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Calculate the moment of inertia of a uniform disc of mass \( 10 kg \) and radius \( 60 cm \) about an axis perpendicular to its length and passing through its centre. |
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Answer» Moment of inertia of a uniform disc about an axis perpendicular to its length = \(\frac{MR^2}{2}\) = \(\frac{10 * (0.6)^2}{2}\) = 1.8 kg.m2 |
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