Explore topic-wise InterviewSolutions in .

Correct option is B) Fewer

Correct option is D) me/it/him

Correct option is C) give it back

Correct option is C) him/your

Correct option is B) your/her/hers

the correct option is -your/her/hers

Duties: 

1. Coordinates staff, processes and procedure to support the DC in maintaining and exceeding inventory accuracy goals. 

2. Analyze data and publish reports. 

3. Maintain system data integrity. 

4. Track performance by area, determine problems and root causes. 

5. Implement and administer all approved changes to current inventory program

Responsibilities:

1. Coordinate and perform physical inventories of daily/weekly cycle accounts and adjusts inventory records if necessary. 

2. Investigate inventory variances. 

3. Perform other related duties as assigned by management. 

4. Review and monitor the timely confirmation and accuracy of inbound inventory and outbound shipments.

सही विकल्प है b. मुंबई इंडियंस

सही विकल्प है c. क्रिस गेल

सही विकल्प है c. यूएई

सही विकल्प है   b. के एल राहुल
 670 रन बनाये।
 

सही विकल्प है a. कागिसों रबादा

सही विकल्प है c. शिखर धवन

सही विकल्प है d. के एल राहुल

सही विकल्प है b. ईशान किशन

सही विकल्प है c. देवदत्त पल्तीकल

सही विकल्प है  a.  के एल राहुल

Following are the points of distinction:

(a) An integrated steel plant is larger than mini steel plant.

(b) Mini steel plant uses steel scrap and sponge iron while integrated steel plant use basic raw materials, i.e. iron ore for making steel.

(c) Mini steel plant produces mild and alloy steel while integrated steel plant produces only steel

Gross Motor skills 

• Becoming more skilled at running, jumping, early throwing, and kicking 
• Catching a bounced ball 
• Pedaling a tricycle (at 3 years); becoming able to steer well at around age 4 
• Hopping on one foot (at around 4 years), and later balancing on one foot for up to 5 seconds 

Fine Motor Skills 

• Drawing a circle 
• Drawing a person with 3 parts 
• Beginning to use children's blunt-tip scissors 
• Self-dressing (with supervision)

Types of sports injuries include:

• Sprains. Overstretching or tearing the ligaments results in a sprain.
• Strains. Overstretching or tearing muscles or tendons results in a sprain.
• Knee injuries.
• Swollen muscles.
• Achilles tendon rupture.
• Fractures.
• Dislocations.
• Rotator cuff injury.

• Chair Stand Test - testing lower body strength
• Arm Curl Test - testing upper body strength
• Chair sit and Reach Test - lower body flexibility test
• Back Scratch Test - upper body flexibility test
• 8 Foot Up and Go Test - agility test
• Walk Test (6 min) - used to assess aerobic endurance

Types of sports injuries include:

• Sprains. Overstretching or tearing the ligaments results in a sprain.
• Strains. Overstretching or tearing muscles or tendons results in a sprain.
• Knee injuries.
• Swollen muscles.
• Achilles tendon rupture.
• Fractures.
• Dislocations.
• Rotator cuff injury.

Correct option is B) crouch

Given:

SP of each set = Rs. 287

Fixed cost = 18% of total cost

Explanation:

There is a loss of 18 %

∴ SP is 82% of CP

82% of CP = Rs. 287

CP = Rs. (287/82) × 100

⇒ Rs. 350

∴ The cost price of each set of cup is Rs. 350

GIVEN:

1 cup costs Rs. 80 but a box containing 6 cups costs Rs. 400.

CONCEPT:
Basic concept of discount.

FORMULA USED:

Discount = [(MP – SP)/MP] × 100

CALCULATION:

Original cost of 6 bars of chocolates = 6 × 80 = Rs. 480

∴ Effective discount on the box = [(480 – 400)/480] × 100

= 16.67%

Given:

Akash purchased two cups for Rs 390 and 460 respectively.

Upon selling the second cup at Rs. 575, he made a total profit of 245 on both the cups. 

The profit percentage for the two cups is interchanged.

Formula Used:

Profit or Gain = Selling price – Cost Price

Loss = Cost Price – Selling Price

Profit percentage = (Profit /Cost Price) x 100

Loss percentage = (Loss/Cost price) x 100

Calculation:  

1st profit = Rs. (390 × 1/4) = Rs. 97.5

2nd profit = Rs. (460 × 1/3) = Rs. 153.33

Total profit = Rs. 250.83

∴ His total profit is Rs. 250.83

(d) Amount received by each person
172850/25
= Rs.6914

√ 432 = 12√ 3 and √ 675 = 15√ 3

Now, √ 432 : √ 675

= 12√ 3 : 15√ 3

= 12 : 15

= 4 : 5

 (a) According to the question, 

x + x + 2 + x + 4 + x + 6 + x + 8 = 140 

or, 5x + 20 = 140 

or, 5x = 120 

x = 120/5 = 24 

x + 8 = 24 + 8 = 32 

The next set of five consecutive even number will start with = 34 

Required sum = 34 + 36 + 38 + 40 + 42 = 190

Given:

Tap A can fill a tank in 4 hours

Tap B can fill the same tank in 8 hours

Tap C can empty the same tank in 6 hours

Concept Used: 

If a tap can fill a tank in n hours then part of the tank filled in 1 hour is 1/n

Calculation:

Time is taken by tap A to fill the tank = 4 hours

Tank filled by tap 1 in one hour = 1/4 part of the tank 

Time is taken by tap B to fill the tank = 8 hours

Tank filled by tap 2 in one hour = 1/8 part of the tank 

Time is taken by tap C to empty the tank = 6 hours

Tank emptied by tap 3 in one hour = 1/6 part of the tank 

So, the part of the tank filled in one hour when all three taps are opened simultaneously 

\(\frac{1}{4} + \frac{1}{8} - \frac{1}{6}\;part\)

\( ⇒ \;\frac{{6 + 3 - 4}}{{24}}\;part\)

\(⇒ \;\frac{5}{{24}}\;part\)

⇒ Time taken by 3 taps to fill the tank = 24/5 = 4.8 hours.

∴ time taken by three taps to fill the tank is 4.8 hours.

Given:

The number series:

16, 26, 39, 52, 68

Concept Used:

Number series following a fixed pattern.

Calculation:

The given number series follows the pattern:

4² + 0 = 16 

5² + 1  = 26

6² + 2 = 36 + 2 = 38

7² + 3 = 49 + 3 = 52

8² + 4 = 64 + 4 = 68

∴ The wrong number in the given number series is 39.

2² + 1 = 4 + 1 ⇒  5

32 + 1 = 9 + 1 ⇒  10

52 + 1 = 25 + 1 ⇒ 26

72 + 1 =  49 + 1 ⇒ 50

112 + 1 = 121 + 1 = 122

132 + 1 = 169 + 1 = 170

∴ In the given pattern 120 is the wrong number

Given:

Time taken by X to complete the work alone = 10 days

Time taken by Y to complete the work alone = 15 days

Time taken by Z to complete the work alone = 60 days

Formula Used:

Efficiency = Total work/Time taken

Calculation:

Let the total work be 60x units (LCM of 10,15, 60)

Efficiency of X = 6x units/day

Efficiency of Y = 4x units/day

Efficiency of Z = x units/day

Work done in 5 days by X and Y = (6x + 4x) × 5

= 50x units

⇒ Remaining work = 60x – 50x = 10x units

This work is completed by Y and Z

Time taken to complete the remaining work = 10x/[(4x + x)]

= 10x/5x = 2 days

Total time taken to complete the whole work = 5 + 2 = 7 days

∴ The total time taken to complete the whole work is 7 days

Given:

Average of speed during uphill (S₁) = 24 kmph

Average of speed during down (S₂) = 30 kmph

Formula used:

Average speed = (2 × S1 × S2)/(S1 + S2)

Calculation:

Average speed = (2 × 24 × 30)/(24 + 30)

⇒ 1440/54

⇒ 26.66 kmph

Hence, The average speed of the entire journey is 26.66 kmph.

Given:

⇒ Total investment of P = 500 × 5 + 750 × 7 = Rs.7750

⇒ Initial investment of Q = 500 × 40/100 = Rs.200

⇒ Total investment of Q = 200 × 4 + 400 × 8 = Rs.4000

Ratio oft their profit shares = 7750 : 4000 = 31 : 16

∴ Required difference = 2350 × (31 - 16) /(31 + 16) = Rs.750

Given:

A takes 5 hours to travel 320 km while B takes 7 hours to travel 301 km.

Formula Used:

Distance = time x speed

Calculation:

Speed A = (320/5) km/hr = 64 km/hr

Speed of B = (301/7) km/hr = 43 km/hr

Now, distance covered by B in 19 hours after reducing his speed by 13 km/hr = (30 × 19) km = 570 km.

Time required = (570/64) hours = 8.9 hours

∴ A will take 8.9 hours.

Given:

Let the initial investment of Q and R be Rs.a and Rs.4a respectively.

⇒ Total investment of Q = a × 6 + (a + 400) × 6 = Rs.(12a + 2400)

⇒ Total investment of R = 4a × 5 + (4a - 200) × 7 = Rs.(48a - 1400)

⇒ Profit share of R = 2100 - 1080 = Rs.1020

Then,

⇒ (12a + 2400)/(48a - 1400) = 1080/1020

⇒ (12a + 2400)/(48a - 1400) = 36/34

⇒ (12a + 2400)/(48a - 1400) = 18/17

⇒ a = 100

∴ Initial investment of Q = Rs.100.

Given:

⇒ Total investment of Radha = 200 × 4 + 250 × 8 = Rs.2800

⇒ Total investment of Sham = 100 × 5 + 400 × 7 = Rs.3300

Ratio of their profit shares = 2800 : 3300 = 28 : 33

∴ Profit share of Sham = 915 × 33/(28 + 33) = Rs.495

Given:

Let initial investment of Ramu be Rs.a.

⇒ Total investment of Raju = 250 × 7 + 400 × 5 = Rs.3750

⇒ Total investment pf Ramu = a × 7 + (a - 150) × 5 = Rs.(12a - 750)

Total profit shares of Raju and Ramu = Rs.2800

The difference between the profit shares = 300

Solving,

⇒ The profit share of Raju = Rs.1250

⇒ The profit share of Ramu = Rs.1550

Then,

⇒ 3750 : (12a - 750) = 1250 : 1550

⇒ a = 450

∴ Initial investment of Ramu is Rs.450.

Given:

(1/3)rd of distance travel with speed 25 km/h.

Formula used:

Speed = Distance/Time

Calculation:

Let the total distance is x km

25 = [(x/3)/(2)]

⇒ 25 = (x/6)

⇒ x = 150 km 

Given:

Let amount removed and added by Raj and Ram after 8 months be Rs.a.

⇒ Total investment of Raj = 500 × 8 + (500 - a) × 4 = Rs.(6000 - 4a)

⇒ Total investment of Ram = 600 × 8 + (600 + a) × 4 = Rs.(7200 + 4a)

Total profit shares of Raj and Ram = Rs.2640

⇒ The profit share of Ram = 2640 - 1040 = Rs.1600

Then,

⇒ (6000 - 4a) : (7200 + 4a) = 1040 : 1600

Solving,

⇒ a = 200

∴ After 8 months, Raj and Ram removed and added Rs.200.