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\( 16-a^{6}+4 a^{3} b^{3}-4 b^{6} \) |
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Answer» Its not mentioned in the question that we have to factorise or not. From the best of my knowledge i am factorising it. 16 - a6 + 4 a3b3 - 4b6 = 16 - {(a3)2 - 2.a3.2b3 + (2b3)3} = (4)2 - (a3 - b3)2 = { 4 + (a3 + b3) } { 4 - (a3 + b3) } = (4 + a3 + b3) (4 - a3 - b3) = {4 + (a + b) (a2 - ab + b2 )} {4 + (a−b)(a2 + ab + b2)} |
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