1.

Starting from rest a 10 kg object is acted upon by only one force as indicated in figure. Then the total work done by the force in 5 seconds is A. 90 JB. 320 JC. 245 JD. 490 J

Answer» Correct Answer - B
Change in velocity `=("area under F-T graph")/("mass")`
`=(120+(-40))/(10)=8 m//s`
`W_(f)=DeltaK.E = (1)/(2)(10)8_(2) = 320 J`


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