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The electrode potential `E_(Zn^(+2)//Zn) ` of a zinc electrode or `25^(@)C` with an aqueous solution of `0.1 M ZnSO_(4)` is `[E_((Zn^(+2)//Zn))=-0.76V]["assume"(2.3-3RT)/(F)=0.06at298K]`A. `+0.73V`B. `-0.79V`C. `-0.82V`D. `-0.70V` |
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Answer» Correct Answer - B `Zn^(+2)+2e^(-)toZn` `E_((Zn^(+2)//Zn))=E_((Zn^(+2)//Zn))^(@)` `-(2.303RT)/(2F)log.([Zn])/([Zn^(+2)])` `=-0.76-(0.06)/(2)log.(1)/([0.1])` `=-0.76-0.03=-0.79V` |
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