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Latent heat of fusion of ice is "1436.3 cal mol"^(-1). Calculate the molal depression constant of water. |
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Answer» Solution :`K_(f)=(M_(1)RT_(0)^(2))/(1000Delta_("FUS")H)=("18 GMOL"^(-1)XX"2 cal K"^(-1)"mol"^(-1)xx(273 K)^(2))/("1000 g kg"^(-1)xx"1436.3 cal mol"^(-1))` `="1.87 K kg mol"^(-1)` |
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