1.

a liquid column of height 80 cm at 0oc

Answer»

So they have same mass, that means they will have same volume at same temperature. Now Suppose A cm2 is the area of cross section of the pipe, so volume at 0oC is
80×A 80×A cm3
and at 100C is
80.4×A cm3 80.4×A cm3
So change in volume is
dv=80.4×A−80×A=0.4×Adv=80.4×A-80×A=0.4×A
Now if γ is the volume expansion coefficient then we have
γ=dv/vdT=0.4×A/(80×A)100=5×10−5



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