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A ray of light incident on a transparent block at an angle of incident `60^(@)`. If the refractive index of the block is `1.732`, the angle of deviation of the refracted ray isA. `15^(@)`B. `25^(@)`C. `30^(@)`D. `45^(@)` |
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Answer» Correct Answer - C `del=i-r`, ` mu=(sin i)/(sin r)`, `sqrt(3)=(sin60)/(sinr)` `r=30^(@)` , `del=60-30=30^(@)` |
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