This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8001. |
In the fourteenth century, which of the following travelers came to India?1. Ibn Battuta2. Duarte Barbosa3. Francois Bernier4. Antonio Monserrate |
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Answer» Correct Answer - Option 1 : Ibn Battuta The correct answer is Ibn Battuta.
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| 8002. |
Fill in the blanks by choosing the appropriate expression given in bracket.Navdanya, the movement .......... biodiversity conservation ........... organic farming .......... I started in 1987, is spreading ......... far we’ve worked with farmers. (that, for, so, and) |
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Answer» Navdanya, the movement or biodiversity conservation and organic farming that I started in 1987, is spreading so far we’ve worked with farmers. |
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| 8003. |
In the context of forest conservation, Navadanya Movement was founded in 1987 by ______.1. Pandurang Hegde2. Baba Amte3. Vandana Shiva4. Medha Patkar |
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Answer» Correct Answer - Option 3 : Vandana Shiva The correct answer is Vandana Shiva.
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| 8004. |
Observe the information provided in the table about quantum numbers. Then answer the questions given below it.nlml1002010–1, 0, +13012 0–1, 0, +1–2, –1, 0, +1, +2(i) Write the 'l' value and symbol of the spherical shaped sub-shell. (ii) How many values that ml takes for l = 2 ? What are they ? (iii) Write the symbols of the orbitals for l = 1 sub-shell ? (iv) What is the shape of the sub-shell for l = 2 ? What is the maximum number of electrons that can occupy this sub-shell ? |
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Answer» (i) Spherical shaped sub-shell 'l' value is zero and symbol is 's'. (ii) Number of ml values for l = 2 is 5, those are –2, –1, 0,1,2 (iii) Symbols of the orbitals for l = 1 sub-shell are px, py, pz . (iv) Shape of the sub-shell l = 2 is double dumbel. The maximum number of electrons that can occupy in this sub-shell is 10. |
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| 8005. |
Some elements belonging to second period of periodic table, and their atomic radii are given below.Observe them and write answers.2nd period elements BBeONLiCAtomic radii8811166 7415277(a) Write the elements in the ascending order of their atomic radii. (b) Which of the 2nd period elements closer to the configuration of inert gas ? (c) Which is the outermost orbit of all these elements ? (d) Which elements atomic size bigger Beryllium or Carbon ? Why ? |
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Answer» (a) The ascending order of atomic sizes is O, N, C, B, Be and Li. (b) Lithium has closest inert gas configuration i.e., 1s2 2s1.Its nearest inert gas is Helium. (c) The outermost orbit for all these elements is second orbit. (d) Beryllium has more atomic size than Carbon. Because when we move across a period the atomic number increases. So nuclear attraction of outermost orbit increases. So carbon has lesser size than Beryllium. |
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| 8006. |
Observe the information provided in the table about quantum numbers. Then answer the questions given below it.nlml10020 01– 1, 0, + 13001– 1, 0, + 12– 2, – 1, 0, + 1, + 2(i) Write the 'l' value and symbol of the spherical shaped sub-shell. (ii) How many values that 'ml ' takes for l = 2 ? What are they? (iii) Write the symbols of the orbitals for l = 1 sub-shell. (iv) What is the shape of the sub-shell for l = 2? What is the maximum number of electrons that can occupy this sub-shell ? |
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Answer» (i) Spherical shaped sub-shell "l" value is zero and symbol is 's'. (ii) Number of ml values for l = 2 is 5, those are – 2, – 1, 0, 1, 2. (iii) Symbols of the orbitals for l = 1 sub-shell are px , py, pz. (iv) Shape of the subshell l = 2 is double dumbel. The maximum number of electrons that can occupy in this sub-shell is 10. |
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| 8007. |
_________ was the summer capital of the British.1. Dalhousie2. Ooty3. Shimla4. Darjeeling |
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Answer» Correct Answer - Option 3 : Shimla The correct answer is Shimla.
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| 8008. |
Shimla was declared as the summer capital of British India in _____.1. 18622. 18633. 18644. 1865 |
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Answer» Correct Answer - Option 3 : 1864 In 1864, Shimlawas declared theSummer Capital of British India.
Hence, we can conclude that Shimla became the Summer Capital of India. |
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| 8009. |
Which of the following is malachile?A. `Cu_(2)S`B. `CuFeS_(2)`C. `Cu(CH)_(2) ,2CaCO_(3)`D. `Cu(OH)_(2) CaCO_(2)` |
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Answer» Correct Answer - d Malachite (green) is a basic copper carbonate its copposition is `CaCO_(2), CaOH)_(2)` Arurite (blue) is mother example of basic copper carbonate , its composition is `2CaCO_(2)Ca (OH)_(2)` Malachine and strite are used respectively as green and blue pigments copper is meainly extercted from copper pyoles `CaFeS_(2)` THe term fools gold is used for copper pyrites which like gold |
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| 8010. |
A sample of `C_(x)O_(y)` having `3xx10^(19)` molecules is weighing `3.4 mg`. Then the value of x and y is respectively …………… `(Take N_(A) = 6xx10^(23))`A. `1,2`B. `3,2`C. `2,2`D. `5,2` |
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Answer» Correct Answer - B A sample of `C_(x)O_(y)` having `3xx10^(18)` ………….. Mass of `N_(A)` molecules (Molar mass) `= (3.4xx10^(-3))/(3xx10^(19))xx6xx10^(23)` `= 68 g//mol` This is satisfied only for `x = 3 and y = 2` . |
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| 8011. |
A large body of magmatic material that cools in the deeper depth of the Earth's crust and develops in the form of large domes is known as1. Batholiths2. Lacoliths3. Lopoliths4. Phacoliths |
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Answer» Correct Answer - Option 1 : Batholiths The correct answer is Batholiths.
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| 8012. |
Most heat labile immunoglobulin is (A) Ig G (B) Ig A (C) Ig M (D) Ig D |
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Answer» Most heat labile immunoglobulin is Ig D. |
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| 8013. |
Write the name and molecular formula of the fourth member of alkane series |
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Answer» The fourth member of the alkane series is butane C4H10. |
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| 8014. |
Choose the right order to make up a story.1. They give us much information about history. 2. He wrote about the everyday life of the common people and problems of kings and queens. 3. W. Shakespeare wrote 37 plays, dramas, tragedies and comedies. 4. His plays help us to understand people. 5. For example: Hamlet, King Lear. A) 3,5,2,4,1 B) 2,4,1,5,3 C) 4,1,2,3,5 D) 2,5,1,4,3 E) 4,5,1,3,2 |
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Answer» Correct option is A) 3,5,2,4,1 |
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| 8015. |
Choose the right order to make up a story.1. Her father understood that she boiled the egg for the first time in her life. 2. He took up a newspaper and read for ten minutes. 3. Father asked Kate to boil an egg soft for his breakfast. 4. Kate answered that it wasn't ready because it was still very hard. 5. Then he asked Kate if the egg was ready. A) 3,2,5,4,1 B) 4,2,3,1,5 C) 2,4,3,1,5 D) 5,3,1,2,4 E) 1,3,4,5,2 |
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Answer» Correct option is A) 3,2,5,4,1 |
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| 8016. |
I hate it when my boiled egg ______ properly. A) not done B) isn’t done C) wasn’t done D) won’t be done |
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Answer» Correct option is B) isn’t done |
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| 8017. |
An example of an electrolyte is- (a) Sugar(b) Sodium acetat(c) Urea(d) Benzene |
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Answer» An example of an electrolyte is Sodium acetat |
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| 8018. |
Consider the following processes :I. Dilution of sulphuric acidII. Sublimation of dry iceIII. Condensation of water vapoursIV. Dissolution of ammonium chloride in waterThe endothermic process(es) is/are :(a) I and III(b) II only(c) III only(d) II and IV |
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Answer» Correct answer is (d) II and IV (i) Whenever, concentrated H2SO4 is diluted with water to obtain dilute H2SO4 acid, Huge amount of Heat released. that's why it is exothormic process. (ii) In sublimation, substance changes its physical state from solid to gas, without going in liquid state. Thus, to change the physical state from solid to liquid we have to require heat energy. Hence, it is endothermic process. (iii) Condensation of water vapours are gives up heat energy. Hence it is a exothermic process. (iv) NH4Cl(s) \(\longrightarrow\) NH4(aq) + Cl-(aq) ΔH = +ve On dissolution of ammonium chloride in water, the temperature of water decreases. it means on dissolution of NH4Cl some heat absorbs from water. Hence, it is a endothermic process. |
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| 8019. |
0.2 M NaOH is titrated with 100 ml 0.2 M `CH_(3)` COOH in a conducitivity cell. The data obtained were plotted as following The pH of solution in conductivity cell is 9 at point B. Calculate pH of conductivity cell when 100 ml 0.1 M HCl added in resulting solution present in conducitivity cell at point B. |
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Answer» Correct Answer - 5 `CH_(3)COOH(aq)+NaOH(aq)rarrCH_(3)COONa(g)+H_(2)O` `{:(,(0.2xx100)/(1000),(0.2xx100)/(1000)," "0," "0),(," "0,0,0.02," "0.02):}` `pH=9=(1)/(2)(pKw+pKa+log .(0.02)/(0.2))` ` 18=14+pKa-1` `pKa=5` `CH_(3)COONa(aq)+HCl(aq)rarrCH_(3)COOH(aq)+NaCl(aq)` `{:(,0.02,(100xx0.1)/(1000)=0.01,0,0),(,0.01," "0,0.01,0.01):}` Acidic buffer `pH=pKa+log.(CB)/(CA)` `pH=5+log.(0.01)/(0.01)` `ph=5` |
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| 8020. |
Increasing order of bond angle of `(Cl_(2)O, ClO_(2), Cl_(2)O_(7), I_(3)^(ɵ))` isA. `Cl_(2)O lt ClO_(2) lt Cl_(2)O_(7) lt I_(3)^(ɵ)`B. `Cl_(2)O lt ClO_(2) lt I_(3)^(ɵ) lt Cl_(2)O_(7)`C. `I_(3)^(ɵ) lt Cl_(2)O_(7) lt ClO_(2) lt Cl_(2)O`D. `Cl_(2)O lt Cl_(2)O_(7) lt ClO_(2) lt I_(3)^(ɵ)` |
| Answer» Correct Answer - D | |
| 8021. |
If `61.25 gm` of `K ClO_(3)` reacts with excess of red phosphorus, what mass of tetraphosphorous dioxide `(P_(4) O_(10))` would be produced. `K ClO_(3) (s) + P_(4) (s) rarr P_(4) O_(10) (s) + K Cl (s)`A. `142 gm`B. `426 gm`C. `14.2 gm`D. `32.6 gm` |
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Answer» Correct Answer - B `10 KClO_(3) (s) + 3P_(4) (s) rarr 3 P_(4)O_(10) (s) + 10 KCl (s)` `61.25 gm` `n = (61.25)/(122.5)` `{:(n = (1)/(2) " mole" ,n = (3)/(10) xx (1)/(2),),(,n = (3)/(20) " mole",):}` mass of `P_(4)O_(10) = (3)/(20) (3 1 xx 4 + 10 xx 16)` `= (3)/(20) (284)` `= 14.2 xx 3` `= 32.6 gm` |
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| 8022. |
For the following compounds, the correct statement(s) with respect to nucleophilic substitution reactions is(are)(A) I and III follow SN1 mechanism (B) I and II follow SN2 mechanism (C) Compound IV undergoes inversion of configuration (D) The order of reactivity for I, III and IV is: IV > I > III |
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Answer» (A) I and III follow SN1 mechanism (B) I and II follow SN2 mechanism (C) Compound IV undergoes inversion of configuration (D) The order of reactivity for I, III and IV is: IV > I > III Benzylic and 3° halides both follow SN1 mechanism. Benzylic and 1° halides both follow SN2 mechanism. Benzylic 2° halides can undergo inversion of configuration. The order of reactivity would be IV > I > III if both SN1 and SN2 are considered suitably for substrates. |
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| 8023. |
Which of the following statements about physical adsorption is correct ?A. It is usually monolayerB. It is reversible in natureC. It involves van der Waals interactions between adsorbent and adsorbateD. It involves small value of adsorption |
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Answer» Correct Answer - A Physical adsorption is a multilayer phenomenon. |
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| 8024. |
If ∆G°= –2.3RT log Keq, the free energy for the reaction will be A BC + 10moles 10moles 10moles (A) –4.6 RT (B) –2.3 RT (C) +2.3 RT (D) +4.6 RT |
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Answer» Correct option (C) +2.3 RT |
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| 8025. |
When a graph is plotted between log `x//m` and log p, it is striaght line with an angle `45^(@)` and intercept `0.3010` on y-axis. If initial pressure is `0.3` atm, what will be the amount of gas adsorbed per gm of adsorbent?A. 0.4B. 0.6C. 0.8D. 0.1 |
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Answer» Correct Answer - B `"log"x/m="log"K+1/n"log"Pimplies 1/n=tan 45^@ implies n=1 implies "log" K=0.3010,K=2 implies x/m=2xx(0.3)^1 implies x=0.6` |
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| 8026. |
The following sets of three vectors act on a body. Whose resultant cannot be zero ?A. `10, 10, 10`B. `10, 10, 20`C. `10, 20, 20`D. `10, 20, 40` |
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Answer» Correct Answer - D For zero resultant, sum of any of any two forces `ge` remaining force |
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| 8027. |
How many minimum number of vectors in different planes can be added to give zero resultant? |
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Answer» The correct option is (3) 4. Explanation: The required number of vectors is 4. suppose A,B,C, D are four vectors and no three of them are coplaner. if the resultant of A and B be X, and resultant of C and D be Y. if X, and Y be equal in magnitude but in opposing directions, that's the only way the resultant of A, B, C, D be zero, without any three of them being in the same plane. Correct answer is 4 Four vectors in different planes may give zero resultant. |
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| 8028. |
Match the following |
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Answer» a. (c) b. (d) c. (b) d. (a) |
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| 8029. |
2. The displacement of a particle as a function of time is shown in the figure. The figure shows that[CPMT 1970, 86](a) The particle starts with cecrand velocity but the motion is retarded and finally the particle stops(b) The velocity of the particle is constant throughout(c) The acceleration of the particle is constant throughout.(d) The particle starts with constant velocity, then motion is accelerated and finally the particle moves with another constant velocity |
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Answer» I want answer |
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| 8030. |
A car starts from P and follows the path as shown in figure. Finally car stops at R. If the distance travelled is s and magnitude of displacement of the car is d then value of `(3s)/(4d)`. `[a = 7m, b = 8m " and " r = (11)/(pi) m " take " pi = (22)/(7)]` |
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Answer» Correct Answer - 1 Distance travelled by the car `= 48 m`, Displacement of the car `= 36 m` |
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| 8031. |
A particle moves with an initial velocity `V_(0)` and retardation `alpha v` , where `alpha` is a constant and v is the velocity at any time t. Velocity of particle at time is :A. `v = alpha t^(2)`B. `v = V_(0) - alpha t`C. `v = (V_(0))/(ln alpha t)`D. `v = V_(0)e^(-alpha t)` |
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Answer» Correct Answer - B Velocity of ………….. `(dv)/(dt) = -alpha v` `overset(v)underset(v_(0))int (dv)/(v) = -alpha overset(t)underset(0)int dt` `|l nv|_(v_(0)^(v)= -alpha|t|_(0)^(t)` In `(V)/(V_(0))= - alpha t` `V = V = V_(0)e^(-alpha t)` |
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| 8032. |
A particle moves with an initial velocity `V_(0)` and retardation `alpha v` , where `alpha` is a constant and v is the velocity at any time t. total distance covered by the particle isA. `(v_(0))/(2alpha)`B. `(v_(0))/(alpha)`C. `(3v_(0))/(2alpha)`D. None of these |
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Answer» Correct Answer - C Total distance …………… Retardation `=alpha V` ltbgt `V(dv)/(ds)= -alpha V implies overset(v)underset(v_(0))int dv= -alpha overset(s)underset(0)int ds` `V-V_(0)= -alpha(S-0)` `V = v_(0)-alpha S` when particle stops `V = 0` `V_(0)-alpha s = 0` `S = (V_(0))/(alpha)` |
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| 8033. |
A particle moves with an initial velocity `V_(0)` and retardation `alpha v` , where `alpha` is a constant and v is the velocity at any time t. After how much time, speed of particle decreases by `75%`A. `(2l n2)/(alpha)`B. `(l n(4//3))/(alpha)`C. `(3V_(0))/(4alpha)`D. `(e^(4))/(alpha)` |
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Answer» Correct Answer - D After how …………. `V = (V_(0))/(4) implies V_(0)e^(-alpha t)= (V_(0))/(4)` `-alpha t = l n(1)/(4) implies t = (2l n2)/(alpha)` |
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| 8034. |
The displacement (x) of particle depends on time (t) as `x = alpha t^(2) - beta t^(3)`.A. The particle will return to its starting point after time `alpha//beta`B. The particle will come to rest after time `2alpha//3beta`C. The initial velocity of the particle was zero but its initial acceleration was not zeroD. No net force will act on the particle at `t = alpha//3beta` |
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Answer» Correct Answer - A::B::C::D `x= alpha t^(2) - beta t^(3)` for `x = 0, alpha t^(2) - beta t^(3) = 0` `:. t = (alpha)/(beta)` `(dx)/(dt) = 2 alpha t - 3 beta t^(2)` Particle at rest `v = 0` `2 alpha t - 3 beta t^(2) = 0` `t = (2)/(3) (alpha)/(beta)` `(d^(2)x)/(dt^(2)) = 2 alpha - 6 beta t` at `t = 0 " " a = 2 alpha, " at " t = 0, v = 0` for no net force, `(a = 0)` `2 alpha - 6 beta t = 0, t = (alpha)/(3 beta)` |
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| 8035. |
A particle has initial velocity `12 m//s`. It moves due to a constant force along the line of velocity which initially produces retardation of `8 m//s^(2)`. Then :A. the distance travelled in first 3 second is 0 mB. the distance travelled in first 3 second is `36 m`C. the distance travelled in first 3 second is `18 m`D. displacement in first 3 second is 0 m |
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Answer» Correct Answer - C::D `u = 12 m//s` `a = -8 //s^(2)` Displacement `vec(S) = vec(u) t + (1)/(2) vec(a) t^(2)` `= 12 xx 3 + (1)/(2) xx (-8) xx 3^(2) = 0` Distance `v = u + at` `0 = 12 - 8t` `t = (3)/(2)s at t = (3)/(2)s` velocity becomes zero & direction of motion reverses Distance `t = 0 " to " t = (3)/(2)s` `S = ut + (1)/(2) at^(2) = 9 m` Distance `t (3)/(2)s "to" 3s` `S = 9m` Total distance `= 9 + 9 = 18 m` |
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| 8036. |
Which of th efollowing is/are correct regarding vectors `vec(A) = 2hat(i) + hat(j)` and `vec(B) = 2hat(i) - 4 hat(j)`.A. Angle between `vec(A)` and `vec(B)` is acuteB. Angle between `vec(A) + vec(B)` and `vec(A)` is acuteC. `hat(k)` is a unit vector perpendicular to `vec(A)`D. `(hat(i) - 2 hat(j))/(sqrt5)` is a unit vector perpendicular to `vec(A)` |
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Answer» Correct Answer - B::C::D (A) `vec(A).vec(B) = AB cos theta = 0` `rArr theta = 90^(@)` Angle between `vec(A)` & `vec(B)` in `90^(@)` (B) `vec(A) + vec(B) = 4 hat(i) - 3 hat(j)` `(vec(A) + vec(B)).vec(A) = 8 - 3` `= 5 (+ve)` So, angle between `vec(A) + vec(B)` & `vec(A)` in acute (C ) z-axis is perpendicular to `x - y` plae `|(hat(i) - 2 hat(j))/(sqrt5)| = 1` `(2 hat(i) + hat(j)).((hat(i) - 2 hat(j))/(sqrt5)) = 0` |
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| 8037. |
Which of th efollowing statement is correct ?A. `LiOH gt NaOH gt KOH gt RbOH` (solubility orderB. `Be(OH)_(2) gt Mg(OH)_(2) gt Ca(OH)_(2) gt Sr(OH)_(2)` (basic strength order)C. `LI lt K lt Na lt Rb lt Cs` (density order)D. `Li^(+) gt Na^(+) gt K^(+) gt Rb^(+) gt Cs^(+)` (ionic mobilty in aqueous medium) |
| Answer» Correct Answer - C | |
| 8038. |
Which of the following statement is incorrect about the structure of `B_(2)Hs` isA. It has four `2C - 2e^(-)` bond and two `3C - 2e^(-)` bond.B. The hybridization of each boron atom is `sp^(3)`C. All hydrogens in `B_(2)H_(6)` lie in the same plane.D. Terminal bonds are shorter than bridged bonds. |
| Answer» Correct Answer - C | |
| 8039. |
Which of the following graph is correct for real gases other than hydrogen and helium at `0^(@)` ?A. B. C. D. |
| Answer» Correct Answer - C | |
| 8040. |
In an ionic compound `XY_(2)O_(4)` oxide ions are arranged in ccp. Cations `X` are present in octahedral voids.Cations `Y` are equally distributed between octahedral voids occupied isA. `(1)/(2)`B. `(1)/(4)`C. `(1)/(6)`D. `(1)/(8)` |
| Answer» Correct Answer - A | |
| 8041. |
give a relationship between nearest neighbour distance(d),radius of atom(r), edge of unit cell(a), for fcc and BCC crystal |
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Answer» Simple cubic - Nearest dist - a, radius a/2 , z(no of atoms per unit cel) = 1 Fcc - Nd = a/(2)1/2 , radius = a/2 root2 z=4 Bcc- Nd- a root 3 /2 ; radius = a root3 /4 z= 2 For the derivation and detailed answer must refer to master NCERT book. |
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| 8042. |
(a) Dendrite → axon → axonal end → cell body(b) Cell body → dendrite → axon → axonal end(c) Dendrite → cell body → axon → axonal end(d) Axonal end → axon → cell body → dendrite |
| Answer» (c) Dendrite → cell body → axon → axonal end | |
| 8043. |
(i) The charge on the positive rays depends upon __________ of gas in the __________ tube(ii) The anode rays (positive rays) obtained from ____________ gas, consists of only protons. |
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Answer» i) The charge on the positive rays depends upon "Nature" of gas in the "Cathode ray" Tube. ii) The anode rays (positive rays) obtained from "Hydrogen" gas, consists of only protons. |
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| 8044. |
Define'nerve impulse'. Which structure in a neuron helps to conduct a nerve impulse(i) towards the cell body(ii) away from the cell body? |
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Answer» The information passing through neurons is in the form of chemical and electrical signals, called nerve impulse. (i) Towards the cell body: Dendrites. (ii) Away from the cell body: Axon. |
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| 8045. |
Identify the incorrect match:Name IUPC Offical Name(a) Unnilunium(i) Mendelevium(b) Unnitrium(ii) Lawrencium(c) Unnihexium(iii) Seaborgium(d) Unununnium(iv) Darmstadtium(1) (d), (iv) (2) (a), (i) (3) (b), (ii) (4) (c), (iii) |
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Answer» (1) (d), (iv) Unununium (Z = 111) it is Rontgentum (Rg) not darmstadtium. |
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| 8046. |
Which of the following is not extracted from its sulphide ore?(a) Aluminium(b) Zinc(c) Copper(d) None of these |
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Answer» Correct option is (a) Aluminium Aluminium is extracted from its oxide ore (Bauxite) by electrolysis |
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| 8047. |
The `E^(0)(M^(2+)//M)` value for copper is positive `(+0.34V)`. What is possibly the reason for this? |
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Answer» `E^(ɵ)((M^(2+))/(M))` for any metal is related to the sum of the enthalpy changes taking place in the following steps: `M_(s)overset(triangle_aH^(ɵ))toM_(g)(triangle_aH^(ɵ)=` enthalpy of atomisation) `M_(g)overset(triangle_iH^(ɵ))toM_(g)^(2+)(triangle_iH^(ɵ)=`ionisation enthalpy) `M_(g)^(2+)+aq.overset(triangle_(hyd)H^(ɵ))toM_(aq)^(2+)(triangle_(hyd)H^(ɵ)=`hydration enthalpy) Copper has high (positive) enthalpy of atomisation and low (negative) enthalpy of hydration. Hence `E^(ɵ)((Cu^(2+))/(Cu))` is positive. |
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| 8048. |
Which of the 3d-seres of the transition metals exhibits the largest number of oxidation states ? |
| Answer» Manganese `(Z=25)`, as its atom has the maximum number of unpaired electrons. | |
| 8049. |
In the series `Sc(Z=21)` to `Zn(Z=30)` the enthalpy of atomisation of zinc is the lowest, i.e., 126 kJ `mol^(-1)`. Why? |
| Answer» In the formation of metallic bonds, no electrons from 3d-orbitals are involved in case of zinc, while in all other metals of the 3d series, electrons from the d-orbitals are always invilved in the formation of metallic bonds. | |
| 8050. |
Write the electronic configuration of Fe3+ on the basis of this. |
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Answer» 1s2 2s2 2p6 3s2 3p6 3d5 |
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