1.

\( 16-a^{6}+4 a^{3} b^{3}-4 b^{6} \)

Answer»

Its not mentioned in the question that we have to factorise or not.

From the best of my knowledge i am factorising it.

16 - a6 + 4 a3b3 - 4b6

= 16 - {(a3)2 - 2.a3.2b3 + (2b3)3}

= (4)2 - (a- b3)2

= { 4 + (a3 +  b3) }  { 4 - (a3 + b3) } 

= (4 + a3 + b3) (4 - a3 - b3)  

= {4 + (a + b) (a2 - ab + b2 )} {4 + (a−b)(a+ ab + b2)}



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