_(2), ..., x_(n)." If "sum_(i=1)^(n)(x_(i)+1)^(2)=9n and sum_(i=1)^(n)(x_(i)-1)^(2)=5n`, the standard deviation of the data isA. 2B. `sqrt(7)`C. 5D. `sqrt(5)`

Answer» Correct Answer - D
We have, `sum_(i=1)^(n)(x_(i)+1)^(2)=9n " ...(i)" `
` and sum_(i=1)^(n)(x_(i)-1)^(2)=5n " ...(ii)" `
On substracting Eq. (ii) from Eq. (i) is, we get
`rArr sum_(i=1)^(n){(x_(i)+1)^(2)-(x_(i)-1)^(2)}=4n`
`rArr sum_(i=1)^(n)4x_(i) =4n rArr sum_(i=1)^(n)x_(i)=n rArr (sum_(i=1)^(n)x_(i))/(n)=1`
` therefore " mean " (bar(x))=1`
Now, standard deviation `=sqrt((sum_(i=1)^(n)(x_(i)-bar(x))^(2))/(n))=sqrt((sum_(i=1)^(n)(x_(i)-1)^(2))/(n))`
`=sqrt((5n)/(n))=sqrt(5)`
23972.

Fill in the blanksIf `x

Answer» Correct Answer - `-1 and 2`
Since, `x gt 0, y lt 0`
`and x+y+(x)/(y) =(1)/(2)`
`and (x+y) *(x)/(y)= -(1)/(2) rArr -(y)/(2x)+(x)/(y)+(1)/(2)`
Let `(x)/(y) =t`
`rArr -(1)/(2t)+t=(1)/(2)`
`rArr 2t^(2)-1=t rArr 2t^(2)-t-1=0`
`therefore t= -(1)/(2) ["but "x gt 0 and y lt 0 therefore (x)/(y) lt 0 " neglecting "1]`
`rArr (x)/(y) = -(1)/(2) rArr y=-2x rArr x+y+(x)/(y) =(1)/(2)`
`rArr x-2x-(1)/(2) =(1)/(2) rArr x= -1 and y=2`
23973.

The solution of the equation `(log)_7(log)_5(sqrt(x+5)+sqrt(x))=0`is ... (1986, 2M)

Answer» Correct Answer - 4
Given equation is
`log_(7)log_(5)(sqrt(x+5)+sqrt(x))=0 rArr log_(5)(sqrt(x+5)+sqrt(x))=1`
`rArr sqrt(x+5)+sqrt(x)=5 rArr sqrt(x+5) =5-sqrt(x)`
`rArr x+5=25+x-10sqrt(x) rArr 10sqrt(x)=20 rArr sqrt(x) =2`
`therefore x=4`
23974.

The mean square deviations of a set of observations `x_(1),x_(2), …, x_(n)` about a point c is defined to be `(1)/(n) sum_(i=1)^(n)(x_(i)-c)^(2)`. The mean square deviations about -1 and +1 of a set of observations are 7 and 3, repectively. Find the standard deviation of this set of observations.

Answer» Correct Answer - `sqrt(3)`
Mean square deviations `=(1)/(n) sum_(i=1)^(n)(x_(i)-c)^(2)`, about c.
Also, given that mean square deviation about -1 and +1 are 7 and 3, respectiveyl.
`rArr (1)/(n)sum_(i=1)^(n)(x_(i)+1)^(2)=7 and (1)/(n)sum_(i=1)^(n)(x_(i)-1)^(2)=3`
`rArr sum_(i=1)^(n)x_(i)^(2)+2sum_(i=1)^(n)x_(i)+n=7n and sum_(i=1)^(n)x_(i)^(2)-2sum_(i=1)^(n)x_(i) +n-3n`
`rArr sum_(i=1)^(n)x_(i)^(2)+2sum_(i=1)^(n)x_(i) =6n and sum_(i=1)^(n)x_(i)^(2) -2sum_(i=1)^(n)x_(i)=2n`
`rArr sum_(i=1)^(n)x_(i)-n rArr bar(x) =(sum_(i=1)^(n)x_(i))/(n)=1`
`therefore` Standard deviation
`=sqrt((1)/(n)sum_(i=1)^(n)(x_(i)-bar(x))^(2))=sqrt((1)/(n)sum_(i=1)^(n)(x_(i)-1)^(2))=sqrt(3)`
23975.

The marks obtained by 40 students are grouped in a frequency table in class intervals of 10 marks each. The mean and the variance obtained from this distribution are found to be 40 and 49, respectively. It was later discovered that two observations belonging to the class interval (21 - 30) were included in the class interval (31 - 40) by mistake. Find the mean and the variance after correcting the error.

Answer» Correct Answer - 49.25
Given , `n=40, bar(x)=40, var(x) =49`
`rArr bar(x)=(Sigmaf_(i)x_(i))/(40)=40 rArrSigmaf_(i)x_(i)=1600`
Also, var`(x)=49`
`rArr (1)/(40)Sigma f_(i)(x_(i)-40)^(2)=49`
`therefore 49=(1)/(40) (Sigmax_(i)^(2)f_(i))-2Sigma x_(i)f_(i)+40Sigma f_(i)`
`rArr 49=(1)/(40) (Sigma x_(i)^(2)f_(i))-2(1600)+40xx40`
`therefore Sigma x_(i)^(2) f_(i)=1649 xx40`
Let (21-30) and (31-40) denote the kth and (k + 1)th class intervals, respectively.
Then, if before correction `f_(k) and f_(k+1)` are frequencies of those intervals, then after correction (2 observations are shifted form (31-40) to (21-30), frequency of kth interval becomes `f_(k+2)` and frequency of (k+1)th interval becomes `f_(k+1)-2`
`therefore bar(x)_("new")=(1)/(40){underset(i ne k,k+1)(sum_(i=1)^(40)f_(i)x_(i))+(f_(k)+2)x_(k)+(f_(k+1)-2)x_(k+1)}`
`bar(x)_("new")=(1)/(40){sum_(i=1)^(40)f_(i)x_(i)}+(2)/(40){(x_(k)-x_(k+1))}`
`=(1)/(40)sum_(i=1)^(40)f_(i)x_(i) +(1)/(20)(-10)=39.5`
`=(1)/(40)[sum_(i=1)^(40)f_(i)(x_(i)-39.5)^(2) +f_(k)(x_(k)-39.5)^(2)+f_(k+1)(x_(k+1)-39.5)^(2)" where " i ne k, k+1]`
`=(1)/(40)[Sigma(f_(i)x_(i)^(2)-79f_(i)x_(i)+(39.5)^(2)f_(i))]`
`=(1)/(40) sum_(i=1)^(40)f_(i)*x_(i)^(2)-79((1)/(40)) sum_(i=1)^(40)f_(i)x_(i)+(39.5)^(2)*(1)/(40) sum_(i=1)^(40)f_(i)`
`=1649-3160+1560.25=49.25`
23976.

need solution for 41st  questionThe greater and least resultant of two forces are 7N and 3N respectively. If each of the force is increased by 3N and applied at 60 degree. The magnitude of the resultant is

Answer»

Let the two forces be x and y

Greatest resultant ( parallel cosz=1) = x+y = 7N ------------(1)

Least Resultant ( antiparallel cosz= -1) = x-y = 3N -------------(2)

Solving equation (1) and (2) we get  x =5N, y =2N

Each force is increased by 3N

Therefore x = 8N, y = 5N

Resultant vector = ( x2 + y2 +2xycos60o)1/2

= (64 + 25 + 2*8*5*1/2)1/2

= √129

23977.

A Fireman has to carry an injured person of mass 40 kg from the top of a building with the help of the Rope which can with stand A Load of hundred kg the acceleration of the fire man if his mass is 80 kg will be​

Answer»

Mass of man = 40kg

Mass of fireman = 80 kg

To find :

The acceleration of the fire man

Solution :

  • Total mass = 120 kg
  • Maximum Tension = 100×9.8
  • The total weight of persons = 120×(g-a)
  • The total weight should not exceed maximum  tension

             120×(9.8-a) = 100×9.8

  • By solving the above equation a = 1.63 m/s²

The acceleration of the fire man is 1.63 m/s²

23978.

Who among the following had attended all the three Round Table Conferences in London? (a) M K Gandhi (b) B R Ambedkar (c) J L Nehru (d) M M Malaviya

Answer»

(b) B R Ambedkar

23979.

Who of the attended all the three Round Table Conferences?(A) B.R. Ambedkar(B) M.M. Malavia(C) Vallabhbhai Patel(D) Gandhiji

Answer»

(A) Bhimrao Ambedkar

 Dr Ambedkar attended all the three Round Table Conferences in London and each time, forcefully projected his views in the interest of the “untouchable'' He exhorted the downtrodden sections to raise their living standards and to acquire as much political power as possible. He was of the view that there was no future for untouchables in the Hindu religion and they should change their religion if it is needed. In 1935, he publicly proclaimed, "I was born a Hindu because I had no control over this but I shall not die a Hindu".

23980.

The sorrow of Bihar is(A) Damodar(B) Kosi(C) Son(D) Gandak

Answer»

(B) Kosi   

Kosi is known as the "sorrow of Bihar", as it has caused widespread human suffering in the past due to flooding and very frequent changes in course, when it flows from Nepal to Bihar. Over the last 250 years, the Kosi River has shifted its course over 120 km from east to west. Its unstable nature has been attributed to the heavy silt it caries during the monsoon season and flooding in India has extreme effects.

23981.

A fuse wire is made of(A) an alloy of tin and copper(B) an alloy of tin and lead(C) an alloy of tin and aluminium(D) an alloy of nickel and chromium

Answer»

(B) an alloy of tin and lead

Electric fuse wire is an alloy made of tin (63%) & lead (37%). The cross sectional area determines the melting point at a certain current. Alloys (e.g. tin/lead) are used due to their ‘eutectic’ action i.e. the resulting combination of good conductivity (due to the tin) with a low melting point due to the lead.

48. The most basic kind of soap is made from caustic soda and animal fat. The two are heated together and then cooled. The process is called "saponification". In 

23982.

Soap is prepared by boiling caustic soda with(A) .Alcohol(B) Kerosene oil(C) Glycerine(D) Fats

Answer»

(D) an alloy of nickel and chromium

The most basic kind of soap is made from caustic soda and animal fat. The two are heated together and then cooled. The process is called "saponification". In 

23983.

Which of the following politicians of the United Kingdom with Indian roots was appointed UK's Chancellor of the Exchequer in February 2020?1. Navendu Mishra2. Priti Patel3. Rishi Sunak4. Alok Sharma

Answer» Correct Answer - Option 3 : Rishi Sunak

The correct answer is Rishi Sunak.

  • Rishi Sunak politician of the United Kingdom with Indian roots was appointed UK's Chancellor of the Exchequer in February 2020.
  • Rishi Sunak (born on 12 May 1980) is a British politician who has been Chancellor of the Exchequer since February 2020.
  • A member of the Conservative Party, he was previously Chief Secretary to the Treasury from July 2019 to February 2020.
  • He has been the Member of Parliament for Richmond (Yorks) in North Yorkshire since 2015
  • He served in Theresa May's second government as Parliamentary Under-Secretary of State for Local Government.
  • Javid was replaced by his former second-in-command Rishi Sunak, a relatively new entity in British politics.

  •  Alok Sharma :
    • Alok Sharma is a British politician.
    • He is currently serving as President for COP26, based in the Cabinet Office, and is a full member of the Cabinet.
    • He has been the Conservative Member of Parliament for Reading West since 2010.
  • Priti Patel :
    • Priti Sushil Patel is a British politician serving as Home Secretary since 2019.
    • She previously served as Secretary of State for International Development from 2016 to 2017.
    • A member of the Conservative Party, she has been a Member of Parliament for Witham since 2010.
  • Navendu Mishra :
    • Navendu Prabhat Mishra is a British Labour Party politician who has served as the Member of Parliament for Stockport since 2019.
    • Mishra is a member of the Socialist Campaign Group and endorsed fellow SCG member Rebecca Long-Bailey in the 2020 Labour leadership election.
23984.

What are the signals that inform operating the system that some activity has taken place called?(A) Informers(B) Interrupts(C) Events(D) Handlers

Answer»

Han(D) dlers

In computer programming, an event handler is an asynchronous callback subroutine that handles inputs received in a program. Each event is a Piece of application-level information from the underling framework, typically the GUI toolkit. GUI events include key presses, mouse movement, action selections and timers expiring. Event handlers are a central concept in event-driven programming.

23985.

(i) A, B, C, D, E, F, G and H are eight students each having a different height (ii) D is shorter than A but taller than G. (iii) E is taller than H but shorter than C. (iv) B is shorter than D but taller than F. (v) C is shorter than G. (vi) G is not as tall as F. which of the following is definitely false ?A. G is shorter than FB. C is shorter than FC. F is taller than CD. All are true

Answer» Correct Answer - D
(i)AgtDgtG , (ii)CgtEgtH , (iii)DgtBgtF , (iv)GgtC , (v)F gt G
From all the statements
AgtDgtBgtFgtGgtCgtEgtH
All statements are true
23986.

Who was the first Indian to become member of British parliament?(A) Bankim Chander Chatterjee(B) W.C. Bannerjee(C) Dadabhai Naoroji(D) None of the above

Answer»

(C) Dadabhai Naoroji

Dadabhai Naoroji was a Member of Parliament (MP) in the United Kingdom House of Commons between 1892 and 1895 and the first Asian to be a British MP.

23987.

In which year did the last king of Punjab Maharaja Duleep Singh ascend on the throne of Punjab at 10 years of age?1. 18242. 18493. 18364. 1852

Answer» Correct Answer - Option 2 : 1849

The correct answer is 1849.

  • In the year 1849, the last king of Punjab Maharaja Duleep Singh ascends the throne of Punjab at 10 years of age.
    • After the close of the Second Anglo-Sikh War and the subsequent annexation of Punjab on 29 March 1849, he was deposed at the age of ten and was put into the care of Dr. John Login and sent from Lahore to Fatehgarh on 21 December 1849, with tight restrictions on who he was allowed to meet.

  • The eighth son of Maharaja Ranjit Singh, and that too from a minor wife, Duleep Singh became Maharaja of Punjab when he was just five years old.
    • But within six years, his kingdom, the sole independent power in mid-19th century north India, was defeated twice in battle by the British and annexed, he had to hand over the world's most famous diamond and spent the rest of his life in overseas exile.
  • Duleep Singh never abandoned hope of regaining his kingdom - though his efforts were subverted by the British, managed to hit back at them - especially over the Kohinoor - and his memory endures in both India and Britain in some curious ways, says British historian Peter Bance, author of half a dozen books on Sikh history in Britain.
    • These include "The Duleep Singh's: The Photograph Album of Queen Victoria's Maharajah", and "Sovereign, Squire & Rebel: Maharajah Duleep Singh and the heirs of a Lost Kingdom".
23988.

Name any two important salts present in the ocean water.

Answer»

Important salts resent in the ocean water are Sodium Chloride, Magnesium chloride, Calcium sulphate.

23989.

Mention the difference between weather and climate.

Answer»

Weather refers to frequent changes or average condition in the atmosphere of a place at a given time.

The average weather condition of palace for a long period like 30- 33 years in known as climate.

23990.

Give two examples for local winds.

Answer»

Loo (India) Foehn (Northern Alps) Brickfielder (Austrialia).

23991.

What is air pressure? Name the instrument used to measure atmosphere pressure.

Answer»

Air pressure is the force exerted by air on the Earth. The atmospheric pressure is measured by an instrument called Barometer. 

23992.

What are exogenic and endogenic forces?

Answer»

The internal fopces are also known as endogenic forces. There are mainly the land building forces. 

The external forces are also known as Exogenic forces. These forces are found on the surface of the Earth.

23993.

Mention any two types of chemical weathering. 

Answer»

1. Oxidation 

2. Carbonation

23994.

State the difference between Endogenic and Exogenic forces.

Answer»

The internal forces are called endogenic forces. These are mainly the land building forces. 

The external forces are called exogenic forces. These are found on the surface of the earth.

23995.

The banker's discount on Rs. 1800 at 12% per annum is equal to the true discount on Rs. 1872 for the same time at the same rate. Find the time.

Answer»

S.I. on Rs. 1800 = T.D. on Rs. 1872. 

P.W. of Rs. 1872 is Rs. 1800. 

Rs. 72 is S.I. on Rs. 1800 at 12%. 

Time =[(100 x 72)/ (12 x 1800)]year 1/3 year = 4 months.

23996.

The true discount on a certain sum of money due 3 years hence is Rb. 250 and the simple interest on the same sum for the same time and at the same rate is Rs. 375. Find the sum and the rate percent.

Answer»

T.D. = Rs. 250 and S.I. = Rs. 375. 

Sum due =S.I. x T.D./ S.I. -T.D. = 375 x 250/375- 250 = Rs.750. 

Rate=[100*375/750*3]%=16 2/3%

23997.

Banker’s gain on a bill due after 6 months at 4% p.a. is 24. Find true discount and Banker’s discount,

Answer»

Given B.G = 24. T = 6 months, = \(\frac{1}{2}\)yr, r = 4% = 0.0 

BG = TD + r 

24 = TD × \(\frac{1}{2}\) × 0.04 

\(TD = \frac{24 \times 2}{0.04} = \frac{24 \times200}{4} = 1200\)

TD = 1200 

BG = BD – TD ⇒ BD = BG + TD = 24 + 1200 = 1224

23998.

Find the present worth of Rs. 930 due 3 years hence at 8% per annum. Also find the discount.

Answer»

P.W = 100 x Amount /[100 + (R x T)] 

= Rs.100 x 930/100+ (8 x 3) 

= (100 x 930)/124 

= Rs. 750, 

T.D. = (Amount) - (P.W.) = Rs. (930 - 750) = Rs. 180.

23999.

The difference between banker’s discount and true discount on a bill due after 6 months at 4% interest p.a. is Rs. 20. Find the true discount, banker’s discount and face value of the bill.

Answer»

BG = ₹ 20, r = 4% = 0.04, t = 6 Months = 6/12 = 1/2

TD = ?, BD = ?, F = ? 

W.K.T. = BG = TD. 

Rs. 20 = TD 1/2 x 0.04 

40 = 0.04 TD ⇒ TD = 40/0.04 = ₹ 1000 

BD = BG + TD; = 20 + 1000 = 1020

F = (BD x TD)/BG = (1020 x 1000)/20 = 51, 000

24000.

The banker's discount on Rs. 1650 due a certain time hence is Rs. 165. Find the true discount and the banker's gain.

Answer»

Sum = [(B.D.x T.D.)/ (B.D.-T.D.)] = [(B.D.x T.D.)/B.G.] 

T.D./B.G. = Sum/ B.D. 

= 1650/165 

=10/1 

Thus, if B.G. is Re 1, T.D. = Rs. 10. 

If B.D.is Rs. ll, T.D.= Rs. 10.

If B.D. is Rs. 165, T.D. = Rs. [(10/11) x l65] 

= Rs.150 

And, B.G. = Rs. (165 - 150) = Rs, 15.