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`int_(2)^(5)(1)/((2+3x))dx` is -A. `(15)/(2)`B. `(7)/(5)`C. `(1)/(3)l"n"(17)/(8)`D. `l"n"(17)/(8)` |
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Answer» Correct Answer - 3 `[(log(2+3x))/(3)]_(2)^(5)` `(1)/(3)(log17-log8)=(1)/(3)l n(17)/(8)` |
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