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A gas is expanded from volume `V_(0) = 2V_(0)` under three different processes. Process `1` is isobaric process, process `2` is isothermal and process `3` is adiabatic. Let `DeltaU_(1), DeltaU_(2) and DeltaU_(3)` be the change in internal energy of the gas in these three processes. then A. `DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`B. `DeltaU_(1) lt DeltaU_(2) lt DeltaU_(3)`C. `DeltaU_(2) lt DeltaU_(1) lt DeltaU_(3)`D. `DeltaU_(2) lt DeltaU_(3) lt DeltaU_(1)` |
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Answer» Correct Answer - A (i) isobaric (ii) isothermal `V prop T, DeltaU = +ve , Delta U = 0` `V uarr, T , DeltaW = +ve` (iii) `DeltaU lt 0, DeltaW gt0` `(DeltaU)_(I) gt (DeltaU)_(II) gt (DeltaU)_(III)` |
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