Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Laughing gas is produced from zine react with

Answer»

DILUTE `HNO_(3)`
Conc. `HNO_(3)`
Dilute `H_(2)SO_(4)`
`HNO_2`

ANSWER :A
Discussion
2.

Laughing gas is prepared by heating:

Answer»

`NH_4Cl`
`(NH_4)_2CO_4`
`NH_4Cl+ NaNO_2`
`NH_4NO_3`

ANSWER :D
Discussion
3.

Laughing gas is obtained when a mixture of NH_(4)Cl and ............ Is heated while nitrogen gas is obtained when a mixture of NH_(4)Cl and ............. Is heated.

Answer»

SOLUTION :`NaNO_(3), NaNO_(2)`
Discussion
4.

Laughing gas is prepared by heating :

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`NH_(4)NO_(3)`
`(NH_(4))_(2)SO_(4)`
`NaNO_(2)+NH_(4)Cl`
`HNO_(3)`.

ANSWER :A
Discussion
5.

Lattice enthalpy of an ionic compound depends upon

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Charge on the ion only
Size of the ion only
Packing of ions only
Charge on the ion and size of the ion.

Solution :`SF_(4)` (`SP^(3)d`hybridisation)has see SAW geometry with 1 LONE pair`CF_(4)`(`sp^(3)` hybridisation) has TETRAHEDRAL geometry with 0 lone pair
`XeF_(4)`(`sp^(3)d^(2)`hybridisation) has octahedral shape with 2 lone pairs.
Discussion
6.

Lattice energy for an ionic compound is calculated by using

Answer»

Kirchoff's equation
MARKOWNIKOFF's rule
Born HABER CYCLE
Carnot cycle

Answer :B
Discussion
7.

Latic acid on oxidation with fenton 'sreagent gives the main product

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OXALIC ACID
PYRUVIC acid
succinic acid
ACETIC acid

ANSWER :A
Discussion
8.

Latex is acolloidal solution of rubber particles which are

Answer»

POSITIVELY CHARGED
NEGATIVELY charged
neutral
can be negatively and positivelycharged.

ANSWER :B
Discussion
9.

Latest techniquue for purification, isolation and separation of organic compounds:

Answer»

charomatography
STEAM DISTILLATION
CRYSTALLISATION
VACUUM distillation

SOLUTION :N//A
Discussion
10.

Latent heat of vaporisation of a liquid at 500K and 1 atm pressure is 10.0 kcal/mol. What will be the change in internal energy(triangleE) of 3 mole of liquid at same temperature:

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13.0 KCAL
`-13.0 kcal`
27.0 kcal
`-27.0 kcal`

ANSWER :C
Discussion
11.

Latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10 kcal//mol. What will be the change in internal energy (DeltaU) of 3 mol of liquid at the same temperature ?

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13.0 kcal
`-13.0 kcal`
27.0 kcal
`-27.0 kcal`

Solution :`DELTA H` = 10.0 kcal for one mole
`Delta H` = 30.0 kcal for three moles
`"Liquid" hArr "Vapours"`.
`Delta U = Delta H - Delta n_(G) RT`
`= 30.0 - 3 XX 1.98 xx 10^(-3) xx 500`
= 30 - 3
= 27.0 kcal
Discussion
12.

latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10 .0 kcal/ mol . What will be the change in internal energy (DeltaE) of 3 moles of liquid at same temperature ?

Answer»

30 KCAL
`-54 kcal`
27.0 kcal
50 kcal

Solution :`DeltaH=DeltaE+Deltan_(G) RT, 30 = 30 DELTA + 3xx2xx500xx10^(-3)`
`DeltaE=27 kcal`
Discussion
13.

Latent heat of fusion of ice is "1436.3 cal mol"^(-1). Calculate the molal depression constant of water.

Answer»

Solution :`K_(f)=(M_(1)RT_(0)^(2))/(1000Delta_("FUS")H)=("18 GMOL"^(-1)XX"2 cal K"^(-1)"mol"^(-1)xx(273 K)^(2))/("1000 g kg"^(-1)xx"1436.3 cal mol"^(-1))`
`="1.87 K kg mol"^(-1)`
Discussion
14.

Late discovery of F_2 is due to its:

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HIGH reactivity
High IONIZATION potential
High electronegativity
High ELECTRON affinity

Answer :A
Discussion
15.

Lassigne's test is used to detect

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NITROGEN and halogens
Sodium and halogens
Halogensand sulphur
All the above

Solution :N//A
Discussion
16.

Last element of group-IV is found to be

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STRONG metallic
Weak metallic
Strong non-metallic
Weak non-metallic

Answer :B
Discussion
17.

Lassaigne's test is used in qualitative analysis to detect

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Nitrogen
Sulphur
Chlorine
All of these

Solution :N//A
Discussion
18.

Lassaigne's test is used in qualitative analysis to detect :

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NITROGEN
SULPHUR
CHOLRINE
all of these

Solution :N//A
Discussion
19.

Lassaigne's test for the detection of nitrogen will fall in the case of

Answer»



`NH_(2)-NH_(2).HCl`

Solution :For lassaigne's test organic, compound must `N` in ADDITION to CARBON to form `NACN` in sodium EXTRACT.
Discussion
20.

Lassaigne's test for the detection of nitrogen will fail in the case of :

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`NH_(2)CONH_(2)`
`NH_(2)CONHNH_(2).HCl`
`NH_(2)NH_(2).HCl`
`C_(6)H_(5)NHNH_(2).2HCl`

SOLUTION :`NH_(2)-NH_(2)` (Inorganic compound give -ve Lassigne's test)
Discussion
21.

Lassaigne's test for the detection of nitrogen will fail in case of :

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`NH_(2)CONH_(2)`
`NH_(2)CONHNH_(2).HCl`
`NH_(2)NH_(2).HCl`
`C_(6)H_(5)NHNH_(2).2HCl`

ANSWER :C
Discussion
22.

Lassaigne's extract of m-nitrochlorobenzene is acidified with dil. HNO_(3) and then treated with AgNO_(3) solution, the white precipitate formed is due to :

Answer»

AgCl
AGCN
both (a) and (B)
`Ag_(2)O`

Solution :DUE to AgCl and AgCN
Discussion
23.

Lassaigne's solution gives violet colouration with sodium nitroprusside. It indicates the presence of :

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Nitrogen
Sulphur
Halogens
Both N and S

Answer :B
Discussion
24.

LAS is which type of detergent ?

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Bio-hard
Anionic
Cationic
Non-ionic 

ANSWER :B
Discussion
25.

Largest size stands for:

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`CL^-`<BR>`Br^-`
`Br^+`
`Br`

ANSWER :B
Discussion
26.

Largest in size out of Na^(+),Ne and F^(-) is:

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`NA^(+)`
`NE`
`F^(-)`
all are equal

Answer :B
Discussion
27.

Larger polymers of alpha-amino acids are called _____.

Answer»


ANSWER :PROTEINS
Discussion
28.

Larger no. oxidation states are exhibited by Actinides than those by Lanthanides. The main reason being.

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Lesser energy differene between 5f and 6D than 4f and 5D ORBITAL.
POOR shielding of 5d-orbital than 6d orbital.
LOW ionization energy of Lanthanides.
Penetration of d is more than 5d orbital. 3

Answer :A
Discussion
29.

Large number ofoxidation states are exhibited by the actinoids than those by the lanthanoids, the main reason being.

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more energy DIFFERENCE between 5d and 6D than between 4f and 5d ORBITALS
more reactive nature of the antinoids than the lanthanoids
4f orbitals more diffusedthan the 5f orbitals
lesser energy difference between 5f and 6d than between 4f and 5d orbitals.

Answer :d
Discussion
30.

Large molecules can be formed by the combination of a number of smaller molecules. These smaller molecules are called

Answer»

isomer
monomers
epimer
polymers

Answer :B
Discussion
31.

Large energy released in an atomic bomb explosion is mainly due to

Answer»

PRODUCTS having a lesser mass than initial substance
Conversion of HEAVIER to LIGHTER atoms
Release of neutrons
Relase of electrons

Solution :Mass decay occurs
Discussion
32.

Lapis Lazuli is a blue coloured mineral used as valuable artificial.gemstone. It is:

Answer»

cryolite
sodium ALUMINOSILICATE
 BASIC COPPER acetate
basic CHROMIUM carbonate

Answer :B
Discussion
33.

Large deposite of sulphur in nature are found in the form of:

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FLOWERS of SULPHUR
`H_2SO_4`
`H_2SO_3`
FREE sulphur

Answer :D
Discussion
34.

Lanthenoid (Ln) is known for its +3 oxidation state. Which of the following statement is not applicable?

Answer»

Ionic volume (RADII) DECREASES as atomic number increases
The COMPOUNDS of LN(III) are most of coloured
Hydroxides of Ln(III) are most of basic
As volume of Ln(III) is more their compounds possess ionic nature

Answer :B
Discussion
35.

Lanthanoids are placed in

Answer»

`3^(rd)` GROUP and `7^(th)` period
`3^(rd)` group and `6^(th)` period
`4^(th)` group and `7^(th)` period
`3^(rd)` group and`5^(th)` period

Answer :A::B::C::D
Discussion
36.

Lanthanoids are

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14 ELEMENTS in the sixth period (ATOMIC no. 90 to 103) that are FILLING 4f sublevel
14 elemenets in the seventh period (atomic number = 90to103) that are filling 5f sublevel
14 elements in the sixth period (atomic number = 58to71) that are filling the 4f sublevel
14 elements in the seventh period (atomic number = 50 to 71) that are filling 4f sublevel

Answer :C
Discussion
37.

Lanthanoids are-

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14 elements in the sixth period (atomic no. 90 to 103)that are filling4f sublevel
14 elements in the seventh period (atomic no.90 to 103 ) that are filling5f sublevel
14 elements it the sixth period (atomic no.58 to 71) that are FILLING the 4f sublevel
14 elements in theseventh period (atomic no. 50 to 71) that are filling 4f sublevel.

Answer :C
Discussion
38.

Lanthanoids and actinoids resembles in….

Answer»

OXIDATION states
electronic configuration
formation of complexes
ionisation state

Answer :B
Discussion
39.

Lanthanoids are :

Answer»

14 elements in the seventh period (at. Nos. 90 to 103) that are filling 5f sublevel.
14 elements in the sixth period (at. Nos. 58 to 71) that are fiiling 4F sublevel.
14 elements in the seventh period (atmoic nos. 58 to 71) that are filling 4f sublevel.
14 elements in the sixth period (at nos. 90 to 103) that are filling 4f sublevel.

Answer :C
Discussion
40.

Lanthanoids and actinoids are f-block elementsIt is difficult to separate lanthanoids in the pure state. Explain.

Answer»

Solution :Lanthanoids have SIMILAR size DUE to lanthanoid contraction. They all have similar outer electronic arrangement. So these elements are ALMOST similar in their chemical properties and HENCE the separation of individual lanthanoid elements is DIFFICULT.
Discussion
41.

Lanthanoide contraction affects on

Answer»

basicity of LANTHANOIDE hydroxides
atomic and ions radii of POST lanthanoide
similarty in properties of `2 ^(ND) and 3 ^(rd)` ROW TRANSITION elements
all of these

Answer :D
Discussion
42.

Lanthanoids and actinides resemble in :

Answer»

ELECTRONIC configuration
Oxidation STATES
LONISATION energy
None of these.

ANSWER :D
Discussion
43.

Lanthanoid contraction will not have any influence when we compare size of :-

Answer»

ZR & Hf
Y & La
MO & W
TC & Re

ANSWER :B
Discussion
44.

Lanthanoid contraction implies

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DECREASE in density
Decrease in mass
Decrease in ionic radii
Decrease in radioactivity

Solution :DECREASES in atomic radius
Discussion
45.

Lanthanoid contraction means :

Answer»

small atomic sizes of lanthanoid elements
small ionic size of lanthanoid ions.
smaller atomic size of lanthanoids as COMPARED to TRANSITION element in the sameperiod
decrease in atomic and ionic radii of the element of lanthanoid series in moving from LEFT to the RIGHT.

Solution :is the correctanswer
Discussion
46.

Lanthanides like Eu and Yb can form hydrodes like EuH_2 and YbH_2. These hydrides are

Answer»

IONIC HYDRIDES
Covalent hydrides
Metallic hydrides
Intermediate hydrides

Solution :EU,YB, can FORM Ionic hydrides
Discussion
47.

Lanthanidwes shows variable oxidation state, because they release electron from the following orbitals

Answer»

4f
6S
5d
all of these

Solution :We know that, lanthanide shows `+2,+3,+4.` O.S. by loss of TWO, THREE and four electrons. These electrons MAY be rmoved from 6s, 4f and 5d orbitals.
Discussion
48.

Lanthanoid contraciton can be observed in

Answer»

At
GD
Ac
Lw

Solution :AMONGST the GIVEN ELEMENTS, only Gd is LANTHANIDE.
Discussion
49.

Lanthanides does not show +4 O. S. in which of the following configuration

Answer»

`f^(0)`
`f ^(7)`
`f ^(14)`
all of these

Solution :Lanthanides show +4 O.S. in `f ^(0), and f^(7)` CONFIGURATION, whereas it is POSSIBLE to attend stable electronic configuration. i.e., `(+3` to `+4`) But they does not show +4 O.S. in `4f^(14)` configuration because, by lose of three electrons they already ACQUIRE `4f^(14)` configuration i.e. `(+3` to `+4)` O.S. Hence `+4` O.S. is not possible in `4f^(14)` configuration.
Discussion
50.

Lanthanides are characterized by the filling of the

Answer»

penultimate 4F energy LEVEL
antepenultimate 4f energy level
penultimate 5F energy level
antepenultimate 5f energy level

Answer :B
Discussion