1.

The resistance of a wire of length `l` and diameter `d` is `R`. The wire is stretched to double its length. The resistance of the wire will now beA. `(R )/(2)`B. `2R`C. `4R`D. `16R`

Answer» Correct Answer - C
When a wire is stretched `n` times its resisitance becomes `n^(2)` times.


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