100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS Page 127 InterviewSolution

6301.	A particle of mass m is projected form ground with velocity u making angle `theta` with the vertical. The de Broglie wavelength of the particle at the highest point isA. `oo`B. `h/(m u sin theta)`C. `h/(m u cos theta)`D. `h/(m u)`
Answer» Correct Answer - B Velocity at highest point `=u sin theta` `:. lambda_(D)=h/(m u sin theta)` (since `theta` is velocity w.r.t vertical)

Discussion

6302.	Match the following columns and select the correct optionColumn -IColumn -II(a) Organ of Corti(i) Connects middle ear and pharynx(b) Cochlea(ii) Coiled part of the labyrinth(c) Eustachian tube(iii) Attached to the oval window(d) Stapes(iv) Located on the basilar membrane(a)(b)(c)(d)(1)(i)(ii)(iv)(iii)(2)(ii)(iii)(i)(iv)(3)(iii)(i)(iv)(ii)(4)(iv)(ii)(i)(i)
Answer» (4) (iv) (ii) (i) (iii)

Discussion

6303.	The process reponsible for facilitating loss of water in liquid form from the tip of grasss blades at night and in early morning is : (1) Plasmolysis (2) Transpiration (3) Root pressure (4) Imbibition
Answer» (3) Root pressure

Discussion

6304.	The enzyme enterokinase helps in conversion of : (1) pepsinogen into pepsin (2) protein into polypeptides (3) trypsinogen into trypsin (4) caseinogen into casein
Answer» (3) trypsinogen into trypsin

Discussion

6305.	If the head of cockroach is removed, it may live for few days because:(1) the head holds a 1/3rd of a nervous system while the rest is situated along the dorsal part of its body. (2) the supra-oesophageal ganglia of the cockroach are situated in ventral part of abdomen. (3) the cockroach does not have nervous system. (4) the head holds a small proportion of a nervous system while the rest is situated along the ventral part of its body.
Answer» (4) the head holds a small proportion of a nervous system while the rest is situated along the ventral part of its body.

Discussion

6306.	The solids which have the negative temperature coefficient of resistance are : (1) insulators and semiconductors (2) metals (3) insulators only (4) semiconductors only
Answer» Correct answer is (1) insulators and semiconductors

Discussion

6307.	For transistor action, which of the following statements is correct ? (1) The base region must be very thin and lightly doped. (2) Base, emitter and collector regions should have same doping concentrations. (3) Base, emitter and collector regions should have same size. (4) Both emitter junction as well as the collector junction are forward biased.
Answer» Correct answer is (1) The base region must be very thin and lightly doped. Base region is very thin and lightly doped.

6307.

For transistor action, which of the following statements is correct ? (1) The base region must be very thin and lightly doped. (2) Base, emitter and collector regions should have same doping concentrations. (3) Base, emitter and collector regions should have same size. (4) Both emitter junction as well as the collector junction are forward biased.

Answer»

Correct answer is (1) The base region must be very thin and lightly doped.

Base region is very thin and lightly doped.

Discussion

6308.	In a certain region of space with volume 0.2 m3 the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is :(1) 5 N/C (2) Zero (3) 0.5 N/C (4) 1 N/C
Answer» Correct answer is (2) Zero Potential is constant throughout the volume ∴ Electric field is zero.

6308.

In a certain region of space with volume 0.2 m3 the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is :(1) 5 N/C (2) Zero (3) 0.5 N/C (4) 1 N/C

Answer»

Correct answer is (2) Zero

Potential is constant throughout the volume

∴ Electric field is zero.

Discussion

6309.	The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is : (c = speed of electromagnetic waves)(1) 1 : c2 (2) c : 1 (3) 1 : 1 (4) 1 : c
Answer» Correct answer is (3) 1:1 In EMW, electric field and magnetic field have same energy density and same intensities.

6309.

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is : (c = speed of electromagnetic waves)(1) 1 : c2 (2) c : 1 (3) 1 : 1 (4) 1 : c

Answer»

Correct answer is (3) 1:1

In EMW, electric field and magnetic field have same energy density and same intensities.

Discussion

6310.	An ideal gas of mass `m` in a state `A` goes to another state `B` via three different processes as shown in Fig. If `Q_(1), Q_(2)` and `Q_(3)` denote the heat absorbed by the gas along the three paths, then A. `Q_(1)ltQ_(2)ltQ_(3)`B. `Q_(1)ltQ_(2)=Q_(3)`C. `Q_(1)=Q_(2)gtQ_(3)`D. `Q_(1)gtQ_(2)gtQ_(3)`
Answer» Correct Answer - A

Discussion

6311.	A gas is expanded from volume `V_(0) = 2V_(0)` under three different processes. Process `1` is isobaric process, process `2` is isothermal and process `3` is adiabatic. Let `DeltaU_(1), DeltaU_(2) and DeltaU_(3)` be the change in internal energy of the gas in these three processes. then A. `DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`B. `DeltaU_(1) lt DeltaU_(2) lt DeltaU_(3)`C. `DeltaU_(2) lt DeltaU_(1) lt DeltaU_(3)`D. `DeltaU_(2) lt DeltaU_(3) lt DeltaU_(1)`
Answer» Correct Answer - A (i) isobaric (ii) isothermal `V prop T, DeltaU = +ve , Delta U = 0` `V uarr, T , DeltaW = +ve` (iii) `DeltaU lt 0, DeltaW gt0` `(DeltaU)_(I) gt (DeltaU)_(II) gt (DeltaU)_(III)`

Discussion

6312.	Consider a thin square sheet of side L and thickness t, made of a material of resistivity `rho`. The resistance between two opposite faces, shown by the shaded areas in the figure is A. directly proportional to LB. directly proportional to tC. independent of LD. independent of t
Answer» Correct Answer - C

Discussion

6313.	The resistance of a wire of length `l` and diameter `d` is `R`. The wire is stretched to double its length. The resistance of the wire will now beA. `(R )/(2)`B. `2R`C. `4R`D. `16R`
Answer» Correct Answer - C When a wire is stretched `n` times its resisitance becomes `n^(2)` times.

Discussion

6314.	The Nile ______ into the Mediterranean Sea. A) flowing B) flowed C) is flowing D) will flow
Answer» Correct option is C) is flowing

Discussion

6315.	Current flowing through a conducting wire is given by `I = (1+ 2t)` Where t is in seconds and current `I` is in amperes. The charge (in coulombs) flown through the resistor in the interval from `t =0` to `t =1` second is -A. 3B. 2C. 1D. 0
Answer» Correct Answer - B `q=underset(0)overset(t=1)(int) I dt =2` coulombs

Discussion

6316.	A uniform conducting ring of mass `m=2kg`, radius `r=2m` and resistance `8Omega` is kept on smooth, horizontal surface. A time varying magnetic field `vecB=(hati+t^(2)hatj)` Tesla is present in the region, where `t` is time in second and take vertical as `y`-axis. (Take `pi^(2)=10`). ThenA. Time when ring starts toppling is 1 secB. Time when ring starts toppling is `3//4` secC. Heat generated through the ring till the instant when the ring start toppling is `40//3` Joule.D. Heat generated through the ring till the instant when the ring start toppling is `80//3` Joule
Answer» Correct Answer - A::D `phi=BA=(t^(2))(pir^(2))` `epsilon=(dphi)/(dt)=2pir^(2)t` `i=(epsilon)/R=(2pir^(2)t)/R` For toppling `tau=\|vec(mu)xxvecB\|gemgr` `(i.pir^(2)).1gemgr` `(2pir^(2)t)/R.pir^(2) gemgr` `t ge (mgR)/(2pi^(2)r^(3))=1`sec Heat `=int i^(2)Rdt=int((2pir^(2)t)/R)^(2)=dt.R` Heat `=(4pi^(2)r^(4))/R int_(0)^(1) t^(2) dt =80/3` Joule

Discussion

6317.	A block of mass 2kg is sliding on a smooth surface. At t=0, its speed is `v_(0)=2m//s`. At t=0, a time varying force starts acting on the block in the direction opposite to `v_(0)` if the speed of object is `(38)/(N)m//s` at t=10s. Find the value of N
Answer» Area=mv`-mv_(0)` `-42=2(v-2)` -21=v-2 `thereforev=-19m//s`

Discussion

6318.	Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum and `[mu_(0)]` that of the permeability of the vacuum. If M= mass, L=length, T= time and I= electric currentA. `[epsilon_(0)]=[M^(-1)L^(-3)T^(2)I]`B. `[epsilon_(0)]=[M^(-1)L^(-3)T^(4)I^(2)]`C. `[mu_(0)]=[MLT^(-2)I^(-2)]`D. `[mu_(0)]=[ML^(2)T^(-1)I]`
Answer» Correct Answer - B::C `F=(1)/(4pi in_(0))(q_(1)q_(2))/r^(2) rArr MLT^(-2)=[1/in_(0)](A^(2)T^(2))/L^(2)` `rArr [1/in_(0)]=M^(1)L^(3)A^(-2)T^(-4) rArr [in_(0)]=M^(-1)L^(-3)A^(+2)T^(4)` `F/L=mu_(0)/(4pi)(i_(1)i_(2))/(r)` `[ML^(-2)]=[(mu_(0)A^(2))/L]rArr [mu_(0)]=MLA^(-2)T^(-2)`

Discussion

6319.	Verncir constant of verneir scale = 0.1 mm on measuring diameter of shaft. Main scale reading = 1.7 cm. If main scale coincides with 5 division of verneir scale & zero error is -0.05 cm. Diameter of shaft in cm is:(a) 1.80 cm(b) 2.80 cm(c) 4.80 cm(d) 6.80 cm
Answer» Correct option is (a) 1.80 cm Reading = MSR + L.C x V_{S.R + correction} Correction = -zero error = 0.05 cm Reading 1.7 + 0.1 x 10^-1 (5) +0.05 = 1.7 + 0.05 + 0.05 ⇒ 1.80 cm

6319.

Verncir constant of verneir scale = 0.1 mm on measuring diameter of shaft. Main scale reading = 1.7 cm. If main scale coincides with 5 division of verneir scale & zero error is -0.05 cm. Diameter of shaft in cm is:(a) 1.80 cm(b) 2.80 cm(c) 4.80 cm(d) 6.80 cm

Answer»

Correct option is (a) 1.80 cm

Reading = MSR + L.C x V_{S.R + correction}

Correction = -zero error = 0.05 cm

Reading 1.7 + 0.1 x 10^-1 (5) +0.05

= 1.7 + 0.05 + 0.05

⇒ 1.80 cm

Discussion

6320.	The dimensions of a rectangular block measured with a vernier callipers having least count of `0.1mm` is `5mmxx10mmxx5mm`. The maximum percentage error in measurement of volume of the blcok isA. `5%`B. `10%`C. `15%`D. `20%`
Answer» Correct Answer - A `((dv)/(v))_(max)=(0.1)/(5)+(0.1)/(10)+(0.1)/(5)=0.05` So `((dv)/(v))_(max)xx100=5`

Discussion

6321.	Statement 1: A tuning fork of constant frequency sends sound waves in air. If temperature of the air increases, then the wavelength of sound wave in air decreases. Statement 2: Speed of sound in air increases with increases in temperature of airA. Statement-1 is true, Statement-2: is true, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is true, Statement-2: is true, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is true but statement-2 is falseD. Statement-1 is false, Statement-2 is true
Answer» With increases in temperature speed of sound in air shall increases and wavelength of sound will increase. Hence statement-1 is false.

Discussion

6322.	For a FM signal v(t) = 20 cos ( 10 * 108t + 30 sin 3000t), calculate the power dissipated by the FM wave in a 20Ω resistor. a. 100 Watts b. 10 Watts c. 200 Watts d. 20 Watts
Answer» b. 10 Watts Standard expression for FM signal is given by v(t) = A cos ( Ω_ct + m_f sin Ω_mt) Comparing with the given equation, A = 20 The dissipated power is given by P = V²_rms/R = (20/√2)²/ 20 = 10Watts

6322.

For a FM signal v(t) = 20 cos ( 10 * 108t + 30 sin 3000t), calculate the power dissipated by the FM wave in a 20Ω resistor. a. 100 Watts b. 10 Watts c. 200 Watts d. 20 Watts

Answer»

b. 10 Watts

Standard expression for FM signal is given by

v(t) = A cos ( Ω_ct + m_f sin Ω_mt)

Comparing with the given equation,

A = 20

The dissipated power is given by P = V²_rms/R

= (20/√2)²/ 20

= 10Watts

Discussion

6323.	A positively charged metal sphere A is brought into contact with an uncharged metal sphere B. As a result: A. both spheres are positively charged B. A is positively charged and B is neutral C. A is positively charged and B is negatively charged D. A is neutral and B is positively charged E. A is neutral and B is negatively charged
Answer» A. both spheres are positively charged

Discussion

6324.	A neutral metal ball is suspended by a string. A positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. This is because: A. the ball becomes positively charged by induction B. the ball becomes negatively charged by induction C. the number of electrons in the ball is more than the number in the rod D. the string is not a perfect insulator E. there is a rearrangement of the electrons in the ball
Answer» E. there is a rearrangement of the electrons in the ball

Discussion

6325.	Pure silicon and germanimum are
Answer» Both these elements are good semiconductors because they are neither more metallic nor less metallic. They both also lie in the central part of the periodic table.

Discussion

6326.	A wire forming one cycle on sine curve is moved in xy plane with the velocity V = Vxi + Vyj
Answer» INDUCED EMF = (V x B). L = [(v_{x Î +}v_y j^ ) × (-B_ok^) ] λ î = [v_xB_o j^ - v_yB_oî ] λ î = v_yB_o λ

Discussion

6327.	While measuring surface tension of water using capillary rise method, height of the lower meniscus from free surface of water is `3cm` while inner radius of capillary tube is found to be `0.5cm`. Then compute surface tension of water using this data. (Take contact angle between glass and water as `0^(@)` and `g=9.8lms^(-2)`)A. `0.72Nm^(-1)`B. `0.77Nm^(-1)`C. `1.67Nm^(-1)`D. `8.67Nm^(-1)`
Answer» Correct Answer - B `((h+(r )/(3))rdg)/(2costheta)`

Discussion

6328.	The number of six digit numbers that can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that digits do not repeat and the terminal digits are even is (a) 144 (b) 72 (c) 288 (d) 720 (e) None of these
Answer» (d) The first and the last (terminal) digits are even and there are three even digits. This arrangement can be done in ³P₂ ways. For any one of these arrangements, two even digits are used; and the remaining digits are 5(4 odd and 1 even) and the four digits in the six digits (leaving out the terminal digits) may be arranged using these 5 digits in ⁵P₄ ways. The required number of numbers is ³P₂ × ⁵P₄ = 6 × 120 = 720.

Discussion

6329.	Give reasons for the following cases.1. It is easier to swim in sea water than in river walls.2. The passangers are advised to remove ink from pen while going up in an aeroplane.
Answer» 1. The density of sea water is more than that of river water due to the presence of salt. Hence sea water offers more up thrust and only a very small portion of human body will be in sea water compared to river water. 2. In ink pen, ink is filled in atmospheric pressure. As we go higher pressure decreases and hence ink will have a tendancy to come out in order to equalise the pressure.

6329.

Give reasons for the following cases.1. It is easier to swim in sea water than in river walls.2. The passangers are advised to remove ink from pen while going up in an aeroplane.

Answer»

1. The density of sea water is more than that of river water due to the presence of salt. Hence sea water offers more up thrust and only a very small portion of human body will be in sea water compared to river water.

2. In ink pen, ink is filled in atmospheric pressure. As we go higher pressure decreases and hence ink will have a tendancy to come out in order to equalise the pressure.

Discussion

6330.	Why cotton dress is preferred in summer?
Answer» Cotton dresses have ne pores which act as capillaries for the sweat.

Discussion

6331.	Mobil oil is used in scooters and bikes for which purpose?As fuelFor reducing frictionFor increasing frictionNone of the above
Answer» Answer: (b) For reducing friction

Discussion

6332.

Match the following1. Pascal’s lawa. √(2gh)2. Bernoulli’s theoremb. a1v1= a2v23. Surface tensionc. Hydraulic jack4. Velocity of effluxd. Reynolds number5. Equation of continuitye. Angle of contact6. Viscosityf. Ventiuri meter

Answer»

1. Pascal’s law	c. Hydraulic jack
2. Bernoulli’s theorem	f. venturi meter
3. Surface tension	e. Angle of contact
4. Velocity of efflux	a. √(2gh)
5. Equation of continuity	b. a₁v₁= a₂v₂
6. Viscosity	d. Reynolds number

Discussion

6333.	Why more viscous oil is used in summer than in winter in scooters?
Answer» The viscosity decreases with increase in temperature.

Discussion

6334.	(a) auxin(b) gibberellin(c) abscisic acid(d) cytokinin
Answer» (c) abscisic acid

Discussion

6335.	Pneumatophore are(1) Positively geotropic (2) Negative phototropic (3) Negatively geotropic (4) Hydrotropic
Answer» (3) Negatively geotropic

Discussion

6336.	The root of a plant is (A) Positively geotropic (B) Positively phototropic (C) Negative geotropic (D) Positively thigmotropic
Answer» Correct option (A) Positively geotropic Explanation: Since root shows growth in the direction of gravity, this type of response is termed as positive geotropism.

6336.

The root of a plant is (A) Positively geotropic (B) Positively phototropic (C) Negative geotropic (D) Positively thigmotropic

Answer»

Correct option (A) Positively geotropic

Explanation:

Since root shows growth in the direction of gravity, this type of response is termed as positive geotropism.

Discussion

6337.	Haematuria can occur in all of the following except(A) Acute glomerulonephritis(B) Cancer of urinary tract(C) Stone in urinary tract(D) Mismatched blood transfusion
Answer» Correct option is (D) Mismatched blood transfusion

Discussion

6338.	The orientation of head where the mouthparts are projected forward along the horizontal axis of body a. Prognathous b. Hypognathous c. Opisthognathous d. Opisthosynchous
Answer» a. Prognathous

Discussion

6339.	The active transport system for hepatic uptake of bilirubin is congenitally defective in (A) Gilbert’s disease (B) Crigler-Najjar syndrome (C) Rotor’s syndrome (D) Dubin-Johnson syndrome
Answer» (A) Gilbert’s disease

Discussion

6340.	In hepatic diseases (A) Both the bound iron and total iron binding capacity of the plasma may be low (B) Both the bound iron and total iron binding capacity of the plasma may be high (C) Only bound iron may be high (D) Only the total iron binding capacity may be high
Answer» (A) Both the bound iron and total iron binding capacity of the plasma may be low

Discussion

6341.	Sucking mouthparts are NOT found in: a. Fleas b. Lice c. Flies d. Ants
Answer» Sucking mouthparts are NOT found in Ants.

Discussion

6342.	Write about Monoclonal Antibody
Answer» Monoclonal Antibody: Monoclonal antibodies are special type of antibody for the specific antigen. They can be cultured outside body very easily. Such type of antibody is produced by fusion of antibody producing cell with any malignant tumour cells.

6342.

Write about Monoclonal Antibody

Answer»

Monoclonal Antibody:

Monoclonal antibodies are special type of antibody for the specific antigen. They can be cultured outside body very easily. Such type of antibody is produced by fusion of antibody producing cell with any malignant tumour cells.

Discussion

6343.	Pre- hepatic jaundice occurs because of (A) Increased haemolysis (B) Liver damage (C) Biliary obstruction (D) None of these
Answer» (A) Increased haemolysis

Discussion

6344.	Agrobacterium tumifaciens is a natural vector. How?
Answer» Agrobacterium T_i plasmid is preferred over all other vector because of wide host range of its bacterial system and the capacity to transfer genes due to presence of T-DNA border sequence. Agrobacterium tumefacieni said to be natural genetic engineer of plants due to the reason due to their capability to transfer T-DNA of their plasmid into desired plant genome at wound site. It leads of the formation of crown gall (tumour) i.e., unorganised growth of cells. Crown gall tumours synthesize, large amount of certain metabolites called opines. The genes which determine opine synthesis are borne on T_i plasmid.

Discussion

6345.	Bile pigments are not present in urine in(A) Haemolytic jaundice (B) Hepatic jaundice (C) Obstructive jaundice (D) Rotor’s syndrome
Answer» (A) Haemolytic jaundice

Discussion

6346.	Name the process of working with and through others to effectively achieve organisational objectives by efficiently using limited resources in a changing environment. (a) Management (b) Planning (c) Organising (d) Controlling.
Answer» (a) Management

Discussion

6347.	In which state is the Sarhul festival celebrated?1. Chhattisgarh2. Gujarat3. Jharkhand4. Assam
Answer» Correct Answer - Option 3 : Jharkhand The correct answer is Jharkhand. Sarhul is a popular festival celebrated by various tribes in the Jharkhand region. The festival is the tribal New Year and is celebrated by the Munda, Oraon, Ho, etc. tribes of Jharkhand. One of the most popular tribal festivals celebrated across the Jharkhand region, the Sarhul festival marks the beginning of New Year. It is celebrated by the Oraon, the Munda, and the Ho tribes, of the Jharkhand region. Celebrated every year in the first month of the Hindu calendar, on the third day of the moon or the fortnight of 'Chaitra', Sarhul marks the advent of the spring season or “Phaagun” and is celebrated till the month of June or “Jeth”. Sarhul means worship of trees. Being close to nature, these tribes start the Sarhul festival with the worship of trees and other elements of nature.

6347.

In which state is the Sarhul festival celebrated?1. Chhattisgarh2. Gujarat3. Jharkhand4. Assam

Answer» Correct Answer - Option 3 : Jharkhand

The correct answer is Jharkhand.

Sarhul is a popular festival celebrated by various tribes in the Jharkhand region. The festival is the tribal New Year and is celebrated by the Munda, Oraon, Ho, etc. tribes of Jharkhand.
One of the most popular tribal festivals celebrated across the Jharkhand region, the Sarhul festival marks the beginning of New Year.
- It is celebrated by the Oraon, the Munda, and the Ho tribes, of the Jharkhand region.
- Celebrated every year in the first month of the Hindu calendar, on the third day of the moon or the fortnight of 'Chaitra', Sarhul marks the advent of the spring season or “Phaagun” and is celebrated till the month of June or “Jeth”.
- Sarhul means worship of trees. Being close to nature, these tribes start the Sarhul festival with the worship of trees and other elements of nature.

Discussion

6348.	The dance form related to Garasia Tribe is1. Gavari2. Loor3. Bam4. Terahtali
Answer» Correct Answer - Option 2 : Loor The correct answer is Loor. The dance form related to Garasia Tribe is Loor. Garasii The hill tribes of Meenas and Bhils are termed as Garasias. The tribals of Rajasthan perform a number of famous dance forms that are participated by both man and woman alike. Dancing forms performed by Garasias are: The Garva dance The Valar dance Chang dance Loor dance Gavari Performed Udaipur, Rajsamand and Chittorgarh districts of Rajasthan. Performed By mainly Bhil Tribe. Bam It is a dance performed by men only to the beat of a big drum (bomb). It is performed on the occasion of Holi in Bharatpur and Alwar region. Terahtali Performed in Ramdevra, Dindwana, Dungarpur, Udaipur. Mainly Performed By Woman from Kamad tribe while sitting on the floor before Baba Ramdeo's image.

6348.

The dance form related to Garasia Tribe is1. Gavari2. Loor3. Bam4. Terahtali

Answer» Correct Answer - Option 2 : Loor

The correct answer is Loor.

The dance form related to Garasia Tribe is Loor.

Garasii
- The hill tribes of Meenas and Bhils are termed as Garasias.
- The tribals of Rajasthan perform a number of famous dance forms that are participated by both man and woman alike.
- Dancing forms performed by Garasias are:
  - The Garva dance
  - The Valar dance
  - Chang dance
  - Loor dance

Gavari
- Performed Udaipur, Rajsamand and Chittorgarh districts of Rajasthan.
- Performed By mainly Bhil Tribe.
Bam
- It is a dance performed by men only to the beat of a big drum (bomb).
- It is performed on the occasion of Holi in Bharatpur and Alwar region.
Terahtali
- Performed in Ramdevra, Dindwana, Dungarpur, Udaipur.
- Mainly Performed By Woman from Kamad tribe while sitting on the floor before Baba Ramdeo's image.

Discussion

6349.

What is the percentage of urban population in India and Rajasthan respectively as per Census 2011?1. 24.87% and 31.15%2. 34.14% and 24.87%3. 21.87% and 34.15%4. 31.15% and 24.87%

Answer» Correct Answer - Option 4 : 31.15% and 24.87%

The correct answer is 31.15% and 24.87%.

The percentage of the urban population in India and Rajasthan is 31.15% and 24.87% respectively as per Census 2011.

Rajasthan Urban Population 2011

Description	Rural	Urban
Population (%)	75.13%	24.87%
Total Population	51,500,352	17,048,085
Male Population	26,641,747	8,909,250
Female Population	24,858,605	8,138,835
Population Growth	18.96%	29.01%

Rajasthan Urban Population 2011
- Out of the total population of Rajasthan, 24.87% of people live in urban regions.
- The total figure of the population living in urban areas is 17,048,085 of which 8,909,250 are males and while remaining 8,138,835 are females.
- The urban population in the last 10 years has increased by 24.87 per cent.
- Sex Ratio in urban regions of Rajasthan was 914 females per 1000 males.
- For child (0-6) sex ratio the figure for the urban region stood at 874 girls per 1000 boys.
- Total children (0-6 age) living in urban areas of Rajasthan were 2,234,621.
- Of the total population in the urban region, 13.11 % were children (0-6).
- Average Literacy rate in Rajasthan for Urban regions was 79.68 per cent in which males were 87.91% literate while female literacy stood at 63.81%.
- Total literates in urban region of Rajasthan were 11,803,496.
The total urban population in the country
- The total urban population in the country as per Census 2011 is more than 377 million constituting 31.16% of the total population.
- Class I UAs/Towns:
  - The UAs/Towns are grouped on the basis of their population in Census.
  - The UAs/Towns which have at least 1,00,000 persons as a population are categorised as Class I UA/Town.
  - At the Census 2011, there are 468 such UAs/Towns.
  - The proportion has increased considerably over the last Census. In the remaining classes of towns, the growth has been nominal
- Million Plus UAs/Towns:
  - Out of 468 UAs/Towns belonging to Class I category, 53 UAs/Towns each has a population of one million or above each.
  - Known as Million Plus UAs/Cities, these are the major urban centres in the country.
- Mega-Cities:
  - Among the Million Plus UAs/Cities, there are three very large UAs with more than 10 million persons in the country, known as Mega-Cities.
  - These are Greater Mumbai UA (18.4 million), Delhi UA (16.3 million) and Kolkata UA (14.1 million).

Discussion

6350.	As per 2011 census India’s sex Ratio is-(A) 950 (B) 930(C) 940 (D) 960
Answer» As per 2011 census India’s sex Ratio is 940.

Discussion

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A particle of mass m is projected form ground with velocity u making angle `theta` with the vertical. The de Broglie wavelength of the particle at the highest point isA. `oo`B. `h/(m u sin theta)`C. `h/(m u cos theta)`D. `h/(m u)`

The process reponsible for facilitating loss of water in liquid form from the tip of grasss blades at night and in early morning is : (1) Plasmolysis (2) Transpiration (3) Root pressure (4) Imbibition

The enzyme enterokinase helps in conversion of : (1) pepsinogen into pepsin (2) protein into polypeptides (3) trypsinogen into trypsin (4) caseinogen into casein

The solids which have the negative temperature coefficient of resistance are : (1) insulators and semiconductors (2) metals (3) insulators only (4) semiconductors only

In a certain region of space with volume 0.2 m3 the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is :(1) 5 N/C (2) Zero (3) 0.5 N/C (4) 1 N/C

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is : (c = speed of electromagnetic waves)(1) 1 : c2 (2) c : 1 (3) 1 : 1 (4) 1 : c

Consider a thin square sheet of side L and thickness t, made of a material of resistivity `rho`. The resistance between two opposite faces, shown by the shaded areas in the figure is A. directly proportional to LB. directly proportional to tC. independent of LD. independent of t

The resistance of a wire of length `l` and diameter `d` is `R`. The wire is stretched to double its length. The resistance of the wire will now beA. `(R )/(2)`B. `2R`C. `4R`D. `16R`

The Nile ______ into the Mediterranean Sea. A) flowing B) flowed C) is flowing D) will flow

Current flowing through a conducting wire is given by `I = (1+ 2t)` Where t is in seconds and current `I` is in amperes. The charge (in coulombs) flown through the resistor in the interval from `t =0` to `t =1` second is -A. 3B. 2C. 1D. 0

A block of mass 2kg is sliding on a smooth surface. At t=0, its speed is `v_(0)=2m//s`. At t=0, a time varying force starts acting on the block in the direction opposite to `v_(0)` if the speed of object is `(38)/(N)m//s` at t=10s. Find the value of N

Verncir constant of verneir scale = 0.1 mm on measuring diameter of shaft. Main scale reading = 1.7 cm. If main scale coincides with 5 division of verneir scale &amp; zero error is -0.05 cm. Diameter of shaft in cm is:(a) 1.80 cm(b) 2.80 cm(c) 4.80 cm(d) 6.80 cm

The dimensions of a rectangular block measured with a vernier callipers having least count of `0.1mm` is `5mmxx10mmxx5mm`. The maximum percentage error in measurement of volume of the blcok isA. `5%`B. `10%`C. `15%`D. `20%`

For a FM signal v(t) = 20 cos ( 10 * 108t + 30 sin 3000t), calculate the power dissipated by the FM wave in a 20Ω resistor. a. 100 Watts b. 10 Watts c. 200 Watts d. 20 Watts

Pure silicon and germanimum are

A wire forming one cycle on sine curve is moved in xy plane with the velocity V = Vxi + Vyj

The number of six digit numbers that can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that digits do not repeat and the terminal digits are even is (a) 144 (b) 72 (c) 288 (d) 720 (e) None of these

Give reasons for the following cases.1. It is easier to swim in sea water than in river walls.2. The passangers are advised to remove ink from pen while going up in an aeroplane.

Why cotton dress is preferred in summer?

Mobil oil is used in scooters and bikes for which purpose?As fuelFor reducing frictionFor increasing frictionNone of the above

Match the following1. Pascal’s lawa. √(2gh)2. Bernoulli’s theoremb. a1v1= a2v23. Surface tensionc. Hydraulic jack4. Velocity of effluxd. Reynolds number5. Equation of continuitye. Angle of contact6. Viscosityf. Ventiuri meter

Why more viscous oil is used in summer than in winter in scooters?

(a) auxin(b) gibberellin(c) abscisic acid(d) cytokinin

Pneumatophore are(1) Positively geotropic (2) Negative phototropic (3) Negatively geotropic (4) Hydrotropic

The root of a plant is (A) Positively geotropic (B) Positively phototropic (C) Negative geotropic (D) Positively thigmotropic

Haematuria can occur in all of the following except(A) Acute glomerulonephritis(B) Cancer of urinary tract(C) Stone in urinary tract(D) Mismatched blood transfusion

The orientation of head where the mouthparts are projected forward along the horizontal axis of body a. Prognathous b. Hypognathous c. Opisthognathous d. Opisthosynchous

The active transport system for hepatic uptake of bilirubin is congenitally defective in (A) Gilbert’s disease (B) Crigler-Najjar syndrome (C) Rotor’s syndrome (D) Dubin-Johnson syndrome

In hepatic diseases (A) Both the bound iron and total iron binding capacity of the plasma may be low (B) Both the bound iron and total iron binding capacity of the plasma may be high (C) Only bound iron may be high (D) Only the total iron binding capacity may be high

Sucking mouthparts are NOT found in: a. Fleas b. Lice c. Flies d. Ants

Write about Monoclonal Antibody

Pre- hepatic jaundice occurs because of (A) Increased haemolysis (B) Liver damage (C) Biliary obstruction (D) None of these

Agrobacterium tumifaciens is a natural vector. How?

Bile pigments are not present in urine in(A) Haemolytic jaundice (B) Hepatic jaundice (C) Obstructive jaundice (D) Rotor’s syndrome

Name the process of working with and through others to effectively achieve organisational objectives by efficiently using limited resources in a changing environment. (a) Management (b) Planning (c) Organising (d) Controlling.

In which state is the Sarhul festival celebrated?1. Chhattisgarh2. Gujarat3. Jharkhand4. Assam

The dance form related to Garasia Tribe is1. Gavari2. Loor3. Bam4. Terahtali

What is the percentage of urban population in India and Rajasthan respectively as per Census 2011?1. 24.87% and 31.15%2. 34.14% and 24.87%3. 21.87% and 34.15%4. 31.15% and 24.87%

As per 2011 census India’s sex Ratio is-(A) 950 (B) 930(C) 940 (D) 960

Verncir constant of verneir scale = 0.1 mm on measuring diameter of shaft. Main scale reading = 1.7 cm. If main scale coincides with 5 division of verneir scale & zero error is -0.05 cm. Diameter of shaft in cm is:(a) 1.80 cm(b) 2.80 cm(c) 4.80 cm(d) 6.80 cm