94420 + Interview Questions in Chemistry in Class 12

1.	Lanthanides are able to show oxidation states
Answer» only `+3` only `+4` only `+2 and+3` both `+2 , +3 and +4` ANSWER :D

Discussion

2.	Lanthanides are
Answer» 14 elements in the `7^(th)` PERIOD filling 4f orbitals 14 elements in the `5^(th)` period filling 5T orbitals 14 element in the `5^(th)` period filling 5t orbitals 14 elements in the `4^(th)` period that are filling 4f orbitals ANSWER :B

Discussion

3.	Lanthanides and actinides are also called as
Answer» SHORT periods inner TRANSITION elements long periods main transition elements. Answer :B

Discussion

4.	Lanthanide for which +2 and +3 oxidation states are common is
Answer» La Nd Ce Eu Solution :`Gd=[XE] 4F^(7) 5d^(1) 6S^(2)`

Discussion

5.	Lanthanide do not show oxidation state
Answer» `+3` `+4` `+6` `+2` ANSWER :C

Discussion

6.	Lanthanide contraction occurs because (1) f-orbital are incompletely filled (2) f-orbital electrons are easily lost (3) f-orbital do not come out on the surface of atom and are buried inside (4) f-orbital electron are poor sheilders of nuclear charge
Answer» SOLUTION :Key: 4 The size of lanthanides are smaller than expected. This is associated with the filling up of 4f orbitals which MUST be filled before the 5d orbitals. The electrons in f-orbitals are not EFFECTIVE in screening other electrons from the nuclear charge.

Discussion

7.	Lanthanide contraction is related to
Answer» VALENCE electron IONIC radii densities NUCLEAR MASS of various membere of the series Answer :B

Discussion

8.	Lanthanide contraction is observed in
Answer» Gd At Xe Ac Answer :A

Discussion

9.	Lanthanide contraction is due to increase in
Answer» shielding of 4f electrons EFFECTIVE NUCLEAR charge atomic NUMBER size of 4f orbital ANSWER :B

Discussion

10.	Lanthanide contraction is due to ___
Answer» IMPERFECT SHIELDING an outer electrons by 4f electrons from the NUCLEAR charge. effective shielding by 4f electron on the VALENCE shell electrons greater shielding of 5d electrons by 4f electrons from the nuclear charge appreciable shielding on outer electrons by 4f electrons from the nuclear charge Answer :A

Discussion

11.	Lanthanide contraction due to
Answer» POOR SHIELDING of 5F ORBITALS poor shielding of 3F orbitals prerfect shielding of 4f orbitals poor shielding of 4f orbitals Answer :D

Discussion

12.	Langmuir adsorption isotherm is deduced using at assumption
Answer» The adsorbed molecules interact with each other The ADSORPTION takes place in multi layers The adsorption sites are equivalent in their ability to adsorb the particles The heat of adsorption varies with the coverage Solution :LANGMUIR adsorption isotherm is based on the assumption that EVERY adsorption site is equivalent and that the ability of a particle to bind there is independent of WHETHER NEARBY sistes are occupied or not .

Discussion

13.	Lantanide series arises due to
Answer» stability of 6s-orbitals stability of 5D-orbitals stability of 4f-orbitals EQUAL stability of 5d and 4f-orbitals Solution :We know that, in `6^(th)` row after 6s-orbitals. At this stage 5d-orbitals stop its spliting and 4f-orbitals, split into 7 orbitals, and BECOME lower energy than, 5d-orbitals. Hence 4f-orbital are progressively filled and 14 new ELEMENTS are added called as lanthanides.

Discussion

14.	Lamitic acid is
Answer» `C_(16)H_(31)COOH` `C_(17)H_(35)COOH` `C_(15)H_(31)COOH` `C_(17)H_(31)COOH` Solution :Formula of palmitic ACID is `C_(15)H_(31)COOH`.

Discussion

15.	lamda^(oo) of NH_4OH at infinite dilution is ______Scm^2 eq^(-1) given lamda^(oo)of OH^(-) = 174 , lamda^(oo) of OH^(-) = 174 , lamda^(oo) of Cl = 66 and lamda^(oo) of NH_4Cl = 130 Scm^2eq^(-1)
Answer» 140 218 328 198 Answer :C

Discussion

16.	Lamda_(m(NH_(4)OH))^(@) is equal to_____
Answer» `Lamda_(m(NH_(4)OH))^(@)+Lamda_(m(NH_(4)Cl))^(@)-Lamda_((HCl))^(@)` `Lamda_(m(NH_(4)Cl))^(@)+Lamda_(m(NAOH))^(@)-Lamda_((NaCl))^(@)` `Lamda_(m(NH_(4)Cl))^(@)+Lamda_(m(NaCl))^(@)-Lamda_((NaOH))^(@)` `Lamda_(m(NaOH))^(@)+Lamda_(m(NaCl))^(@)-Lamda_((NH_(4)Cl))^(@)` Solution :* `NH_(4)Cl` is strong electrolyte. * According to KOHLRAUSCH LAW, limiting molar conductivity of electrolyte is the summation of positive and negative IONS, which are two individual ions PRESENT in the solution.

Discussion

17.	Lamda_(m)^(@)(H_(2)O) is equal to ______
Answer» `Lamda_(m(HCL))^(@)+Lamda_(m(NaOH))^(@)-Lamda_(m(NaCl))^(@)` `Lamda_(m(HNO_(3)))^(@)+Lamda_(m(NaNO_(3)))^(@)-Lamda_(m(NaOH))^(@)` `Lamda_(m(HNO_(3)))^(@)+Lamda_(m(NaOH))^(@)-Lamda_(m(NaNO_(3)))^(@)` `Lamda_(m(NH_(4)OH))^(@)+Lamda_(m(HCl))^(@)-Lamda_(m(NH_(4)Cl))^(@)` Solution :This problem is based on the concept of Kohlrausch law of independent MIGRATION of IONS : `(lamda_(m)^(@))` is the sum of limiting MOLAR conductivities of cation `lamda_(+)^(@)` and anion `lamda_(-)^(@)`. `Lamda_(m(H_(2)O))^(@)=lamda_(m(H^(+)))^(@)+lamda_(m(OH^(-)))^(@)` The value of `lamda_(m(H^(+)))^(@)` is OBTAINED from the `Lamda_(m(HCl))^(@)` and value of `lamda_(m(OH^(-)))^(@)` is obtained from the `Lamda_(m(NaOH))^(@)` but by doing so `lamda_(m(Na^(+)))^(@)` and `lamda_(m(Cl^(-)))^(@)` are added. So to eliminate them `Lamda_(m(NaCl))^(@)` should be subtracted.

Discussion

18.	lamda_(ClCH_(2)COONa)=224ohm^(-1)cm^(2)gmeq^(-1) lamda_(NaCl)=38.2ohm^(-1)cm^(2)gmeq^(-1) lamda_(HCl)=203ohm^(-1)cm^(2)gmeq^(-1) What is the value of lamda_(ClCH_(2)COOH)
Answer» 288.5 `OHM^(-1)cm^(2)gmeq^(-1)` 289.5 `ohm^(-1)cm^(2)gmeq^(-1)` `388.8ohm^(-1)cm^(2)gmeq^(-1)` 59.5 `ohm^(-1)cm^(2)gmeq^(-1)` Solution :`ClCH_(3)COONa+HCltoClCH_(3)COOH+NACL` `lamda_(ClCH_(3)COONa)+lamda_(HCL)=lamda_(CiCH_(2)COOH)+lamda_(NaCl)` ltBrgt `224+203=lamda_(ClCH_(2)COOH)+38.2` `lamda_(ClCH_(3)COOH)=427-38.2=388.8ohm^(-1)cm^(2)gmeq^(-1)`.

Discussion

19.	Lambda_(m(NH_(4)OH)^(@) is equal to -
Answer» `Lambda_(m(NH_(4)OH))^(@)+Lambda_(m(NH_(4)CL))^(@)-Lambda_(HCl)^(@)` `Lambda_(m(NH_(4)Cl))^(@)+Lambda_(m(NaOH))^(@)-Lambda_(m(NaCl))^(@)` `Lambda_(m(NH_(4)Cl))^(@)+Lambda_(m(NaCl))^(@)-Lambda_(m(NaOH))^(@)` `Lambda_(m(NaOH))^(@)+Lambda_(m(NaCl))^(@)-Lambda_(m(NH_(4)Cl))^(@)` ANSWER :B

Discussion

20.	lamda_m^0for NaCl,HCL and NaAc are 126.4,425.9and91.0Scm^2mol^(-1)respectively. Calculate^^_m^0for Hac.
Answer» SOLUTION :`^^_m^0(HA_C)=lamda_m^0(NAAC)+lamda_m^0(HCL)-lamda_m^0(NACL)` `=91+425.9-126.4=390.5Scm^2mol^(-1)`

Discussion

21.	Lambda_(m)^@ values of the weak electrolytes can be determined using .................... .
Answer» SOLUTION :Kohlraush.s LAW

Discussion

22.	Lambda_(m)^(@) values of KCl and KNO_(3) is 149.86 and "154.96 ohm"^(-1)."cm"^(-1)."mol"^(-1). If lambda_(m)^(@)(Cl^(-))? ="71.44 ohm"^(-1)."cm"^(2)."mol"^(-1), calculate lambda_(m)^(@)(NO_(3)^(-)).
Answer» SOLUTION :`"76.54 OHM"^(-1)"CM"^(-1)"MOL"^(-1)`

Discussion

23.	lambda_m^(@)(AgNO_3), lambda_m^(@)(HCl) and lambda_m^(@)(HNO_3) are a,b and c S cm^(2) mol^(-1) respectively . If the conductivity of a saturated solution is Z S cm^(-1) . Then the solubility of AgCl is
Answer» `(a+B+c)/(1000 MZ)` `((a+b+c)1000)/(Z)` `(1000Z)/(a+b-c)` `(Z(a+b-c))/(1000M)` SOLUTION :`^^_(Mg) = ^^_(M) " of " -^^_(Mg) + ^^_(Mg) ,2AgCl = AgNO_3 HNO_3 HCl = (a+ b -c)` ` S = M = (K xx 1000)/(^^_M) , S = [(Z xx 10^(3))/((a + b -c))]`

Discussion

24.	lambda_(m)^(@) for NaCl, HCl and CH_(3)COONa are 126.4,425.9 and "91.0 S cm"^(2)//"mol" respectively. Calculate lambda_(m)^(@)" for "CH_(3)COOH.
Answer» SOLUTION :`lambda_(m_(CH_(3)COOH))^(@)=lambda_(CH_(3)COONA)^(@)+lambda_(HCl)^(@)-lambda_(NaCl)^(@)=91+425.4-126.4=390.5scm^(3)//mol`

Discussion

25.	lambda_(CICH_(2)COONa)=224ohm^(-1)cm^(2) gm eq^(-1) lambda_(NaCl)=38.2 ohm^(-1)cm^(2) gm eq^(-1) lambda_(HCl)=203 ohm^(-1)cm^(2)gm eq^(-1), what is the value of lambda_(CICH_(2)COOH)?
Answer» `288.5ohm^(-1)cm^(2)gm eq^(-1)` `289.5ohm^(-1)ohm^(-1)cm^(2)gmeq^(-1)` `388.8ohm^(-1)cm^(2)gmeq^(-1)` `59.5ohm^(-1)cm^(2)gmeq^(-1)` SOLUTION :`lambda_(ClCH_(2)COOH)=lambda_(ClCH_(2)COONa)+ lambda_(HCl)-lambda_(NACL)` `=(224+203-38.2)ohm^(-1)cm^(2)(g eq^(-1))` =`388.8ohm^(-1)cm^(2)(g eq^(-1))`

Discussion

26.	lambda_(c)=mu_(c) for,
Answer» NACL `H_(2)SO_(4)` `Na_(2)SO_(4)` `Al_(2)(SO_(4))_(3)` ANSWER :A

Discussion

27.	lambda_(HCN) is 0.1M solution is20S m^(2) " mol"^(-1) lambda_(HCN)^(@)is 200S m^(2) "mol"^(-1) . The P^(H) of 0.1M HCN solution is ____________
Answer» SOLUTION :`ALPHA = (^^_(HCN))/(^^_(HCN)^(0)) = (20)/(200) = 10^(-1) , [H^(oplus)] = C alpha = 0.1 XX 10^(-1) = 10^(-2) , P^(H) =2 `

Discussion

28.	Lambda_(ClCH_(2)COONa)^(@)=224 Ohm^(-1)cm^(2)g meq^(-1), Lambda_(NaCl)^(@)=38.2Ohm^(-1)cm^(2)gm eq^(-1), Lambda_( HCl)^(@)=203Ohm^(-1)cm^(2)gm eq^(-1). What is the value of L_(ClCH_(2)COOH)^(@) ?
Answer» `288.5 Ohm^(-1)CM^(2)gm EQ^(-1)` `289.5 Ohm^(-1)cm^(2)gm eq^(-1)` `388.8 Ohm^(-1)cm^(2)gm eq^(-1)` `59.5 Ohm^(-1)cm^(2)gm eq^(-1)` ANSWER :C

Discussion

29.	Lambda_(c) of acetic acid at 25^(@)C is 16.3 ohm^(-1)cm^(2)eq^(-1).The ionic conductances of H^(+) andCH_(3)COO^(-) are 349.83and 40.89 ohm^(-1).What is prop ofCH_(3)COOH ?
Answer» ANSWER :`0.04072`

Discussion

30.	Lake Cayuga has a volume of water estimated to be 8.2 xx 10^(12) litres. A power station not so far above Cayuga's waters produces electricity at the rate of 1.5 xx 10^(6) coulombs per second at an appropriate voltage. How long would it take to electrolyse the kale ?
Answer» ANSWER :1.9 MILLION YEARS

Discussion

31.	Lake of oxygen at high altitude produces :
Answer» Bends Anoxia Asthma Artificial respire Answer :B

Discussion

32.	Lake Cayuga has a volume of water estimated to be 8.2 xx 10^(12)" Litre." A power station not so far above. Cayuga's water produces electricity at a rate of 1.5 xx 10^(6) Coulomb per second at an appropriate voltage. How long would it take to electrolyse the lake?
Answer» `1.86 X 10^(6)" YEARS"` 1.86 years `0.93 xx 10^(6)" years"` `9.3 xx 10^(6)" years"` Answer :A

Discussion

33.	Laevorotatory substance or l-Isomer.
Answer» Solution :An optically ACTIVE substance (or isomer) which ROTATES the PLANE of a plane polarized light to the left hand SIDE (LHS) is called laevorotatory substance (or isomer) and denoted by l or `(-)` SIGN.

Discussion

34.	Lactose on hydrolysis produces
Answer» `BETA`-D-glucose and `beta`-D-galactose `ALPHA`-D-glucose and `alpha`-D-galactose `beta`-D-glucose and `alpha`-D-galactose Answer :A

Discussion

35.	Lactose on hydrolysis yields :
Answer» Two GLUCOSEMOLECULES Two galactose MOLECULE A galactose and FRUCTOSE molecule A galactose and a GLUCOSE molecule Answer :D

Discussion

36.	Lactose on hydrolysis gives
Answer» TWO MOLECULES of GLUCOSE glucose and FRUCTOSE two molecules of fructose glucose and GALACTOSE Solution :glucose and galactose

Discussion

37.	Lactose has thesame molecular formula as :
Answer» Glucose Maltose Laevulose Galactose ANSWER :B

Discussion

38.	Lactose has …………………..
Answer» only `ALPHA`-D-Glucose `alpha`-D-Glucose and `BETA`-D-Glucose `alpha`-D-Glucose and `beta`-D-Galactose `alpha`-D-Glucose and `alpha`-D-Glucose SOLUTION :`alpha`-D-Glucose and `beta`-D-Galactose

Discussion

39.	Lactose can be names as
Answer» `BETA`-D-glucopyanosyl `beta`-D-galactospyranose `ALPHA`-D-glucospyranosyl `alpha`-D-galactospyranose `beta`-D-galactopyranosyl `beta`-D-glucopyranose `alpha`-D-galactopyranosyl `alpha`-D-glucopyranose Answer :C

Discussion

40.	Lactoseact as reducingsugar. Justifythisstatement .
Answer» SOLUTION :(i)Lactose is a disaccharideand containsone galactoseunitand oneglucos unit . (ii)In lactose ,the `beta` - DGALACTOSE`beta - D`glucoseare linked `beta - 1, 4-` glycosidic bond. (iii) Thealdehydecarbonis notinvolvedin theglycosidic bondhenceit retainsitsreducingpropertyand is calleda reducingsugar .

Discussion

41.	Lactic acid shows
Answer» metamerism optical ISOMERISM functional isomerism with aldehyde tautomerism Answer :B

Discussion

42.	Lactic acid show which type of isomerism
Answer» Geometrical ISOMERISM Tautomerism Optical isomerism Metamerism Solution :Lactic ACID SHOWS optical isomerism.

Discussion

43.	Lactic acid on oxidation with Fenton.s reagent gives main product:
Answer» `CH_3COOH` `H_2C_2O_4` `CH_3COCOOH` None Answer :C

Discussion

44.	Lactic acid on oxidation by alkaline potassium permanganate gives
Answer» Tartaric acid Pyruvic acid Cinnamic acid Propionic acid Solution :`CH_(3)-underset("LACTIC acid")(CHOH)-COOH+[O] OVERSET(KMnO_(4))to underset("Pyruvic acid")(CH_(3)-CO-COOH+H_(2)O)`

Discussion

45.	Lactic acid on oxidation with Fenton's reagent gives:
Answer» a.`CH_(3)COCOOH (Pyruvic ACID)` b.`CH_(3)COOH` C.`HOOC-UNDERSET(O)underset(\|\|)(C )-COOH` d.`HOOC-COOH` SOLUTION :It gives pyruvic acid.

Discussion

46.	Lactic acid molecule has
Answer» One CHIRAL CARBON atom Two chiral carbon atoms No chiral carbon atom An asymmetric molecule Solution :Lactic acid has ne asymmetric (chiral) carbon atom, HENCE it has `(2'=2)` OPTICAL isomers.

Discussion

47.	Lactic acid is a classical example of ___________.
Answer» POSITION ISOMERISM geometrical isomerism optical isomerism CHAIN isomerism Answer :C

Discussion

48.	Lactic acid in which a methyl group, a hydroxyl group, a carboxylic acid group and a hydrogen atom are attached to a central carbon atom, show optical isomerism due to the molecular geometry at the
Answer» Central CARBON atom Carbon atom of the methyl group Carbon atom of the CARBOXYLIC acid group Oxygen of the HYDROXYL GROUPS ANSWER :A

Discussion

49.	Lactic acid CH_3-oversetoverset(OH)(\|)C-CH-oversetoverset(O)(\|\|)C-OH can be prepared by acid hydrolysis of reaction product of
Answer» ETHANAL with HCN/KCN mixture Ethanol with `PCl_5` followed by KCN Propanal with KCN, in PRESENCE of `NH_4Cl` `CrO_3`/acetic ACID and isopropyl alcohol Solution :NA

Discussion

50.	Lactic acid and glycolic acid are the monomers used for preparation of polymer
Answer» NYLON -2-nylon -6 Dextron PHBV Buna-N Solution :`UNDERSET("Lactic acid")(HO -underset(CH_(3))underset(\|)overset(H)overset(\|)C-COOH) + HO - underset("glycolic acid")(CH_(2) - COOH) to underset("Dextron")[[O-underset(CH_(3))underset(\|)(CH)-overset(O)overset(\|\|)C-O-CH_(2) -overset(O)overset(\|\|)C]]-+nH_(2)O`

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Lanthanides are able to show oxidation states

Lanthanides are

Lanthanides and actinides are also called as

Lanthanide for which +2 and +3 oxidation states are common is

Lanthanide do not show oxidation state

Lanthanide contraction occurs because (1) f-orbital are incompletely filled (2) f-orbital electrons are easily lost (3) f-orbital do not come out on the surface of atom and are buried inside (4) f-orbital electron are poor sheilders of nuclear charge

Lanthanide contraction is related to

Lanthanide contraction is observed in

Lanthanide contraction is due to increase in

Lanthanide contraction is due to ___

Lanthanide contraction due to

Langmuir adsorption isotherm is deduced using at assumption

Lantanide series arises due to

Lamitic acid is

lamda^(oo) of NH_4OH at infinite dilution is ______Scm^2 eq^(-1) given lamda^(oo)of OH^(-) = 174 , lamda^(oo) of OH^(-) = 174 , lamda^(oo) of Cl = 66 and lamda^(oo) of NH_4Cl = 130 Scm^2eq^(-1)

Lamda_(m(NH_(4)OH))^(@) is equal to_____

Lamda_(m)^(@)(H_(2)O) is equal to ______

lamda_(ClCH_(2)COONa)=224ohm^(-1)cm^(2)gmeq^(-1) lamda_(NaCl)=38.2ohm^(-1)cm^(2)gmeq^(-1) lamda_(HCl)=203ohm^(-1)cm^(2)gmeq^(-1) What is the value of lamda_(ClCH_(2)COOH)

Lambda_(m(NH_(4)OH)^(@) is equal to -

lamda_m^0for NaCl,HCL and NaAc are 126.4,425.9and91.0Scm^2mol^(-1)respectively. Calculate^^_m^0for Hac.

Lambda_(m)^@ values of the weak electrolytes can be determined using .................... .

Lambda_(m)^(@) values of KCl and KNO_(3) is 149.86 and "154.96 ohm"^(-1)."cm"^(-1)."mol"^(-1). If lambda_(m)^(@)(Cl^(-))? ="71.44 ohm"^(-1)."cm"^(2)."mol"^(-1), calculate lambda_(m)^(@)(NO_(3)^(-)).

lambda_m^(@)(AgNO_3), lambda_m^(@)(HCl) and lambda_m^(@)(HNO_3) are a,b and c S cm^(2) mol^(-1) respectively . If the conductivity of a saturated solution is Z S cm^(-1) . Then the solubility of AgCl is

lambda_(m)^(@) for NaCl, HCl and CH_(3)COONa are 126.4,425.9 and "91.0 S cm"^(2)//"mol" respectively. Calculate lambda_(m)^(@)" for "CH_(3)COOH.

lambda_(CICH_(2)COONa)=224ohm^(-1)cm^(2) gm eq^(-1) lambda_(NaCl)=38.2 ohm^(-1)cm^(2) gm eq^(-1) lambda_(HCl)=203 ohm^(-1)cm^(2)gm eq^(-1), what is the value of lambda_(CICH_(2)COOH)?

lambda_(c)=mu_(c) for,

lambda_(HCN) is 0.1M solution is20S m^(2) " mol"^(-1) lambda_(HCN)^(@)is 200S m^(2) "mol"^(-1) . The P^(H) of 0.1M HCN solution is ____________

Lambda_(ClCH_(2)COONa)^(@)=224 Ohm^(-1)cm^(2)g meq^(-1), Lambda_(NaCl)^(@)=38.2Ohm^(-1)cm^(2)gm eq^(-1), Lambda_( HCl)^(@)=203Ohm^(-1)cm^(2)gm eq^(-1). What is the value of L_(ClCH_(2)COOH)^(@) ?

Lambda_(c) of acetic acid at 25^(@)C is 16.3 ohm^(-1)cm^(2)eq^(-1).The ionic conductances of H^(+) andCH_(3)COO^(-) are 349.83and 40.89 ohm^(-1).What is prop ofCH_(3)COOH ?

Lake Cayuga has a volume of water estimated to be 8.2 xx 10^(12) litres. A power station not so far above Cayuga's waters produces electricity at the rate of 1.5 xx 10^(6) coulombs per second at an appropriate voltage. How long would it take to electrolyse the kale ?

Lake of oxygen at high altitude produces :

Lake Cayuga has a volume of water estimated to be 8.2 xx 10^(12)" Litre." A power station not so far above. Cayuga's water produces electricity at a rate of 1.5 xx 10^(6) Coulomb per second at an appropriate voltage. How long would it take to electrolyse the lake?

Laevorotatory substance or l-Isomer.

Lactose on hydrolysis produces

Lactose on hydrolysis yields :

Lactose on hydrolysis gives

Lactose has thesame molecular formula as :

Lactose has …………………..

Lactose can be names as

Lactoseact as reducingsugar. Justifythisstatement .

Lactic acid shows

Lactic acid show which type of isomerism

Lactic acid on oxidation with Fenton.s reagent gives main product:

Lactic acid on oxidation by alkaline potassium permanganate gives

Lactic acid on oxidation with Fenton's reagent gives:

Lactic acid molecule has

Lactic acid is a classical example of ___________.

Lactic acid in which a methyl group, a hydroxyl group, a carboxylic acid group and a hydrogen atom are attached to a central carbon atom, show optical isomerism due to the molecular geometry at the

Lactic acid CH_3-oversetoverset(OH)(|)C-CH-oversetoverset(O)(||)C-OH can be prepared by acid hydrolysis of reaction product of

Lactic acid and glycolic acid are the monomers used for preparation of polymer