This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 23101. |
Of the following, the one with the most stable frequency is the a. Armstrong b. Clapp c. Colpitts d. Hartley |
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Answer» The answer is: (b) Clapp |
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| 23102. |
The most widely used LC oscillator is the a. Armstrong b. Clapp C. Colpitts d. Hartley |
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Answer» The answer is: (c) Colpitts |
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| 23103. |
An inductor coil stores 32 J of magnetic field energy and dissiopates energy as heat at the rate of 320 W when a current of 4 A is passed through it. Find the time constant of the circuit when this coil is joined across on ideal battery.A. `t =0.2 s`B. `t =0.32 s`C. `t =0.5 s`D. `t =1 s` |
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Answer» Correct Answer - A Magnetic field energy stored `= 1/2 Li^(2)` `32 = 1/2 L(4)^(2) or L=4H` Power dissipated as heat is `P=i^(2)R` `320 =4^(2)R or R=20 Omega` Time constant of circuit =`tau=L/R 4/20 = 0.2 s`. |
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| 23104. |
A semiconducting device is connected in a series circuit with a battery and a resistance.A current is found to pass through the circuit .If the polarity of the battery is reversed, the current drops to almost zero.The device may beA. A P-type semiconductorB. An N-type semiconductorC. A PN-junctionD. An intrinsic semiconductor |
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Answer» Correct Answer - C When polarity of the battery is reversed, the P-N junction becomes reverse biased so no current flows. |
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| 23105. |
Find equivalent resistance |
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Answer» Answer is 6r/5 |
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| 23106. |
Voltage is a form of:A. Kinetic energyB. Potential energyC. both Potential and Kinetic energyD. None of the above |
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Answer» Voltage is a form of Potential energy. |
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| 23107. |
Column I gives ertain situtaions situations in which capacitance of a capacitor is charge by different means. Column II gives resulting effect under different conditions. Match the proper entries from colum - 2to column -1 using the codes given below the columns, `{:(," Column I",," Column II"),((P),"The plates of a plane parallel capacitor are slowly pulled apart. Then the magnitude of electric field intensity inside the capacitor.",(1),"Increases if the capacitor is maintained at constant5 charge."),((Q),"The paltes of a plane parallel plate capacitor are slowly pulled apart. Then the potential energy stored in the capacitor.",(2),"Decreases if the capacitor is maintained at constant charge"),((R),"The capacitance of an air filled plane parallel plate capacitor on insertion of dielectric",(3),"Increases if the capacitor is maintained at constant potential difference."),((S),"A dielectric on inserted an air filled plane parallel plate capacitor. The potential energy stored in the capacitor.",(4),"Decreases if the capacitor is maintained at constant potential difference."):}`A. `{:((P),(Q),(R),(S),),(1,2,4,3,):}`B. `{:((P),(Q),(R),(S),),(4,1,3,2,):}`C. `{:((P),(Q),(R),(S),),(1,2,3,4,):}`D. `{:((P),(Q),(R),(S),),(4,1,2,3,):}` |
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Answer» (A)At constant charge, the electric field within the capacitor remains same when plate separation is changed. The electric field in capacitor is `E=V/d`.Hence at constant potential difference the electric field decreases with increase in d. (B)`U=1/2Q^2/C`.Hence at constant charge U increases with decrease in C. `U=1/2CV^2`. Hence at constant potential difference U decreases with decrease in C. ( C)Capacitance increases on insertion of dielectric. (d)As a result of insertion of dielectric the capacitance increases. `U=1/2 Q^2/C`.Hence at constant charge U decreases with increase in C. `U=1/2 Q^2/C`.Hence at constant potential difference U increases with increase in C. |
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| 23108. |
If `y=sinx`, then `(d^2y)/(dx^2)` will beA. `cos x`B. `sin x`C. `- sin x`D. `sin x + C` |
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Answer» Correct Answer - C `y=sinx` `(dy)/(dx)=cosx` `(d^(2)y)/(dx^(2))=-sinx` |
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| 23109. |
An electric dipole is placed in a uniform electric field with its type of movement parallel to the field. Find: (I) The work done in turning the dipole till its dipole moment points in the direction opposite to E.(2) The orientation at dipole for which the torque acting on it becomes maximum. |
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Answer» Work done by external agent in rotating the dipole W = PE [cosθ1 - cosθ2] then W = PE [cos 0° - cos 180°] W = PE [1 - (-1)] W = 2PE t = rF sinθ t = rF sin 0° t = 0 |
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| 23110. |
A bus of length 5m is behind the car having the back view mirror of back radius of 2m. What will be the length of image when a bus 10m away. |
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Answer» h = 5 r = 2m d = r/2 = 1 m u = -10 m \(\frac1f=\frac1v+\frac1u\) \(\frac11=\frac1v-\frac1{10}\) \(\frac1v=1+\frac1{10}\) \(\frac1v=\frac{11}{10}\) v = \(\frac{10}{11}\) M = \(\frac{h_i}{h_o}\) \(\frac{h_i}{h_o}= \frac{-v}{u}\) \({h_i} = \frac{-v}{u}\times h_o\) \(h_i=\frac{-10}{11}\times\frac{1}{-10}\times5\) \(h_i=\frac5{11}\) |
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| 23111. |
Which of the following is valid for displacement? (1) It cannot be zero. (2) Its magnitude is greater than the distance travelled by the object. |
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Answer» Both the statements are not valid. When the object’s initial and final position is the same, the displacement can become zero. The shortest measurable distance between an object’s original and final locations is displacement. It should not be higher than the magnitude of an object’s distance travelled. But it can be equal to the distance that the object moves. (a) Displacement cannot be zero because the displacement of an object which travels a certain distance and comes back to its initial position is zero. (b) Its magnitude is greater than the distance travelled by the object because the displacement of an object can be equal to, but never greater than the distance travelled. |
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| 23112. |
Make a list of cultural heritage situated in Ahmedabad |
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Answer» please follow me ❤️ Here is the list of 16 Historical Places In Ahmedabad.
Top 10 Heritage Places in Ahmedabad. Ahmedabad is known for its quick and rapid growth for the past decade. When you go into the depth you will come to know about the history of this Pre-Mughal city. Situated on the bank of Sabarmati Rive it was one of the finest cities of Western India established by the king Ahmed Shah Badshah in the 15 th century Top 10 Heritage Places in Ahmedabad. Ahmedabad is known for its quick and rapid growth for the past decade. When you go into the depth you will come to know about the history of this Pre-Mughal city. Situated on the bank of Sabarmati Rive it was one of the finest cities of Western India established by the king Ahmed Shah Badshah in the 15 th century Sabarmati Ahsram Kankaria Lake. Jama Masjid. Siddi Saiyed Mosque. Dada Hari Ki Vav. Akshardham Temple. Jhulta Minar. Calico Textile Museum. ISKCON Temple Lal Darwaza Lalbhai Dalpatbhai Museum Vaishnodevi Temple Hathisingh Jain Temple World Vintage Car Museum Tomb of Ahmed Shah and Ahmed Shah's Mosque. Bhadra Fort & Teen Darwaza. |
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| 23113. |
The objective of supercharging an engine is : 1. To reduce space occupied by the engine 2. To increase the power output of an engine when greater power is required Which of the above statements are correct?(a) 1 only (b) 2 only (c) Both 1 and 2 (d) Neither 1 nor 2 |
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Answer» (c) Both 1 and 2 The main objective of supercharging is to increase the power output but at the same time supercharger are used where weight and space are important like racing car, automotive engine, marine engine. So, supercharging is used to reduce space occupied by engine. |
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| 23114. |
At what angle with the horizontal should a ball be thrown so that the range `R` is related to the time of flight as `R = 5 T^2` ? `(Take g = 10 ms6-2)`.A. `45^(@)`B. `15^(@)`C. `60^(@)`D. `90^(@)` |
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Answer» Correct Answer - A `(2 u^(2) sin theta cos theta)/(g)=5 ((2u sin theta)/(g))^(2)` `theta = 45^(@)`. |
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| 23115. |
A capacitor is charged to a voltage of 400V and has a resistance of 20ohm. Calculate the final value of the discharge current.(a) 10A(b) 0A(c) Infinity(d) 20A |
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Answer» Correct option is (d) 20A The explanation: In a discharging circuit, the final voltage is equal to zero for capacitor. For a resistor, final voltage is 400V.So,final current = V/R = 400/20 = 20A. |
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| 23116. |
Starting from rest a 10 kg object is acted upon by only one force as indicated in figure. Then the total work done by the force in 5 seconds is A. 90 JB. 320 JC. 245 JD. 490 J |
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Answer» Correct Answer - B Change in velocity `=("area under F-T graph")/("mass")` `=(120+(-40))/(10)=8 m//s` `W_(f)=DeltaK.E = (1)/(2)(10)8_(2) = 320 J` |
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| 23117. |
In lettering ‘A’ the height of capital letter is divided in how many parts?(a) 10(b) 14(c) 16(d) 8 |
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Answer» The correct choice is (b) 14 To explain I would say: In lettering ‘A’ type, the height of the capital letter is divided into 14 parts while in lettering ‘B’ type it is divided into 10 parts. The height of letters and numerals for engineering drawing can be selected from 2.5, 3.5, 5, 7, 10, 14 and 20 mm according to drawing size. |
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| 23118. |
Which grade of pencil is used for drawing arrowheads?(a) 2H(b) 2B(c) 7H(d) H |
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Answer» Correct option is (a) 2H Explanation: Arrowheads resembles the extent of dimensions. It should be sharply defined and uniform throughout the drawing. Generally, 3 mm in length is used. For such precision small diameter pencils are used, hence 2H is used as arrowheads. |
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| 23119. |
If the charge stored in a capacitor is 4C and the value of capacitance is 2F, calculate the energy stored in it.(a) 2J(b) 4J(c) 8J(d) 16J |
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Answer» Correct answer is (b) 4J Easy explanation: The expression for finding the value of energy is: U=Q^2/2C = 4*4/(2*2) = 4J. |
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| 23120. |
If the charge in a capacitor is 4C and the energy stored in it is 4J, find the value of capacitance.(a) 2F(b) 4F(c) 8F(d) 16F |
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Answer» Correct choice is (a) 2F To explain: The expression for finding the value of energy is: U=Q^2/2C. Substituting the values of U and Q, we get C=2F. |
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| 23121. |
If the charge in a capacitor is 4C and the energy stored in it is 4J, calculate the voltage across its plates.(a) 2V(b) 4V(c) 8V(d) 16V |
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Answer» Correct option is (a) 2V The best I can explain: The expression for finding the value of energy is: U=Q^2/2C. Substituting the values of U and Q, we get C=2F. V=Q/C, hence V=4/2=2V. |
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| 23122. |
Three capacitors having a capacitance equal to 2F, 4F and 6F are connected in parallel. Calculate the effective parallel.(a) 10F(b) 11F(c) 12F(d) 13F |
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Answer» Right answer is (c) 12F Easiest explanation: When capacitors are connected in parallel, the total capacitance is equal to the sum of the capacitance of each of the capacitors. Hence Ctotal = C1+C2+C3 = 2+4+6 = 12F. |
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| 23123. |
In which of the following cases, the moment of inertial is greater than 0.005 kg `-m^(2)`A. a disc of mass 0.3 kg, radius 0.2 m about its diameter.B. a cylinder of mass 0.2 kg and radius 0.3 m about its axis.C. a sphere of mass 0.1 kg radius 0.2 m about it tangent.D. a rod of mass 0.2 kg and length 0.3m about it end. |
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Answer» Correct Answer - BCD `I_(1)=1/4 mr^(2)=1/4xx0.3xx(0.2)^(2)=0.003 kg -m^(2)` `I_(2)=1/2 xx0.2xx(0.3)^(2)=0.009 kg -m^(2)` `I_(3)=2/5 xx0.1xx(0.2)^(2)+0.1xx(0.2)^(2)` `I_(4)=1/3 xx0.2xx(0.3)^(2)` `=0.2xx0.3xx0.03 =0.006 kg m^(2)` |
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| 23124. |
A ball tied to a rope making an angle `30^(@)` with the horizontal is held so that the rope is just If the ball is released, calculate the heat generated in joule when it crosses `30^(@)` down the horizontal (dotted)Given `m=Kg,L=2m,g=10m//s^(2)`. |
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Answer» The speed just after jerking `v=sqrt(2gL) cos 30^(@)=sqrt((3gL)/(2))` `therefore` heat=10 sec in kinetic energy `=(1)/(2)m(2gL-(3gL)/(2))` `=(mgL)/(4)=5J` |
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| 23125. |
An electron moves on a straight line path XY as shown in the figure. The coil abed is adjacent to the path of the electron. What will be the direction of current, if any, induced in the coil?(a) The current will reverse its direction as the electron goes past the coil(b) No current will be induced (c) abcd (d) adcb |
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Answer» (a) The current will reverse its direction as the electron goes past the coil |
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| 23126. |
The following graph shows current versus voltage values of some unknown conductor. What is the resistance of this conductor?(a) 2 ohm (b) 4 ohm (c) 8 ohm (d) 1 ohm |
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Answer» Correct answer is (a) 2 ohm |
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| 23127. |
Two points A and B are maintained at a potential of 7 V and -4 V respectively. The work done in moving 50 electrons from A to B is ……(a) 80 x 10-17 J (b) -8.80 x 10 -17J (c) 4.40 x 10 -17J (d) 5.80 x 10 -17J |
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Answer» (a) 80 x 10-17 J |
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| 23128. |
The dimension of \(\frac{1}{μ_0ε_0}\) is ........(a) [L T-1 ] (b) [L2 T-2 ] (c) [L-1 T] (d) [L-2 T2] |
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Answer» Correct answer is (b) [L2 T-2 ] |
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| 23129. |
Give the uses of Foucault current. |
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Answer» Though the production of eddy current is undesirable in some cases, it is useful in some other cases. A few of them are (1) Induction stove : Induction stove is used to cook the food quickly and safely with less energy consumption. Below the cooking zone, there is a tightly wound coil of insulated wire. The cooking pan made of suitable material, is placed over the cooking zone. When the stove is switched on, an alternating current flowing in the coil produces high frequency alternating magnetic field which induces very strong eddy currents in the cooking pan. The eddy currents in the pan produce so much of heat due to Joule heating which is used to cook the food. (2) Eddy current brake : This eddy current braking system is generally used in high speed trains and roller coasters. Strong electromagnets are fixed just above the rails. To stop the train, electromagnets are switched on. The magnetic field of these magnets induces eddy currents in the rails which oppose or resist the movement of the train. This is Eddy current linear brake. In some cases, the circular disc, connected to the wheel of the train through a common shaft, is made to rotate in between the poles of an electromagnet. When there is a relative motion between the disc and the magnet, eddy currents are induced in the disc which stop the train. This is Eddy current circular brake. (3) Eddy current testing : It is one of the simple nondestructive testing methods to find defects like surface cracks and air bubbles present in a specimen. A coil of insulated wire is given an alternating electric current so that it produces an alternating magnetic field. When this coil is brought near the test surface, eddy current is induced in the test surface. The presence of defects causes the change in phase and amplitude of the eddy current that can be detected by some other means. In this way, the defects present in the specimen are identified. (4) Electro magnetic damping : The armature of the galvanometer coil is wound on a soft iron cylinder. Once the armature is deflected, the relative motion between the soft iron cylinder and the radial magnetic field induces eddy current in the cylinder. The damping force due to the flow of eddy current brings the armature to rest immediately and then galvanometer shows a steady deflection. This is called electromagnetic damping. |
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| 23130. |
The speed of light in an isotropic medium depends on, (a) its intensity (b) its wavelength (c) the nature of propagation (d) the motion of the source w.r.to medium |
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Answer» Correct answer is (b) its wavelength |
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| 23131. |
In a series resonant RLC circuit, the voltage across 100Ω resistor is 40 V. The resonant frequency co is 250 rad/s. If the value of C is 4 pF, then the voltage across L is………(a) 600 V (b) 4000 V (c) 400 V (d) 1 V |
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Answer» Correct answer is (c) 400 V |
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| 23132. |
A dielectric slab of area `A` and thickness `d` is inderted between then plates of a capaitor of area `2A` with constant speed `upsilon` as shown in. Dustance between the plates is (d). . The capacitor is connected to a battery of emf `E`. The current in the ciruit varies with time as.A. B. C. D. |
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Answer» Correct Answer - D `C(t)=(epsi_(0)A)/(d)=K((vtxxb)epsi_(0))/(d)+((l-vt)bepsi_(0))/(d)` `Q(t)=CV=(Kvbepsi_(0))/(d)t+(bepsi_(0)l)/(d)-(bepsi_(0)vt)/(d)` `I=(dq)/(dt)=(Kvbepsi_(0))/(d)-(bepsi_(0)V)/(d)` `I=((K-I)vbepsi_(0))/(d)=` const |
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| 23133. |
5 men each of mass 100 kg are travelling in different cars as shown. Choose the correct alternative(s) A. pseudo force on A as seen by B will be 500NB. pseudo force on C as seen by B will be `500sqrt(2)N`.C. pseudo force on D as seen by B will be 1000ND. pseudo force on B as seen by E will be 1000N |
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Answer» Correct Answer - A `vecF_("pseudo")=` mass of object xx acceleration of observer. In opposite direction. |
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| 23134. |
a liquid column of height 80 cm at 0oc |
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Answer» So they have same mass, that means they will have same volume at same temperature. Now Suppose A cm2 is the area of cross section of the pipe, so volume at 0oC is |
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| 23135. |
A wedge as shown in figure has a rough curved surface of coefficient of kinetic friction `(1)/sqrt(3)` whose shape can be given by equation `y=x^(2)`, where the horizontal direction is x-axis, vertical direction as y axis and the end of surface O as origin and x `&` y are measured in meter. A small block is released, from a certain point on the surface. The maximum height of the point from where block should be released so that it does not slip. A. `(1)/(4)m`B. `(1)/(6)m`C. `(1)/(12)m`D. `(1)/(16)m` |
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Answer» Correct Answer - C For no slipping `tantheta=mu=(dy)/(dx)=2x=(1)/sqrt(3)` `rArrx=(1)/(2sqrt(3))rArry=x^(2)=(1)/(12)m` |
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| 23136. |
The focal length of a convex mirror is obtained by using a convex lens The following observations are recorded during theexperiment . `{:("objectopsition",,=5cm),("lens",,=35.4cm),("Image",,=93.8cm),("Mirror",,=63.3cm),("Bencherror",,=-0.1cm):}` then the focal length of mirror will be .A. `7.5`B. `8.4cm`C. `15.3cm`D. None of these |
| Answer» Correct Answer - C | |
| 23137. |
If a tunnig fork of frequency `(f_(0)) 340 Hz` and tolerance `pm 1%` is used in resonance coulmn method `[v=2f_(0)(l_(2)-l_(1))]`, the first and the second resonance are measured at `l_(1)=24.0 cm` and `l_(2)=74.0 cm`. Find max. permissible error in speed of sound. |
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Answer» `v =2f_(0) (l_(2) -l_(2))` `rArr ((Deltav)/(v))_(max)=(Deltaf_(0))/(f_(0))+(Deltal_(1)+Deltal_(2))/(l_(2)-l_(1))=(1)/(100)+(0.1+0.1)/(74-24)=1.4%` . |
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| 23138. |
For sperical mirros graph plotted between `- (1)/(V)` and `-(1)/(u)is` .A. stright line with slope 1B. straight line with slope -1C. ParabolaD. none |
| Answer» Correct Answer - B | |
| 23139. |
A thin copper wire of length L increase in length by 2 % when heated from `T_(1)` to `T_(2)`. If a copper cube having side 10 L is heated from `T_(1)` to `T_(2)` when will be the percentage change in (i) area of one face of the cube (ii) volume of the cube |
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Answer» (i) Area A=10Lxx10L=100`L^(2)` percentage change in area `=(DeltaA)/(A)xx100=2xx(DeltaL)/(L)xx100=2xx=4%` `(therefore(DeltaA)/(A)=(Delta100)/(100)+2(DeltaL)/(L)=0+2(DeltaL)/(L)=2(DeltaL)/(L))` Note:- Constants do not have any error in them. (ii) Volume `V=10Lxx10Lxx10L=1000 L^(3)` percentage change in volume `=(DeltaV)/(V)xx100=3(DeltaL)/(L)=3xx2%=6%` |
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| 23140. |
45. If \( { }^{7} P_{n} \div{ }^{7} P_{n-3}=60 \) the value of \( n \) is(a) 8(b) 4(c) 5(d) 2 |
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Answer» \(^7P_n \div\,^7P_{n-3} = 60\) ⇒ \(\frac{7!}{(7 -n)!}\div \frac{7!}{(7 - (n-3))!} = 60\) ⇒ \(\frac{(10- n)!}{(7 - n)! }=60\) ⇒ \(\frac{(10 - n)(9 -n)(8 -n)(7 -n)!}{(7 - n)!}= 60\) ⇒ (10 - n) (9 - n) (8 - n) = 5 x 4 x 3 ⇒ (10 - n) (9 - n) (8 - n) = (10 - 5) (9 - 5) (8 - 5) ∴ n = 5 |
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| 23141. |
Number of ways to arrange 6 papers is |
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Answer» Number of ways to arrange 6 papers = 6! = 720. |
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| 23142. |
State the most important use of Iron ore. |
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Answer» It is used to extract steel, which in turn is used as raw materials in various industries. IRON ORE Iron ores are rocks and minerals from which metallic iron can be economically extracted. The ores are usually rich in iron oxides and vary in color from dark grey, bright yellow, or deep purple to rusty red. The iron is usually found in the form of magnetite, hematite, goethite, limonite or siderite. USES OF IRON ORE The primary use of iron ore (98%) is to make steel. The remaining 2% is used in applications such as: powdered iron—for certain types of steels, magnets, auto parts and catalysts. radioactive iron (iron 59)—for medicine and as a tracer element in biochemical and metallurgical research. |
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| 23143. |
What are elastic collisions? |
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Answer» In physics, an elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same. In an ideal, perfectly elastic collision, there is no net conversion of kinetic energy into other forms such as heat, noise, or potential energy. |
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| 23144. |
The correct figure representing isothermal and adiabatic compression of an ideal gas from the same initial state is:A. B. C. D. |
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Answer» Correct Answer - C Slope of adiabatic curve is greater than isothermal curve. |
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| 23145. |
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume becomes 60 L. Calculate entropy change for the process `(C_(p.m)=30.96 J "mole"^(-1) K^(-1))`A. `80.2 J.k^(-1) "mol"^(-1)`B. `62.42 J.k^(-1) "mol"^(-1)`C. `120xx10^2 J.k^(-1) "mol"^(-1)`D. `27.22 J.k^(-1) "mol"^(-1)` |
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Answer» Correct Answer - D `(P_1V_1)/T_1=(P_2V_2)/T_2` `T_2/T_1=6/3` `DeltaS=2.303xxn{C_p"log"_10T_2/T_1+R"log"_10P_1/P_2}` `DeltaS=2.303xx1{30.96"log"_10 6/3 +R"log"_10 20/10}` `DeltaS=27.22 J.K^(-)1 mol^(-)1` |
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| 23146. |
Which among the following is the name of the thermodynamic system in which the temperature changes without supplying heat?1. Isothermal process2. Adiabatic process3. Isochoric process4. Quasi-static process |
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Answer» The correct answer is Adiabatic process.
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| 23147. |
Consider the following data : `Delta_(f)H^(@)(N_(2)H_(4),l)=50kJ//mol,Delta_(f)H^(@)(NH_(3),g)=-46kJ//mol` `B.E(N-H)=393" kJ//mol and B.E."(H-H)=436kJ//mol` `Delta_("vap")H(N_(2)H_(4),l)=18kJ//mol` The N-N bond energy in `N_(2)H_(4)` is :A. 190kJ/molB. `-190kJ//"mol"`C. 95 kJ/molD. `-95 kJ//"mol"` |
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Answer» Correct Answer - A `1/2N_2(g)+3/2H_2(g)toNH_3(g)` Let B.E. of N = N is x `-46=x/2+3/2xx436-3xx393impliesx=958` `N_2H_4(l) to N_2(g)+2H_2(g)` `Delta_rH=-50` kJ/mole `implies Delta_rH=[underset(+B.E.(N-N))overset(Delta_(vap)H(N_2H_4,l))(+4xxB.E.(N-H))]-[overset(B.E.(N-=N))(+2B.E.(H-H))]` `-50=(18+4xx393+y)-(958+2xx436)` `-50=(1590+y)-(1830)` B.E.(N-N)or y=190 kJ/mole |
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| 23148. |
In the reaction `COCl_2(g)hArr CO(g)+Cl_2(g)` at `550^@C`, when the initial pressure of CO & `Cl_2` are 250 and 280 mm of Hg respectively. The equilibrium pressure is found to be 380 mm of Hg.Calculate the degree of dissociation of `COCl_2` at 1 atm.What will be the extent of dissociation, when `N_2` at a pressure of 0.4 atm is present and the total pressure is 1 atm.A. 0.32 and no changeB. 0.32 and 0.4C. 0.4 and 0.3D. In presence of `N_2` dissociation cannot take place |
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Answer» Correct Answer - B `{:(,CoCl_2(g)hArr,CO(g)+Cl_2(g)),("Initial pressure",-,250" "280),("Equilibrium pressure",x,250-x " " 280-x):}` x+250-x+280-x=380 x=150 `K_P=0.114` `K_P=(P_(CO).P_(Cl_2))/(P_(COCl_2))implies K_P=(alpha^2 . P)/(1-alpha^2) implies 0.114 =(alpha^2 . 1)/(1-alpha^2)` hence `alpha=0.32 " " alpha=0.32` In presence of `N_2` (constant pressure process) `K_P=(alpha^2xx0.6)/(1-alpha^2)implies alpha=sqrt(0.114/0.714)implies alpha=0.4` `alpha` increases from 0.32 to 0.4 |
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| 23149. |
At 1000 K water vapour at 1 atm, has been found to be dissociated into `H_2 and O_2` to the extent of `3xx10^(-5)%`. Calculate the free energy decrease of the system, assuming ideal behaviour.A. `-DeltaG=90,060` calB. `-DeltaG=20` calC. `-DeltaG=480` calD. `-DeltaG=-45760` cal |
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Answer» Correct Answer - D `{:(H_2O(g),hArr,H_2+,1/2O_2),(1-alpha," " ,alpha,alpha//2):}` `K_P=alpha/(1-alpha)((alpha/2P)/(1+alpha/2))^(1//2)=11.62xx10^(-)11("atm")^(1//2)implies DeltaG^(@)= -RT "In" K_P`= -45.76 kcal |
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| 23150. |
Mitochondria is the organ for ______(a) Cellular respiration(b) Cellular digestion(c) Cellular death(d) Cellular motility |
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Answer» Right answer is (a) Cellular respiration To explain: Mitochondria is a bean shaped organ in the cell cytoplasm. Its major role is cellular respiration. It utilizes oxygen and carbohydrate to release carbon dioxide and energy in the form of ATP. Cellular respiratory processes such as Kreb’s cycle and oxidative phosphorylation takes place in mitochondria. |
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