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If `61.25 gm` of `K ClO_(3)` reacts with excess of red phosphorus, what mass of tetraphosphorous dioxide `(P_(4) O_(10))` would be produced. `K ClO_(3) (s) + P_(4) (s) rarr P_(4) O_(10) (s) + K Cl (s)`A. `142 gm`B. `426 gm`C. `14.2 gm`D. `32.6 gm` |
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Answer» Correct Answer - B `10 KClO_(3) (s) + 3P_(4) (s) rarr 3 P_(4)O_(10) (s) + 10 KCl (s)` `61.25 gm` `n = (61.25)/(122.5)` `{:(n = (1)/(2) " mole" ,n = (3)/(10) xx (1)/(2),),(,n = (3)/(20) " mole",):}` mass of `P_(4)O_(10) = (3)/(20) (3 1 xx 4 + 10 xx 16)` `= (3)/(20) (284)` `= 14.2 xx 3` `= 32.6 gm` |
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