latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is – InterviewSolution

1.	latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10 .0 kcal/ mol . What will be the change in internal energy (DeltaE) of 3 moles of liquid at same temperature ?
Answer» 30 KCAL `-54 kcal` 27.0 kcal 50 kcal Solution :`DeltaH=DeltaE+Deltan_(G) RT, 30 = 30 DELTA + 3xx2xx500xx10^(-3)` `DeltaE=27 kcal`

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