Saved Bookmarks
| 1. |
The resistance of a wire of length `l` and diameter `d` is `R`. The wire is stretched to double its length. The resistance of the wire will now beA. `(R )/(2)`B. `2R`C. `4R`D. `16R` |
|
Answer» Correct Answer - C When a wire is stretched `n` times its resisitance becomes `n^(2)` times. |
|