Saved Bookmarks
| 1. |
The displacement (x) of particle depends on time (t) as `x = alpha t^(2) - beta t^(3)`.A. The particle will return to its starting point after time `alpha//beta`B. The particle will come to rest after time `2alpha//3beta`C. The initial velocity of the particle was zero but its initial acceleration was not zeroD. No net force will act on the particle at `t = alpha//3beta` |
|
Answer» Correct Answer - A::B::C::D `x= alpha t^(2) - beta t^(3)` for `x = 0, alpha t^(2) - beta t^(3) = 0` `:. t = (alpha)/(beta)` `(dx)/(dt) = 2 alpha t - 3 beta t^(2)` Particle at rest `v = 0` `2 alpha t - 3 beta t^(2) = 0` `t = (2)/(3) (alpha)/(beta)` `(d^(2)x)/(dt^(2)) = 2 alpha - 6 beta t` at `t = 0 " " a = 2 alpha, " at " t = 0, v = 0` for no net force, `(a = 0)` `2 alpha - 6 beta t = 0, t = (alpha)/(3 beta)` |
|