This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 23051. |
What is the commercial unit of electric energy? Convert it into joules. |
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Answer» Kilowatt hour – commercial unit of electrical energy. |
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| 23052. |
Out of 60 W and 40 W lamps which one has higher electrical resistance when in use? |
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Answer» For the same applied voltage P & \(\frac{1}{R}\) i.e., less the same power of electrical device higher it is electrical resistance. |
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| 23053. |
Write two points of difference between electric energy and electric power. |
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Answer» The work done or energy supplied by the source in maintaining the flow of electric current is called electrical energy. It appears in the from of heat given by (i) It is equal to be product of power and time E = P × t (ii) It SI unit is joule (J) Electric power: |
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| 23054. |
What is meant by electric current? Name and define its SI unit. In a conductor electrons are flowing from B to A. What is the direction of conventional current? Give justification for your answer. |
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Answer» A steady current of 1 ampere flows through a conductor. Calculate the number of electrons that flows through any section of the conductor is 1 second (charge on electron 1.6 x 1019 Coulomb) Electric current: The amount of charge Q flowing through a particular area of cross section in unit time ‘t’ is called electric current, i.e., Electric current, I = Q/t One ampere of current is that current which flow when one coulomb of electric charge flowing through a particular area of cross section of the conductor is one second, i.e, 1A = 1 CS-1 The direction of conventional current is A to B, i.e., opposite to the direction of flow of electrons. In a metal, flow of electrons carrying negative charge constitutes the current. Direction of flow of electrons given the direction of electronic current by convention, the direction of flow of positive charge is taken as the direction of conventional current charge \(\frac{1C}{1.6\times 10^{-19}C}\) = \(\frac{10^{19}}{1.6}\) = 6.25 x 1018 electrons |
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| 23055. |
An isolated particle of mass `m` is moving in horizontal plane` xy` along the `x`-axis, at a certain height above the ground. It suddenly explodes into two fragment of masses `m//4` and `3m//4`. An instant later, the smaller fragment is at `y=+15` cm. The larger fragment at this instant is atA. `-5 cm `B. `-20 cm `C. `+5cm `D. `(-45)/4cm` |
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Answer» Correct Answer - 1 The particle moving along x-axis, So, centre of mass will not move along y direction. `y_(cm)=0` `=(m_(1)y_(1)+m_(2)y_(2))/(m_(1)+m_(2)) =((m//4).15+(3m//4)y)/m` y=-5 cm |
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| 23056. |
The outer surface of the cardboard center of a paper towel roll: A. is a possible Gaussian surface B. cannot be a Gaussian surface because it encloses no charge C. cannot be a Gaussian surface since it is an insulator D. cannot be a Gaussian surface because it is not a closed surface E. none of the above |
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Answer» D. cannot be a Gaussian surface because it is not a closed surface |
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| 23057. |
An electron moves from point i to point f, in the direction of a uniform electric field. During this displacement:A. the work done by the field is positive and the potential energy of the electron-field system increases B. the work done by the field is negative and the potential energy of the electron-field system increases C. the work done by the field is positive and the potential energy of the electron-field system decreases D. the work done by the field is negative and the potential energy of the electron-field system decreases E. the work done by the field is positive and the potential energy of the electron-field system does not change |
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Answer» B. the work done by the field is negative and the potential energy of the electron-field system increases |
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| 23058. |
Correct graph of `y-1=x^(2)` is -A. B. C. D. |
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Answer» Correct Answer - 1 At y=1, x=0 |
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| 23059. |
`int_(2)^(5)(1)/((2+3x))dx` is -A. `(15)/(2)`B. `(7)/(5)`C. `(1)/(3)l"n"(17)/(8)`D. `l"n"(17)/(8)` |
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Answer» Correct Answer - 3 `[(log(2+3x))/(3)]_(2)^(5)` `(1)/(3)(log17-log8)=(1)/(3)l n(17)/(8)` |
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| 23060. |
Give the characteristics of image formed by a plane mirror. |
Answer»
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| 23061. |
If the collector resistor decreases to zero in a basebiased circuit, the load line will become a. Horizontal b. Vertical c. Useless d. Fla |
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Answer» The correct answer is: b. Vertical |
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| 23062. |
If the base supply voltage is disconnected, the collector-emitter voltage will equal a. 0 V b. 6 V c. 10.5 V d. Collector supply voltage |
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Answer» (d) Collector supply voltage |
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| 23063. |
If a transistor operates at the middle of the load line, an increase in the base resistance will move the Q point a. Down b. Up c. Nowhere d. Off the load line |
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Answer» The correct answer is: (a) Down |
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| 23064. |
Three different Q points are shown on a load line. The upper Q point represents the a. Minimum current gain b. Intermediate current gain c. Maximum current gain d. Cutoff point |
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Answer» (c) Maximum current gain |
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| 23065. |
If the collector resistor is open, the ac input voltage will a. Decrease b. Increase c. Remain the same d. Equal approximately zero |
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Answer» (a) Decrease |
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| 23066. |
If the emitter resistor is open, the ac input voltage will a. Decrease b. Increase c. Remain the same d. Equal zero |
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Answer» (b) Increase |
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| 23067. |
If any capacitor is open, the ac output voltage will a. Decrease b. Increase c. Remain the same d. Equal zero |
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Answer» (a) Decrease |
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| 23068. |
An open resistor has a. Infinite current through it b. Zero voltage across it c. Infinite voltage across it d. Zero current through it |
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Answer» (d) Zero current through it |
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| 23069. |
If the bypass capacitor is open, the ac input voltage will a. Decrease b. Increase c. Remain the same d. Equal zero |
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Answer» (b) Increase |
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| 23070. |
If the output coupling capacitor is open, the ac input voltage will a. Decrease b. Increase c. Remain the same d. Equal zero |
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Answer» (c) Remain the same |
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| 23071. |
If the load resistance is open, the ac output voltage will a. Decrease b. Increase c. Remain the same d. Equal zero |
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Answer» (b) Increase |
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| 23072. |
If the input coupling capacitor is open, the ac input voltage will a. Decrease b. Increase c. Remain the same d. Equal zero |
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Answer» (d) Equal zero |
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| 23073. |
A shorted resistor has a. Infinite current through it b. Zero voltage across it c. Infinite voltage across it d. Zero current through it |
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Answer» (b) Zero voltage across it |
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| 23074. |
A VCVS amplifier has no output voltage. A possible trouble is a. Shorted load resistor b. Open feedback resistor c. Excessive input voltage d. Open load resistor |
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Answer» (a) Shorted load resistor |
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| 23075. |
Negative feedback reduces the a. Feedback fraction b. Distortion c. Input offset voltage d. Loop gain |
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Answer» (b) Distortion |
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| 23076. |
The positive clamper adds a. A positive dc voltage to the input b. A negative dc voltage to the input c. An ac signal to the output d. A trip point to the input |
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Answer» (a) A positive dc voltage to the input |
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| 23077. |
A first-order stage cannot have a a. Butterworth response b. Chebyshev response c. Maximally-flat passband d. Rolloff rate of 20 dB per decade |
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Answer» (b) Chebyshev response |
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| 23078. |
If GBW is limited, the Q of the stage will a. Remain the same b. Double c. Decrease d. Increase |
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Answer» (d) Increase |
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| 23079. |
To correct for limited GBW, a designer may use a. A constant time delay b. Predistortion c. Linear phase shift d. A rippled passband |
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Answer» (b) Predistortion |
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| 23080. |
To detect when the input is greater than a particular value, use a a. Comparator b. Clamper c. Limiter d. Relaxation oscillator |
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Answer» (a) Comparator |
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| 23081. |
A window comparator a. Has only one usable threshold b. Uses hysteresis to speed up response c. Clamps the input positively d. Detects an input voltage between two limits |
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Answer» (d) Detects an input voltage between two limits |
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| 23082. |
VDB needs a. Only three resistors b. Only one supply c. Precision resistors d. More resistors to work better |
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Answer» (b) Only one supply |
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| 23083. |
The voltage that starts an oscillator is caused by a. Ripple from the power supply b. Noise voltage in resistors c. The input signal from a generator d. Positive feedback |
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Answer» (b) Noise voltage in resistors |
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| 23084. |
A lead circuit has a phase angle that is a. Between 0 and +90 degrees b. Greater than 90 degrees c. Between 0 and -90 degrees d. The same as the input voltage |
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Answer» (a) Between 0 and +90 degrees |
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| 23085. |
Initially, the loop gain of a Wien-bridge oscillator is a. 0 b. 1 c. Low d. High |
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Answer» The answer is: (d) High |
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| 23086. |
A Wien-bridge oscillator uses a. Positive feedback b. Negative feedback c. Both types of feedback d. An LC tank circuit |
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Answer» (c) Both types of feedback |
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| 23087. |
The Wien-bridge oscillator is useful a. At low frequencies b. At high frequencies c. With LC tank circuits d. At small input signals |
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Answer» (a) At low frequencies |
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| 23088. |
The common-mode rejection ratio is a. Very low b. Often expressed in decibels c. Equal to the voltage gain d. Equal to the common-mode voltage gain |
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Answer» (b) Often expressed in decibels |
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| 23089. |
The input offset current is usually a. Less than the input bias current b. Equal to zero c. Less than the input offset voltage d. Unimportant when a base resistor is used |
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Answer» (a) Less than the input bias current |
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| 23090. |
With Sallen-Key high-pass filters, the pole frequency must be a. Added to the K values b. Subtracted from the K values c. Multiplied by the K values d. Divided by the K values |
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Answer» (d) Divided by the K values |
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| 23091. |
When we trim a resistor, we are a. Making a fine adjustment b. Reducing its value c. Increasing its value d. Making a coarse adjustment |
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Answer» (a) Making a fine adjustment |
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| 23092. |
If an op amp has only a positive supply voltage, its output cannot a. Be negative b. Be zero c. Equal the supply voltage d. Be ac coupled |
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Answer» (a) Be negative |
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| 23093. |
A D/A converter with four inputs has a. Two outputs b. Four outputs c. Eight outputs d. Sixteen outputs |
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Answer» (d) Sixteen outputs |
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| 23094. |
When a JFET is used in an AGC circuit, it acts like a a. Switch b. Voltage-controlled current source c. Voltage-controlled resistance d. Capacitance |
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Answer» (c) Voltage-controlled resistance |
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| 23095. |
Link coupling refers to a. Capacitive coupling b. Transformer coupling c. Resistive coupling d. Power coupling |
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Answer» (b) Transformer coupling |
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| 23096. |
An op amp with a rail-to-rail output a. Has a current-boosted output b. Can swing all the way to either supply voltage c. Has a high output impedance d. Cannot be less than 0 V. |
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Answer» (b) Can swing all the way to either supply voltage |
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| 23097. |
The Q of a Sallen-Key second-order stage depends on the a. Voltage gain b. Center frequency c. Bandwidth d. GBW of the op amp |
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Answer» (a) Voltage gain |
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| 23098. |
The Hartley oscillator uses a. Negative feedback b. Two inductors c. A tungsten lamp d. A tickler coil |
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Answer» (b) Two inductors |
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| 23099. |
To vary the frequency of an LC oscillator, you can vary a. One resistor b. Two resistors c. Three resistors d. One capacitor |
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Answer» (d) One capacitor |
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| 23100. |
The material with the piezoelectric effect is a. Quartz b. Rochelle salts c. Tourmaline d. All the above |
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Answer» (d) All the above |
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