Explore topic-wise InterviewSolutions in .

Correct option is A) so 

Correct option is B) amendments

Correct option is B) prepare

Correct option is C) after 

Correct option is B) exchanged

Correct option is C) in 

Vandana Shiva learned about bio-diversity in the Himalayan forests, and transferred those lessons learnt, to the protection of biodiversity on their farms. She started saving seeds from farmers’ fields and then realized they needed a farm for demonstration and training. So, she started “Navdanya farm” in 1994 in the Doon valley located in the lower elevations of the Himalayan region of Uttarkhand province. She conserved and grew 630 varieties of rice, 150 varieties of wheat and hundreds of other species. Bio-diversity also helps to produce more food and nutrition per acre and reduces malnutrition and improves human health.

Correct option is B) devotion

Correct option is C) exclusion

Correct option is A) on 

Correct option is A) make

A Sunny Morning” is a pun phrase as it blends both romance and comedy because sunny morning is mixed with chill and heat. If we stand in shade we feel the chill and if we stand in sun it scorches, chill refers to comedy and hot sun refers to romance of the lovers’ past memories.

Correct option is B) from 

The main objective of a Sales Organization is to effect Sales.

Correct option is B) has been elected

Correct option is C) have lost / Did you see

Correct option is B) us 

Correct option is C) to 

Organized Sector refers to trading activities undertaken by licensed retailers.

It is necessary for specialty store to have Robust Customer loyalty program.

Todays consumer is more Demanding and Knowledgeable.

Correct option is B) watches 

Correct option is D) were told

d.Missed deadlines

Correct option is B) didn’t 

Correct option is B) was / at 

Given:

Money was distributed in the ratio of 5 : 7.

New ratio = 3 ∶ 4

Concept used:

Using linear equation.

Calculation:

The money distributed between Shivani and Parinita be 5x and 7x. 

Parinita gives Rs. 5 to Shivani ,

Parinita's money = 7x – 5.

Shivani's money = 5x + 5.

According to question,

 (5x + 5)/(7x – 5) = 3/4

⇒ 4(5x + 5) = 3(7x – 5)

⇒ 20x + 20 = 21x – 15

⇒ 20 + 15 = 21x – 20x

⇒ x = 35

Total amount = 5x + 7x 

= 12x

= 12 × 35

= 420

∴ The amount divided is Rs.420.

Given:

The ratio of two numbers be 19 : 26.

New ratio will be 3 : 4.

Concept Used:

Ratio concept used.

Calculation:

Let the two numbers be 19x and 26x.

If 2 added to 19x = 19x + 2.

According to the question,

(19x + 2)/26x = 3/4

⇒ 4(19x + 2) = 3 × 26x

⇒ 76x + 8 = 78x

⇒ 2x = 8

⇒ x = 4

So, Big number =  26 × 4 = 104

∴The big number is 104.

Calculation:

The series follows the following pattern

0.5 × 2 = 1

1 × 3 = 3

3 × 4 = 12

12 × 5 = 60

60 × 6 = 360

∴ The Required term in the series will be 360

Calculation:

Selling Price = 40,50,000

Let the CP of the plot be x

∴ 40,50,000 = x – (x × 10%)

⇒ 40,50,000 = 9x/10

⇒ x = 45,00,000

CP = 45,00,000

So, SP to get 20% profit

⇒ 45,00,000 + (4500000 × 20%)

⇒ 54,00,000

He should sell at 54,00,000. 

Given:

New Selling price = 2 × SP

New profit = 3 × P

Concept used:

Profit % = {(SP - CP)/CP} × 100

Calculation:

P = SP - CP      ----(1)

3P = 2SP - CP      ----(2)

On multiplying equation (1) by 3, we get 

3P = 3SP - 3CP     ----(3)

Equating (3) and (2),

3SP - 3CP = 2SP - CP

⇒ SP = 2CP

Now, from (1) we have

P = SP - CP

⇒ P = 2CP - CP

⇒ P = CP

Profit percentage = (P/CP) × 100 = 100%

∴ The profit percentage is 100%.

Formula used:

Profit = SP - CP

Profit % = (Profit/CP) × 100

Here, SP → Selling price, CP → Cost price

Concept used:

Profit and the loss is always given on CP

Calculation:

Let the SP and CP be x and y respectively

Profit = (x - y)

Now, the S.P. is doubled, then the new S.P. is 2x

New profit = (2x - y)

According to the question:

⇒ 3(x - y) = 2x - y

⇒ 3x - 3y = 2x - y

⇒ x = 2y      ----(1)

Now, Profit = SP - CP

⇒ x - y = 2y - y = y      ----(from eq (1))

Profit % = (Profit/CP) × 100

⇒ (y/y) × 100 = 100%

∴ The profit is 100%

Given:

Pipe A takes 5 hours less than pipe B to fill a cistern.

Time to fill the tank by pipe A and B together = 6 hours

Formula used:

Efficiency = Total work/total time

Concept used:

Let time to fill the whole tank by pipe B alone be x hours.

So, time to fill the whole tank by pipe A will be (x - 5) hours.

Let capacity of total tank be 6x(x - 5) units.

Efficiency of pipe A = 6x(x - 5)/(x - 5)

⇒ 6x units/hour

Efficiency of pipe B = 6x(x - 5)/x

⇒ 6(x - 5) units/hour

Efficiency of A and B together = 6x(x - 5)/6

⇒ x(x - 5) units/hour

Equating combined efficiency,

6x + 6(x - 5) = x(x - 5)

⇒ 6x + 6x - 30 = x² - 5x

⇒ 12x - 30 = x² - 5x

⇒ x² - 5x - 12x + 30 = 0

⇒ x² - 17x + 30 = 0

⇒ (x - 15)(x - 2) = 0

Taking (x - 15) = 0

⇒ x = 15 hours

∴ Pipe B will fill the cistern in 15 hours.

Given:

Sum of the numbers = 156

H.C.F of numbers = 12

Concept used:

If H.C.F of two numbers is H, then number are Hx and Hy. Where x and y are relatively prime number or coprimes.

Calculation:

Let numbers are 12x and 12y, where x and y are coprimes

Now, 12x + 12y = 156

⇒ 12 (x + y) = 156

⇒ x + y = 156/12 = 13

∴ possible values if x and y are

(x = 1, y = 12), (x = 2, y = 11)

(x = 3, y = 10), (x = 4, y = 9)

(x = 5, y = 8), (x = 6, y = 7)

Given :

A number when divided by 9,10 and 15 the remainder in each case be 3

What least number should be subtracted from 2983 to get desired result

Concept used :

Take the LCM of given numbers to get required value and perform accordingly

Calculation :

LCM of 9,10 and 15 = 90

Now, when 2983 divided by 90 the remainder is 13 

⇒ 13 should be subtracted from 2983 to make it divisible by all three numbers i.e. 9,10 and 15

⇒ Desired number = 2983 - 13

⇒ 2970

but there should be remainder of 3 in each case

⇒ 3 must be added to 2970

⇒ 2973

⇒ 10 is the least number that should be subtracted from 2983 to get desired result

We are given the following equation:

\({\left[ {\left( {1 - \;\frac{1}{2}} \right)\left( {1 - \;\frac{1}{3}} \right)\left( {1 - \;\frac{1}{4}} \right)\left( {1 - \;\frac{1}{5}} \right) \ldots \ldots ..\left( {1 - \;\frac{1}{{100}}} \right)} \right]^{ - 0.5}} = \;?\)

⇒ [(1/2) × (2/3) × (3/4) × (4/5) × .................. × (99/100)]^–0.5 = ?

In this equation, each denominator of previous term will be cancelled out by the numerator of the next term.

Hence, we obtain:

⇒ [1 × (1/100)]^–0.5

⇒ (100)^0.5

⇒ 10

∴ \({\left[ {\left( {1 - \;\frac{1}{2}} \right)\left( {1 - \;\frac{1}{3}} \right)\left( {1 - \;\frac{1}{4}} \right)\left( {1 - \;\frac{1}{5}} \right) \ldots \ldots ..\left( {1 - \;\frac{1}{{100}}} \right)} \right]^{ - 0.5}} = \;10\)

Concept:

• The slope m of the line joining the two points (x₁, y₁) and (x₂, y₂) is m = \(\rm \frac{y_1-y_2}{x_1-x_2}\).
• The slopes of parallel lines are the same.
• If the lines have the same slope and also have a common point, then they are the same line.

Calculation:

Let's say that the points are A(-a, -b), B(0, 0), C(a, b) and D(a², ab).

Using the slope formula, the slope of the line AB will be:

m_AB = \(\rm \frac{-b-0}{-a-0}=\frac{-b}{-a}=\frac{b}{a}\)

Also, the slopes of the lines BC, CD and AD are:

m_BC = \(\rm \frac{0-b}{0-a}=\frac{-b}{-a}=\frac{b}{a}\)

m_CD = \(\rm \frac{b-ab}{a-{a}^{2}}=\frac{b(1-a)}{a(1-a)}=\frac{b}{a}\)

m_AD = \(\rm \frac{-b-ab}{-a-{a}^{2}}=\frac{b(-1-a)}{a(-1-a)}=\frac{b}{a}\)

Since the slopes of all the lines are same and they also have some common points between them, we can say that the points are actually collinear.

The correct answer is B. Collinear.

Solution:                        

Formula Used:

LCM × HCF = Product of two numbers

Calculations:

LCM = product of numbers/HCF

LCM = 1250/HCF      

LCM : HCF = 1250/(HCF)²

⇒ 1250/25² = 2

⇒ 2 : 1

Hence LCM : HCF = 2 : 1

Given:

If 25% of a number is subtracted from 100, it gives number itself. What is the number?

Calculation:

Let the number be x

According to the question,

⇒ 100 – [25 × (x/100)] = x

⇒ x + (25x/100) = 100

⇒ 125x = 10000

⇒ x = 10000/125

⇒ x = 80

∴ The number is 80.

Worker A is 25% more efficient than B and C takes 8 days more than A to complete the work 

∴ Let the time taken by B to complete the work be x days

Then, time taken by A = x × (100/125) = 4x/5

Time taken by C = (4x/5) + 8 = 4(x + 10)/5

Together can complete the work in 5 days

∴ (1/x) + (5/4x) + (5/4x + 40) = 1/5

⇒ {4(x + 10) + 5(x + 10) + 5x}/4x(x + 10) = 1/5

⇒ (14x + 90)/(4x² + 40x) = 1/5

⇒ 70x + 450 = 4x² + 40x

⇒ 4x² – 30x – 450 = 0

⇒ 2x² – 15x – 225 = 0

⇒ 2x² – 30x + 15x – 225 = 0

⇒ 2x(x – 15) + 15(x – 15) = 0

⇒ x = 15, -15/2

Rejecting negative value of x

Time taken by A = (4 × 15)/5 = 12 days

Time taken by D = 24 days

∴ Working together 

⇒ (1/12) + (1/24) = (2 + 1)/24 = 1/8

∴ Time taken by both of them is 8 days

Given:

LCM of 528, 336 and 154

Concept used:

Factorization method

Calculation:

528 = 2 × 2 × 2 × 2 × 3 × 11

336 = 2 × 2 × 2 × 2 × 3 × 7

154 = 2 × 7 × 11

LCM = 2 × 2 × 2 × 2 × 3 × 7 × 11 = 3696

∴ LCM of 528, 336 and 154 is 3696.

Given:

Quantity of water is twice the quantity of honey

Quantity of water initially = 300ml

Solution:

Quantity of water initially = 300ml

∴ Quantity of honey in the mixture = 300/2 = 150 ml

Now, 'x' ml of mixture is taken out and 80 ml of honey is added the ratio becomes 21 ∶ 26

Quantity of honey left = 150 – x × (150/450) + 80 = 230 – x/3

Quantity of water left = 300 – x × (300/450) = 300 – 2x/3

∴ (230 – x/3)/(300 – 2x/3) = 21/26

⇒ (690 – x)/(900 – 2x) = 21/26

⇒ 17490 – 26x = 18900 – 42x

⇒ 16x = 960

⇒ x = 60

∴ 60 ml of mixture is taken out

Quantity of honey = 230 – (60/3) = 230 – 20 = 210

Quantity of water = 300 – (120/3) = 300 – 40 = 260

Now,  '2x' ml of honey is added in the mixture 

∴ Quantity of honey = 210 + 120 = 330

Quantity of water = 260

∴ Required ratio = 330/260 = 33/26

∴ The ratio of honey and water in the final mixture is 33 ∶ 26

Capacity of channel is 1-H(p) 

H(p) is entropy function 

 With cross over probability of 0.5

H(p) = 1/2log₂1/0.5 + 1/2log₂1/0.5 = 1

⇒ Capacity = 1 - 1 = 0

Spreading factor(SF) = chip rate/symbol rate

This if a single symbol is represented by a code of 8 chips 

Chip rate =80×symbol rate

 S.F (Spreading Factor) = (8 symbol rate)/(symbol rate) = 8

Spread factor (or) process gain and determine to a certain extent the upper limit of the total number of uses supported simultaneously by a station. 

Correct option (D) The closed-loop system is unstable for sufficiently large and positive k

Explanation:

For larger values of K, it will encircle the critical point (-1+j₀), which makes closed-loop system unstable. 

Given G(s) = k/((s + 2)(s - 1))

H(s) = 1

Characteristic equation: 1 + G(s)H(s) = 0

1 + K/((s + 2)(s - 1)) = 0

The poles are s_1,2 = - 1± √(9/4 - 4k)

If 9/k - k = 0, then both poles of the closed loop system at the same location.

So, K = 9/4  ⇒ 2.25

Calculation:

Let the speed of stream be x

So, according to question

\(\frac{{60}}{{12.5\; + \;x}} + \frac{{60}}{{12.5 - x}} = 10\)

Solving it further

⇒ We get x = 2.5 km/hr