Saved Bookmarks
| 1. |
Starting from rest a 10 kg object is acted upon by only one force as indicated in figure. Then the total work done by the force in 5 seconds is A. 90 JB. 320 JC. 245 JD. 490 J |
|
Answer» Correct Answer - B Change in velocity `=("area under F-T graph")/("mass")` `=(120+(-40))/(10)=8 m//s` `W_(f)=DeltaK.E = (1)/(2)(10)8_(2) = 320 J` |
|