In certain mixture of honey and water, quantity of water is twice the

1.	In certain mixture of honey and water, quantity of water is twice the quantity of honey. If 'x' ml of mixture is taken out and 80 ml of honey is added the ratio of honey and water in the mixture becomes 21 ∶ 26. What will be the ratio of honey and water in the final mixture, if '2x' ml of honey is added in the mixture and quantity of water at the beginning was 300ml. 1. 30 ∶ 412. 33 ∶ 263. 35 ∶ 224. 9 ∶ 115. 21 ∶ 29
Answer» Correct Answer - Option 2 : 33 ∶ 26 Given: Quantity of water is twice the quantity of honey Quantity of water initially = 300ml Solution: Quantity of water initially = 300ml ∴ Quantity of honey in the mixture = 300/2 = 150 ml Now, 'x' ml of mixture is taken out and 80 ml of honey is added the ratio becomes 21 ∶ 26 Quantity of honey left = 150 – x × (150/450) + 80 = 230 – x/3 Quantity of water left = 300 – x × (300/450) = 300 – 2x/3 ∴ (230 – x/3)/(300 – 2x/3) = 21/26 ⇒ (690 – x)/(900 – 2x) = 21/26 ⇒ 17490 – 26x = 18900 – 42x ⇒ 16x = 960 ⇒ x = 60 ∴ 60 ml of mixture is taken out Quantity of honey = 230 – (60/3) = 230 – 20 = 210 Quantity of water = 300 – (120/3) = 300 – 40 = 260 Now, '2x' ml of honey is added in the mixture ∴ Quantity of honey = 210 + 120 = 330 Quantity of water = 260 ∴ Required ratio = 330/260 = 33/26 ∴ The ratio of honey and water in the final mixture is 33 ∶ 26

In certain mixture of honey and water, quantity of water is twice the quantity of honey. If 'x' ml of mixture is taken out and 80 ml of honey is added the ratio of honey and water in the mixture becomes 21 ∶ 26. What will be the ratio of honey and water in the final mixture, if '2x' ml of honey is added in the mixture and quantity of water at the beginning was 300ml. 1. 30 ∶ 412. 33 ∶ 263. 35 ∶ 224. 9 ∶ 115. 21 ∶ 29

Answer» Correct Answer - Option 2 : 33 ∶ 26

Given:

Quantity of water is twice the quantity of honey

Quantity of water initially = 300ml

Solution:

Quantity of water initially = 300ml

∴ Quantity of honey in the mixture = 300/2 = 150 ml

Now, 'x' ml of mixture is taken out and 80 ml of honey is added the ratio becomes 21 ∶ 26

Quantity of honey left = 150 – x × (150/450) + 80 = 230 – x/3

Quantity of water left = 300 – x × (300/450) = 300 – 2x/3

∴ (230 – x/3)/(300 – 2x/3) = 21/26

⇒ (690 – x)/(900 – 2x) = 21/26

⇒ 17490 – 26x = 18900 – 42x

⇒ 16x = 960

⇒ x = 60

∴ 60 ml of mixture is taken out

Quantity of honey = 230 – (60/3) = 230 – 20 = 210

Quantity of water = 300 – (120/3) = 300 – 40 = 260

Now, '2x' ml of honey is added in the mixture

∴ Quantity of honey = 210 + 120 = 330

Quantity of water = 260

∴ Required ratio = 330/260 = 33/26

∴ The ratio of honey and water in the final mixture is 33 ∶ 26