This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1651. |
Explain (in one or two lines) the function of the followings:(a) Promoter(b) tRNA(c) Exons |
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Answer» (a) Promoter |
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| 1652. |
Why is the Human Genome project called a mega project? |
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Answer» Human genome project was considered to be a mega project because it had a specific goal to sequence every base pair present in the human genome. It took around 13 years for its completion and got accomplished in year 2006. It was a large scale project, which aimed at developing new technology and generating new information in the field of genomic studies. As a result of it, several new areas and avenues have opened up in the field of genetics, biotechnology, and medical sciences. It provided clues regarding the understanding of human biology. |
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| 1653. |
What is DNA fingerprinting? Mention its application. |
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Answer» DNA fingerprinting is a technique used to identify and analyse the variations in various individuals at the level of DNA. It is based on variability and polymorphism in DNA sequences.
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| 1654. |
Differentiate between Nepal's movement and Bolivia's popular struggle. |
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Answer» The difference between popular struggles in Nepal and Bolivia are as follows : (i) The movement in Nepal was to establish democracy, while the struggle in Bolivia involved claims on an elected democratic govt. (ii) 'The popular struggle in Bolivia was about one specific policy i.e., privatisation of water while the struggle in Nepal was the foundation of the country's politics. (iii) The protest in Nepal was led by a political party, (SPA) while in Bolivia it was led by a pressure group (FEDECOR). (iv) The impact of these struggles was at different levels. The impact of the struggle in Nepal was for the entire world, while in Bolivia it was only for the citizens of the country. |
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| 1655. |
Match the pairs correctly:Section ‘A’Section ‘B’(1) Establishment of League of Nations(1) General Assembly(2) Establishment of United Nations (U.N.)(2) Security Council(3) Largest organ of United Nations (U.N.)(3) 1921(4) The most important organ of United Nations (U.N.)(4) 1945(5) 1920 |
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Answer» (1 – 5), (2 – 4), (3 – 1), (4 – 2). |
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| 1656. |
Consider the following statements with reference to Goods and Services Tax Appellate Tribunal: 1. It is the forum of the second appeal in GST laws. 2. The tribunal will be situated in Mumbai. Which of the above statements is/are correct ?A. 1 OnlyB. 2 OnlyC. Both 1 and 2D. Neither 1 nor 2 |
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Answer» Correct Answer - A National Bench of the Goods and Services Tax Appellate Tribunal will be situated in New Delhi. |
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| 1657. |
A uniform chain has a mass m and length l . It is held on a frictionless table with one - sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is :A. `mgl/72`B. `(mgl)/(36)`C. `(mgl)/(12)`D. `(mgl)/(6)` |
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Answer» [1] Weight of overhanging part of chain `=(mg)/(6)` The weight acts at the centre of gravity of the overhanging part, i.e., `(l)/(12)`below the surface of table . Gain in potential energy `=(mg)/(6)xx(l)/(12)=(mgl)/(72)` ` :.` Work done = gain in potential energy `=(mgl)/(72)` |
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| 1658. |
Complaints to Magistrates contained in1. Chapter XIII of Criminal Procedure Code2. Chapter XVI of Criminal Procedure Code3. Chapter XV of Criminal Procedure Code4. Chapter XIV of Criminal Procedure Code |
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Answer» Correct Answer - Option 3 : Chapter XV of Criminal Procedure Code The correct answer is Chapter XV of the Criminal Procedure Code.
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| 1659. |
When was the Universal Declaration of Human Rights adopted by the United Nations?1. 4 April, 19492. 24 October, 19453. 10 December, 19484. 10 January, 1920 |
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Answer» Correct Answer - Option 3 : 10 December, 1948 The correct answer is 10 December 1948.
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| 1660. |
Write a note on vaccination and immunisation. |
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Answer» Vaccination:- Antibody provoding agents aretermed vaccines. The protect human and domestic animals against infections from viruses and vacteria. The process of vaccins to inter the body of living brings are known as vaccination. Toxoid killed vaccine, altenuated living vaccine, antigens isolated from infectius persons and antibodies and different kinds of vaccinus. Edward Jenner father of Emmunology prepared the small pox vaccine in 1906. Immunisation:- The system of animal body which protects it from various infectious agents and disease in termied imunisition. Our body has allready capecity to immunity. |
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| 1661. |
______ discovered the presence of neutrons inside an atom.1. E. Goldstein2. J. Chadwick3. J. J. Thomson4. Niels Bohr |
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Answer» Correct Answer - Option 2 : J. Chadwick Neutrons:
Thus, J. Chadwick discovered the presence of neutrons inside an atom.
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| 1662. |
Why is ICI more reactive than `I_2`? |
| Answer» `I-Cl` bond is weaker than `I-I` bond and hence `Icl` is more reactive than `I_2`. | |
| 1663. |
Give the reason for bleaching action of `Cl_2`. |
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Answer» In aqueous solution or in presence of moisture, `Cl_2` liberates nascent oxygen. `Cl_2+H_2Oto2HCl+[O]` Nascent oxygen thus produced brings about the oxidation of coloured substances present in vegetable and organic matter to colourless substances. Coloured substance `+[O]to` colourless substance. |
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| 1664. |
Why helium is used an diluent for oxygen in modern diving apparatus ? |
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Answer» He is used as a diluent for oxygen in modern diving apparatus because of its very low solubility in blood. |
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| 1665. |
Why should one prefer to use fresh fruits instead of frozen fruits? |
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Answer» Two advantages of using fresh fruits
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| 1666. |
What is double circulation? How blood circulation is done in fishes having 2- chambered heart? |
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Answer» The heart is a key organ for blood circulation and double circulation provides an effective way of circulation. In double circulation, blood follows two routes- one for oxygenated blood and other for deoxygenated blood. The blood vessels responsible for carrying out double circulation: • Pulmonary artery: it takes deoxygenated blood to the lungs. • Aorta: it carries oxygenated blood to body tissues • Pulmonary vein: it carries oxygenated blood • Vena cava: it takes deoxygenated blood. Fish have a single circuit for blood flow and a two chambered heart that has only a single atrium and a single ventricle. Because blood leaves the gills and immediately circulates to the rest of the body, the heart does not require additional chambers. The blood then arrives back at the atrium. This is called systemic circulation. |
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| 1667. |
Which of the following immune responses is responsible for rejection of kidney graft? (1) Auto-immune response (2) Humoral immune response (3) Inflammatory immune response (4) Cell-mediated immune response |
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Answer» Correct option: (4) Cell-mediated immune response Explanation: The body is able to differentiate self and nonself and the cell-mediated response is responsible for graft rejection. |
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| 1668. |
The molality of 15 % by wt solution of `H_2SO_4` isA. 1.8B. 2.2C. 1.2D. 2.8 |
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Answer» Correct Answer - A `m=(w_(A)xx1000)/(M_(A)xxw_(B))` `=(15xx1000)/(98xx85)=1.8` |
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| 1669. |
6gm of silver salt of tribasic acid gives 4.32 gm silver on strong heating. The molar mass of acid is:A. 126gmB. 129gmC. 123gmD. 252gm |
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Answer» `H_(3)Aoverset(AgNO_(3))rarrAg_(3)Aoverset(Delta)rarrAgdownarrow` `POAc "on" Ag: 3xxn_(Ag_(3)A)=n_(Ag)` `3xx(6)/(M.Wt_("Salt"))=(4.32)/(108)` `M.Wt_("salt")=(3xx6xx108)/(4.32)=450` M.Wt. acid `=450-108xx3+3xx1` M.Wt. acid=`450-107xx3=129` |
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| 1670. |
Identify the unsymmetrical bidentate ligands from the following?A. DMGB. GlyC. oxD. en |
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Answer» Correct Answer - B |
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| 1671. |
For a chemical reaction R ----> P, the variation in the concentration [R] vs time [t] plot is given as:(i) Predict the order of the reaction. (ii) What is the slope of the curve? |
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Answer» (i) Zero order reaction (ii) Slope = -k = \(\frac{d[R]}{dt}\) |
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| 1672. |
Assertion `:-` `SF_(6)` cannot be hydrolysed `SP_(4)` can be Reason `:-` Six `F` atoms in `SF_(6)` prevent the attack of `H_(2)O` on sulphur atom of `SF_(6)`A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - A | |
| 1673. |
Arrange the following in the increasing order of the properties stated against them. (a) (i)`NH_(3)` , (ii)`PH_(3)`, (iii)`AsH_(3)` , (iv)`SbH_(3)`-boiling point. (b)(i)`Bi^(3+)` ,(ii)`Sb^(3+)` , (iii)`As^(3+)`-stability of `+3` oxidation state. ( c)(i)`NH_(3)`, (ii)`PH_(3)` , (iii)`AsH_(3)` , (iv)`SbH_(3)` , (v)`BiH_(3)`-reducing character. |
| Answer» Volatile nature: `NH_(3)ltSbH_(3)ltAsH_(3)ltPH_(3)`. | |
| 1674. |
A gas absorbs a photon of `310nm` and emits three photons. If energy of emitted photons is in the raio `1:2:1` then select correct statement(s) :A. The wave length of emitted photons is in the ratio `1: 2:1`B. The wave length of emitted photons is in the ratio `2:1:2`C. The wave length of emitted photons is in the ratio `1240 nm`.D. The wavelength of least energatic photon is `1310 nm`. |
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Answer» Correct Answer - B::C `E_(1) = (12400)/(lambda_(1)) :. (E_(1))/(E_(2)) = (lambda_(1))/(lambda_(2)) = (1)/(2) rArr lambda_(1) = 2lambda_(2)` `E_(2) = (12400)/(lambda_(2))` `E = (12400)/(3100) = 2 ((12400)/(lambda_(1))) + (12400)/(lambda_(2))` `:. (12400)/(3100) = 2((12400)/(lambda_(1))) + ((12400)/(lambda_((1)/(2))))` `(12400)/(3100) = 4 ((12400)/(lambda_((1)/(2))))` `lambda_(1) = 4 xx 3100 Å` `= 12400Å` `= 1240 nm` |
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| 1675. |
A canteen requires 13 dozen bananas per day. How many bananas will it require for 9 weeks?(a) 728 (b) 9828(c) 1404 (d) 9882(e) None of these |
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Answer» (b) Requirement of bananas for 1 day in the canteen = 13 dozens Requirement of bananas for 9 weeks i.e. 63 days = 63 × 13 dozens = 63 × 13 × 12 = 9828. |
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| 1676. |
What is 768 times 859?(a) 656276 (b) 661248(c) 658176 (d) 659712(e) None of these |
| Answer» (d) Required product = 768 × 859 = 659712 | |
| 1677. |
Which isotope of hydrogen (a) does not contain neutron, (b) contains equal number of protons and neutrons, ( c) is radioactive. |
| Answer» (a) Protium, (b) deuterium, ( c) tritium. | |
| 1678. |
What is the product of the reaction between benzene and `H_(2)O_(2)`? |
| Answer» Correct Answer - Phenol | |
| 1679. |
The CO in a 20L sample of gas was converted to `CO_2` by passing the gas over iodine pentoxide heated to `150^@C`: `I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g)` The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M `Na_2S_2O_3`.The excess hypo was back titrated with 5 mL of 0.001 M `I_2` solution. What must be the milligrams of Co in 1 L of the original gas sample ?A. 0.35 mgB. 0.70 mgC. 0.07 mgD. 3.5 mg |
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Answer» Correct Answer - A meq of `l_2` liberated =10 x 0.011 x 1-5 x 0.001 x 2=0.1 Millimoles of CO=`0.1/2 xx5 =0.25` Weight of CO in 1L =`0.25/20xx28 =0.35 mg` |
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| 1680. |
The electrode potential `E_(Zn^(+2)//Zn) ` of a zinc electrode or `25^(@)C` with an aqueous solution of `0.1 M ZnSO_(4)` is `[E_((Zn^(+2)//Zn))=-0.76V]["assume"(2.3-3RT)/(F)=0.06at298K]`A. `+0.73V`B. `-0.79V`C. `-0.82V`D. `-0.70V` |
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Answer» Correct Answer - B `Zn^(+2)+2e^(-)toZn` `E_((Zn^(+2)//Zn))=E_((Zn^(+2)//Zn))^(@)` `-(2.303RT)/(2F)log.([Zn])/([Zn^(+2)])` `=-0.76-(0.06)/(2)log.(1)/([0.1])` `=-0.76-0.03=-0.79V` |
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| 1681. |
In a `p-n` junction diode having depletion layer of thickness `10^(-6)m`, the potential across it is `0.1V`. The electric field produced is |
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Answer» Correct Answer - C `E=(V)/(d)` |
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| 1682. |
A ray of light incident on a transparent block at an angle of incident `60^(@)`. If the refractive index of the block is `1.732`, the angle of deviation of the refracted ray isA. `15^(@)`B. `25^(@)`C. `30^(@)`D. `45^(@)` |
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Answer» Correct Answer - C `del=i-r`, ` mu=(sin i)/(sin r)`, `sqrt(3)=(sin60)/(sinr)` `r=30^(@)` , `del=60-30=30^(@)` |
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| 1683. |
A given quantity of a ideal gas occupies a volume of 100 litres at 100K when the pressure 2 atm. Its temperature is decreased to 50K and its pressure decreases to 1 atm. What is the new volume?A. 50 litreB. 100 litreC. 200 litreD. 25 litre |
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Answer» Correct Answer - B `P/T`=const. V does not change |
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| 1684. |
One mole of an ideal gas requires 207 J heat to raise the temperature by 10K When heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by 5K, then the heat required isA. 62 JB. 124 JC. 12.4 JD. 6.2 J |
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Answer» Correct Answer - 1 `207=C_(p)xx10` `DeltaQ=C_(v)xx5` `C_(v)=C_(p)-R =12.4` `DeltaQ=nQ DeltaT=62 J` `C_(p)=207` `C_(v)=20.7-8.3=12.4` `DeltaQ=1xx12.4 xx5` |
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| 1685. |
Explain briefly—(a) WWW(b) FAX |
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Answer» (a) WWW—It stands for world wide web. It is a collection of static and dynamic web pages containing information (text, pictures, viders, graphics etc) for sharing with others. (b) FAX—It stands for facsimile telegraphy. In this form of communication, electronic copy of a document is sent to distant places. The original written document is converted into trasmittable codes at the sending end. These codes are converted back into a copy of the original document at the receiving end. |
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| 1686. |
Calculate the moment of inertia of a uniform disc of mass \( 10 kg \) and radius \( 60 cm \) about an axis perpendicular to its length and passing through its centre. |
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Answer» Moment of inertia of a uniform disc about an axis perpendicular to its length = \(\frac{MR^2}{2}\) = \(\frac{10 * (0.6)^2}{2}\) = 1.8 kg.m2 |
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| 1687. |
Total uniform charge on a sphere of radius 2 cm is 10uc. The max electric field due to sphere is |
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Answer» Using Gauss law E. ds = \(\frac{q}{\varepsilon_0}\) E = \(\frac{q}{\varepsilon_0.ds}\) E = \(\frac{10\times10^{-6}}{8.85\times10^{-12}\times4\pi R^2}\) E = \(\frac{10\times10^{-6}}{8.85\times10^{-12}\times4\times3.14(0.02)^2}\) E = 227.6 x 106 N/C E = 227 MN/C |
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| 1688. |
Give any two properties of photon |
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Answer» The basic properties of photons are: (1) They have zero mass and zero rest energy. They only exist as the moving particles. (2)They have no electric charge. |
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| 1689. |
To protest against the Jalianwala Bagh massacre, who returned his title of 'knighthood' to British?1. Mahatma Gandhi2. Gopal Krishna Gokhale3. Ravindranath Tagore4. Maulana Azad |
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Answer» Correct Answer - Option 3 : Ravindranath Tagore The correct answer is Ravindranath Tagore.
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| 1690. |
In the Jalianwala Bagh Massacre of 1919 who ordered the shooting of peaceful protesters?1. General Reginald E. H. Dyer2. Michael O’ Dwyer3. Viceroy Lord Chelmsford4. Lord William Hunter |
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Answer» Correct Answer - Option 1 : General Reginald E. H. Dyer The correct answer is General Reginald E. H. Dyer.
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| 1691. |
The Melghat Tiger reserve is in __________.1. Orissa2. Karnataka3. Assam4. Maharashtra |
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Answer» Correct Answer - Option 4 : Maharashtra The correct answer is Maharashtra.
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| 1692. |
Determine the density of cesium chloride which crystallises in a bcc type structure with the edge length 412. 1 pm .The atomic masses of Cs and C1 are 133 and 35.5 respectively . |
| Answer» Density of CsC1 crystal = 4.0 `g cm^(-3)` | |
| 1693. |
Who was the last ruler of Burdwan Raj?1. Bijay Chand Mahtab2. Uday Chand Mahtab3. Maharaj Kumari Jyotsna Dutt4. None of these |
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Answer» Correct Answer - Option 2 : Uday Chand Mahtab The correct answer is Uday Chand Mahtab.
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| 1694. |
If E1 = a1x + b1y + c1z + d = 0, E2 = a2x + b2y + c2z + d = 0, are two intersecting planes which intersect in a line L, then the equation of any plane passing through line L is of the form λ1E1 + λ2E2 = 0 where |λ1| + |λ2| ≠ 0. |
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Answer» Suppose E ≡ px + qy + rz + t = 0 is a plane containing the line L. Let vector n1 = (a1, b1, c1) and vector n2 (a2, b2, c2) be the normals to E1 = 0 and E2 = 0, respectively. Hence, vector (n1 x n2) is parallel to the line L so that (b1c2 - b2c1 - c2a1, a1b2 - a2b1) are the DRs of the line L. Since one of the DRs is not zero, we consider that a1b2 - a2b1 ≠ 0. Therefore, the equations a1x + a2y = p and b1x + b2y = q are uniquely solvable for a non-zero solution and let x = λ1 and y1 = λ2 be the solution. Therefore, a1λ1 + a2λ2 = p and b1λ1 + b2λ2 = q. Let k = r - λ1c1 - λ2c2 and l = t - λ1d1 - λ2d2 so that E ≡ λ1(a1x + b1y + c1z + d1) + λ2(a2x + b2y + c2z + d2) + kz + l = 0 ...(1) Suppose P (x1, y1, z1) and Q(x2, y2, z2), where z1 ≠ z2, are points on line L. Therefore, a1x1 + b1y1 + c1z1 + d1 = 0 and a2x1 + b2y1 + c2z1 + d2 = 0 so that point P(x1, y1, z1) satisfies the equation E = 0 and similarly point Q(x2, y2, z2) satisfies E = 0 [from Eq. (1)]. Therefore, kz1 + l = 0, kz2 + l = 0 and z1 ≠ z2 k = 0 and then l = 0. Hence, the equation of the plane E = 0 is of the for λ1E1 + λ2E2 = 0. |
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| 1695. |
A laptop seller sells some laptops in such a way that selling price of 36 laptops is the same as the cost price of 30 laptops. So the percentage of gain or loss is:1. \(16{{2} \over 3}\)% Loss2. 20% Gain3. \(16{{2} \over 3}\)% Profit4. 20% Loss |
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Answer» Correct Answer - Option 1 : \(16{{2} \over 3}\)% Loss Given: SP of 36 laptops = CP of 30 laptops Formula used: P = S.P. – C.P. L = C.P. – S.P. P% = (P/C.P.) × 100 L% = (L/C.P.) × 100 Where, P → Profit L → Loss SP → Selling price CP → Cost price Calculations: Let the CP of 1 laptop be Rs.y and its SP be Rs.x. So the SP of 36 laptops = 36x And the CP of 30 laptops = 30y According to the question, 36x = 30y ⇒ x ∶ y = 5 ∶ 6 Now let x and y be 5k and 6k respectively. Since x < y So L = 6k – 5k = k L% = (L/CP) × 100 ⇒ L% = (k/6k) × 100 = \(16{{2} \over 3}\)% ∴ The required Loss% is \(16{{2} \over 3}\)%. |
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| 1696. |
What are the rights guaranteed by the Consumer Protection Act of 1986? |
Answer»
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| 1697. |
Abhay and Bhawna invested Rs. 30,000 and Rs. 28,000 respectively in a business. Abhay left the business with his money after 8 months. What is the share of Abhay in the profit at the end of the first year if they earned a profit of Rs. 84,000?1. Rs. 37,0002. Rs. 35,0003. Rs. 42,0004. Rs. 38,000 |
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Answer» Correct Answer - Option 2 : Rs. 35,000 Given: Abhay's investment = Rs. 30,000 Bhawna's investment = Rs. 28,000 Total profit = Rs. 84,000 Concept used: Divide the total profit according to investment ratio. Calculations: The total investment of Abhay in 8 months = 30000 × 8 The total investment of Bhawna in 4 months = 28000 × 12 The ratio of equivalent capitals of Abhay and Bhawna = (30000 × 8) ∶ (28000 × 12) = 5 ∶ 7 Thus Abhay’s share = 84000 × (5/12) = Rs. 35,000 ∴ The share of Abhay is Rs. 35,000. |
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| 1698. |
Three friends A, B and C started a business. A invests 100% more amount than invested by B whereas C invests 40% of the amount invested by A. If the ratio of time duration of investment made by A, B and C is 2 : 4 : 3 and the share of C in the profit is Rs.1080. What will be the total profit earned?1. 40002. 46803. 33604. 4420 |
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Answer» Correct Answer - Option 2 : 4680 Given: Investment of A = 2 × Investment of B (100% more) Ratio of time duration for which amount is invested A : B : C = 2 : 4 : 3 Share of C in profit = Rs 1080. Concept used: Profit earned = Amount invested × Time Calculation: Let B invests Rs. X Then, A's investment = Rs. 2X and C's investment = Rs. (2/5) × 2X (40% = 2/5) = 4/5X ATQ, Ratio of profit = (2X × 2) : (X × 4) : (4/5 × X × 3) = 4X : 4X : 12X/5 = 5 : 5 : 3 Share of C = Rs. 1080 Required Total profit = 1080 × 13/3 = Rs. 4680 |
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| 1699. |
Jay invested Rs. 65000 for a period of 12 months. His friend Abhay invested for 50% of the time than Jay invested and invested an amount which is 75% more than the amount jay invested. Find the ratio of their profits.1. 7 : 102. 8 : 73. 3 : 84. 8 : 5 |
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Answer» Correct Answer - Option 2 : 8 : 7 Given: Jay invested = Rs. 65000 for 12 months Abhay invested = 75% more than Jay for 50% times of Jay Formula: Ratio of Profit = ratios of product of Amount invested and time Calculation:
⇒ 8 ∶ 7 ∴ The ratio of their profits is 8 ∶ 7. |
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| 1700. |
In a business, A and C invested amounts in the ratio 2 : 1, whereas the ratio between amounts invested by A and B was 3 : 2. If their total profit is Rs. 1,573. How much amount B will receive?1. Rs. 3632. Rs. 4843. Rs. 6054. Rs. 726 |
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Answer» Correct Answer - Option 2 : Rs. 484 Given - A : C = 2 : 1, A : B = 3 : 2 Solution - Let the amount of B be PB. ⇒ A : C = 2 : 1, A : B = 3 : 2 ⇒ A : B : C = (2 × 3) : (2 × 2) : (1 × 3) ⇒ A : B : C = 6 : 4 : 3 ⇒ The amount of B = PB = (4/13) × 1573 = Rs. 484 ∴ the amount received by B = Rs. 484 |
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