Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

What is a cistron? Why is the structural gene in a transcription unit of eukaryotes called monocistronic and that in prokaryotes/bacteria called polycistronic? Give reasons.

Answer»

Cistron is a segment of DNA coding for a polypeptide. In eukaryotes the transcriptional unit have interrupted coding sequences - exons and introns. It codes for only one polypeptide, so it is called monocistronic. 

In prokaryotes structural genes have many coding sequences, so it is called polycistronic.

2.

DNA is the genetic material in most of the organisms, while RNA is the genetic material in a few viruses/ What are the four general/common functions performed by RNA in other organisms?

Answer»

Functions of RNA

- It functions as a messenger. 

- It is an adapter. 

- It is a structural component of ribosome 

- It also acts as a catalysts.

3.

Define a cistron

Answer»

A cistron is defined as the length of mRNA, that codes for a polypeptide.

4.

RNA viruses mutate and evolve faster than other viruses. Why?

Answer»

OH group is present on RNA, which is a reactive group so it is unstable and mutate faster.

5.

State any one reason to explain why RNA virus mutate and evolve faster than other viruses.

Answer»

RNA is an unstable highly reactive molecule due to its single-stranded structure and exposure of its nitrogen bases. But DNA is stable, the molecule, as its, nitrogen bases are not exposed, became its double-helical nature.

6.

a. Cancer is one of the most dreaded diseases of humans. Explain ‘Contact inhibition’ and ‘Metastasis’ with respect to the disease. b. Name the group of genes which have been identified in normal cells that could lead to cancer and how they do so? c. Name any two techniques which are useful to detect cancers of internal organs. d. Why are cancer patients often given α-interferon as part of the treatment?

Answer»

a. Contact inhibition is the property of normal cells in which contact with other cells inhibits their uncontrolled growth. Metastasis is the property in which tumour cells reach distant sites in the body, through blood. 

b. Proto oncogenes or Cellular oncogenes. These genes when activated under certain condition could lead to oncogenic transformation of the cells. 

c. Biopsy/radiography/CT/MRI (Any two) 

d. α-interferon activates immune system and destroys the tumour.

7.

Differentiate between benign and malignant tumours.

Answer»
S. NoBenign tumourMalignant tumour
(i)It is a non-cancerous tumour.It is a cancerous tumour
(ii)Benign tumour does not show metastasis and is non-invasive.It shows metastasis and thus invades other body parts.
(iii)It stops growth after reaching a certain size.Malignant tumour shows indefinite growth.
(iv)Limited adherence occurs amongst cells of benign tumour.There is no adherence amongst cells. They tend to slip past one another.
(v)It is less fatal to the body.It is more fatal to the body.
8.

 Why do RNA viruses undergo mutation and evolution faster than most of the other viruses?

Answer»

The 2' OH-group in the nucleotides of RNA is a reactive group,that makes RNA labile 1 and easily degradable.

9.

What is a cistron?

Answer»

A ciston is a segment of DNA, coding for a polypeptide.

10.

Name the enzyme that joints the short pieces in the lagging strand during synthesis of DNA.

Answer»

DNA   legase. 

11.

Why are Okazaki fragments formed on lagging strand only?

Answer»

1. The lagging template is the template strand with free 5’ end. 

2. The replication always starts at C-3 end of template strand and proceeds towards C-5 end. 

3. Both the strands of the parental DNA are antiparallel and new strands are always formed in 5′ → 3′ direction, i.e. DNA polymerase synthesizes new strand in only one direction i.e. 5′ → 3′ direction. 

4. Hence, the lagging templates becomes available for replication only discontinuously in small patches. 

5. The new lagging strand develops discontinuously away from the replicating fork in the form of small Okazaki fragments. 6. Hence, Okazaki fragments formed on lagging strand only.

12.

A template strand is given below. Write down the corresponding coding strand and the mRNA strand that can be formed along with their polarity. 3' ATGCATGCATGCATGCATGCATGC 5' 

Answer»

Coding strand - 5'

TACGTACGTACGTACGTACGTACG 3'

mRNA stands - 5'

UACGUACGUACGUACGUACGUACG 3'.

13.

Explain metastasis. Why is it fatal ?

Answer»

The cancerous cells are sloughed from the tumours and reach distant sites through blood, and wherever they get lodged in the body, they start a new tumour there. This property called metastasis is the most feared property of malignant tumours.

14.

Name the enzyme involved in the continuous replication of DNA strand. Mention the polarity of the template strand.

Answer»

DNA polymerase.

Template strand has 3' → 5' polarity.

15.

When a farmer cultivated Bananas in a field, most of banana plants were infected by virus. Can you suggest any method for propagation of virus free Banana plants.

Answer»

Meristem culture or shoot tip culture.

16.

Fill in the blanks using appropriate words:Inter specific hybrid produced by the cross between

Answer»

Answer is Mule

17.

What is the importance of corpora quadrigemina?

Answer»

Corpora quadrigemina consists of 4 solid rounded structures, viz. superior and inferior colliculi. Superior colliculi control visual reflexes while inferior colliculi control auditory reflexes.

18.

In a debate one of the speaker reported like this.“Continuous inbreeding leads to inbreeding depression.” If so, define the following: (a) Outcross (b) Crossbreeding

Answer»

(a) It is the practice of mating of animals within the same breed, but having no common ancestors on either side of their pedigree up to 4-6 generations. The offspring of such a mating is known as an out-cross.

(b) In this superior males of one breed are mated with superior females of another breed. Hisardale is a new breed of sheep developed in Punjab by crossing Bikaneri ewes and Marino rams.

19.

Define inbreeding depression. What is its danger?

Answer»

Continuous – Inbreeding without selection leads to loss of fertility & productivity.

20.

The enzyme DNA polymerase in E.coli is a DNA dependent polymerase and also has the ability to proofread the DNA strand being synthesised. Explain. Discuss the dual polymerase.

Answer»

DNA polymerase helps in the replication of DNA molecules. DNA polymerase also helps in the proofreading, if any error/mutation occurred during replication.

21.

Explain the processing the hnRNA needs to undergo before becoming functional mRNA in eukaryotes.

Answer»

The precursor of mRNA i.e. hnRNA contains both introns and exons. Introns are removed and exons are joined by a process called splicing. The remaining mRNA is processed in two ways : 

(i) Capping : Here, an unusual nucleotide called methyl guanosine triphosphate (cap) is added to the 5' end of hnRNA. 

(ii) Tailing : Here, adenylate residues (200-300) are added at 3' end of hnRNA in a template independent manner. 

When hnRNA is fully processed, it is known as mRNA, which is transported out of the nucleus to get translated.

22.

Identify giving reasons, the salient features of genetic code by studying the following nucleotide sequences of mRNA strand and the polypeptide translated from it? 

Answer»

Prosperities of genetic code:

- AUG is the initiation codon and codes for methionine; methionine is the first amino acid in the given polypeptide. 

- Genetic code is unambiguous and specific, i.e., each codon codes only for on particular amino acid. 

- Genetic code is degenerate, i.e., more than one codon code on one amino acid. 

- Each codon is a triplet, i.e., made of three nucleotides e.g., AUG, UUU, etc. 

- UAG does not code for any amino acid, it is a termination codon.

23.

Which method is used to overcome inbreeding depression(a) Intra specific hybridization(b) self pollination(c) out breeding(d) intra varietal hybridization

Answer»

(c) out breeding

24.

When inbreeding depression becomes a problem, how can we overcome the issue?

Answer»

Firstly select animals from inbreed population and mate them with unrelated superior animals of the same breed (Out crossing)). This helps to restore fertility and yield.

25.

Continued inbreeding, usually reduces fertility and causes non productivity. This is called .......

Answer»

Inbreeding depression

26.

Inbreeding increases homozygosity and causes inbreeding depression.1. What you meant by inbreeding depression.2. Name the progenies obtained through this process with selection.

Answer»

1. Inbreeding is the mating of more closely related individuals of the same breed. Continued inbreeding leads to increasing homozygozity and ultimately results in the reduction of fertility and productivity.

2. Purelines.

27.

Match the following column A column B.AB1. Inbreeding(a) Cross between two different related species2. Inter specific hybridization(b) Mating of animals within the same breed but having no common ancestors3. Out crossing(c) Superior males of one breed are mated with superior females of another breed4. Crossbreeding(d) Breeding between the animals of same breed

Answer»

1. (d), 2. (a), 3. (b), 4. (c)

28.

Name the following :Enzyme involved in synthesis of hnRNA, mRNA.

Answer»

RNA polymerase – II

29.

What is hnRNA? Explain the changes hnRNA undergoes during its processing to form mRNA.

Answer»

hnRNA is the precursor of mRNA that is transcribed by RNA ploymerase II and is called heterogenous nuclear RNA. 

Changes: 

• The hnRNA undergoes two additional processes called capping and tailing. 

• In capping, an unusual nucleotide, methyl guanosine triphosphate, is added to the 5'- end of hnRNA. 

• In tailing, adenylate residues (about 200–300) are added at 3'-end in a template independent manner. 

• Now the hnRNA undergoes a process where the introns are removed and exons are joined to form mRNA by the process called splicing. Fragments on one of the template strands.

30.

Identify giving reasons, the salient features of genetic code by studying the following nucleotide sequence of mRNA strand and the polypeptide translated from it.AUG UUU UCU UUU UUU UCU UAG Met – Phe – Ser – Phe – Phe – Ser

Answer»
S. No.Salient features of genetic codeReason
(i)The codon is a triplet.e.g., AUG, UUU, etc, are triplets
(ii)One codon codes for only one amino acid,hence it is unambiguous and specific.e.g., UUU codes for serine, AUG for methionine, etc.
(iii)AUG has dual function as it codes for methionine and it also acts as initiator codon.AUG is seen at the beginning of the polypeptide chain.
(iv)UAG does not code for any amino acid hence iscalled stop codon and leads to end of translation.No amino acid is coded by UAG in the polypeptide chain given.
31.

a. Name the molecule ‘X’ synthesised by ‘i’ gene. How does this molecule get inactivated ? b. Which one of the structural genes codes for β-galactosidase ? c. When will the transcription of this gene stop ?

Answer»

a. The molecule ‘X’ is repressor. It gets inactivated when lactose (inducer) binds with the repressor molecule. 

b. z gene codes for β-galactosidase. 

c. Transcription of the gene stops when lactose is absent and thus repressor is free to bind with the operator.

32.

With the help of the Figure given, explain the processing of hnRNA to mRNA in eukaryotes.

Answer»

(1) Splicing-the introns are removed and exons are joined together. 

(2) capping -methyl guanosine triphosphate is added to the 5-end of hnRNA.

(3) Tailing- adenylate residues (200-300) are added at 3-end in a template

After these three process, fully processed mRNA is released from nucleus into cytoplasm for protein synthesis.

33.

Green revolution mainly aims for growing(a) disease resistance variety(b) semi dwarf variety(c) self fertilizing variety(d) none of the above

Answer»

(b) semi dwarf variety

34.

In some animals productivity is lost due to continuous inbreeding process1. Name the breeding strategy is used to overcome productivity loss2. Name the breading technique used to produce heterozygous off springs

Answer»

1. Out crossing

2. Cross breeding

35.

Write the advantages and disadvantages of inbreeding.

Answer»
AdvantagesDisadvantages
Increase homozygpsityExpose harmful recessive genes
Evolve pure lineContinued inbreeding reduces fertility
Accumulation of desirable gene and elimination of less desirable geneInbreeding depression
36.

Due to inbreeding depression fertility and productivity of animals are lost. Which is the best method used to overcome these?

Answer»

Out crossing

37.

How is hnRNA processed to form mRNA?

Answer»

The hnRNA undergoes the following processes to form mRNA: 

i. Capping: Addition of methyl guanosine triphosphate at 5'-end. 

ii. Tailing: Addition of 200-300 adenylate residues at 3'-end. 

iii. Splicing: Removal of introns and rejoining of exons.

38.

Explain the process of protein synthesis from processed m-RNA.

Answer»

For initiation the ribosome binds to the mature,mRNA at the start codon (AUG) that is recognized by , the initiator t-RNA During elongation charged tRNA sequentially binds to the appropriate codon in m-RNA with the anticodon present on tRNA. The ribosome moves from one codon to another adding amino acids one after the other to form polypeptide,i.e. translation. During termination the release factor binds to stop codon (UAA, UAG, UGA), terminating translation and releasing the polypeptide chain.

39.

Write the role of “untranslated regions” on mRNA segment play in protein synthesis?

Answer»

They are needed for efficient translation

40.

Hisardale is the superior breed of sheep developed by(a) cross breeding(b) genetic engineering(c) somatic hybridization(d) inbreeding

Answer»

(a) cross breeding

41.

Breeding between animals of the same breed is called inbreeding. Write the steps of inbreeding.

Answer»

1. Identifies superior male and female of the same breed.

2. Mate them in pairs.

3. Identifies the superior male and female of the progeny for further mating.

4. Select the best breed.

42.

Explain the process of protein synthesis from processed mRNA.

Answer»

Translation 

▪ Translation is the process of synthesis of protein from mRNA with the help of ribosome. 

▪ A translational unit in mRNA from 5' → 3' comprises of a start codon, region coding for a polypeptide, a stop codon and untranslated regions (UTRs) at both 5'-end and 3'-end for efficient process. 

▪ There are three stages of protein synthesis: 

i. Initiation 

• Assembly of ribosome on mRNA. 

• Activation of amino acids and its delivery to tRNA 

ii. Elongation 

• Repeated cycle of amino acid delivery. 

• Peptide bond formation and movement along the mRNA called translocation. 

iii. Termination 

• The release of a polypeptide chain. 

i. Initiation 

• In prokaryotes, initiation requires the large and small ribosome subunits, the mRNA, initiation tRNA and three initiation factors (IFs). 

• Activation of amino acid: Amino acids become activated by binding with aminoacyl tRNA synthetase enzyme in the presence of ATP. 

• Transfer of amino acid to tRNA: The AA–AMP–Enzyme complex formed reacts with specific tRNA to form aminoacyl-tRNA complex. AA–AMP– Enzyme complex + tRNA → AA–tRNA + AMP + Enzyme. 

• The cap region of mRNA binds to the smaller subunit of ribosome. 

• The ribosome has two sites, A-site and P-site. 

• The smaller subunit first binds to the initiator mRNA and then binds to the larger subunit so that initiation codon (AUG) lies on the P-site. 

• The initiation tRNA, i.e., methionyl tRNA then binds to the P-site. 

ii. Elongation of polypeptide chain 

• Another charged aminoacyl tRNA complex binds to the A-site of the ribosome at the second codon. 

• A peptide bond is formed between carboxyl group (—COOH) of amino acid at P-site and amino group (—NH) of amino acid at A-site by the enzyme peptidyl transferase. 

• The ribosome slides over mRNA from codon to codon in the 5′→3′ direction. 

• According to the sequence of codons, amino acids are attached to one another by peptide bonds and a polypeptide chain is formed. 

iii. Termination of polypeptide 

• When the A-site of ribosome reaches a termination codon which does not code for any amino acid, no charged tRNA binds to the A-site. 

• Dissociation of polypeptide from ribosome takes place, which is catalysed by a ‘release factor’. 

• There are three termination codons namely UGA, UAG and UAA.

43.

Differentiate between the Inducer and repressor in lac operon.

Answer»

Inducer and repressor in lac operon :

Inducer : Lactose is the substrate for the enzyme beta-galactosidase, and it regulates switching on and off of the operon. It is termed as Inducer. 

Repressor : The repressor of the operon is synthesized (all the time constitutively) from the gene. The repressor protein binds to the operator region of the operon and prevents RNA polymerase from transcribing the operon.

44.

Hisaradale is a new breed of sheep developed in Punjab by cross-breeding. Name its parents.

Answer»

Hisardale is a new breed of sheep developed in Punjab by crossing Bikaneri ewes and Marino rams

45.

Which gene acts as a regulatory gene in lac operon?

Answer»

Repressor protein is produced by the action of gene i (inhibitor). This gene acts as a regulator gene.

46.

The sequence of structural gene in Lac operon concept is(a) Lac A, Lac Y, Lac Z(b) Lac A, Lac Z, Lac Y (c) Lac Y, Lac Z, Lac A (d) Lac Z, Lac Y, Lac A

Answer»

(d) Lac Z, Lac Y, Lac A

47.

Explain the role of regulatory gene, operator promoter and structural genes in lac operon when E. Coli is growing in a culture medium with the source of energy as lactose.

Answer»

An operon is a part of DNA that functions as a gene regulatory unit in transcription. 

(a) Regulatory gene : This gene controls the operator gene. This produces a protein substance known as represser which combines with the operator gene to stop its function. 

(b) Operator : It controls the functioning of structural genes which are expressed when operate, gene is turned on by inducer and not expressed when operates is turned off by repressor. 

(c) Promoter : It is the site at which the RNA polymerase binds and reaches the structural genes for the transcription of mRNA to start. 

(d) Structural genes : These genes produce mRNA which synthesize the specific proteins such as enzyme regained for metabolism of Lactose.

48.

Where do transcription and translation occur inside a living cell? Briefly describe the three steps involved in the process of translation ?

Answer»
ProkaryotesEukaryotes
TranscriptionOccurs in cytosolOccurs in nucleus
TranslationOccurs in cytosolOccurs in cytoplasm

Translation 

▪ Translation is the process of synthesis of protein from mRNA with the help of ribosome. 

▪ A translational unit in mRNA from 5' → 3' comprises of a start codon, region coding for a polypeptide, a stop codon and untranslated regions (UTRs) at both 5'-end and 3'-end for efficient process. 

▪ There are three stages of protein synthesis: 

i. Initiation 

• Assembly of ribosome on mRNA. 

• Activation of amino acids and its delivery to tRNA 

ii. Elongation 

• Repeated cycle of amino acid delivery. 

• Peptide bond formation and movement along the mRNA called translocation. 

iii. Termination 

• The release of a polypeptide chain.

49.

A number of personnel were deputed by municipal corporation to check mosquito breeding in your school. On the basis of this information answer the following questions : (i) What places they should search for checking mosquito breeding? (ii) Name two diseases caused by mosquitoes. (iii) Name any two biological agents which can bring about the biological of mosquitoes.

Answer»

(i) Stagnant water bodies, water tanks, flower pots etc. should be searched for checking mosquitoes breeding.

(ii) Malaria, Dengue

(iii) Gambusia, Dragonfly which feeds on mosquito larva and thus eliminates the mosquitoes.

50.

Give an example of a new breed each of cattle and poultry.

Answer»

Jersey/Hissardale—a new breed by crossing Bikaneri ewes and Mirano rams (cattle) and Leghorn (poultry).