Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Change in Amino acid sequence leads to

Answer»

mutation
Translation
Fermentation
Genetic code

Answer :A
Discussion
2.

Chalk powder is added to hydrolysed solution of starch during the manufacture of glucose

Answer»

for HYDROLYSIS it is necessary
for cooling of SULPHURIC acid
for ALKYLATION of sulphuric acid
because the HYDROLYSED solution of starch contains excess of sulphuric acid which as neutralised by chalk powder.

Answer :D
Discussion
3.

Chalgogens are also called as ……………… .

Answer»

Ore forming ELEMENTS
Group -16 elements
group 17 elements
Both (a) and (b)

SOLUTION :Both (a) and (b)
Discussion
4.

Chald power is added to the hydrolysed solution of starch, in the manufacture of glucose. Give reasons.

Answer»

Solution :In the manufacture of glucose, STARCH is HYDROLYZED by dilute sulphuric acid. To neutralize EXCESS of acid, chalk powder is added. Chalk power is calcium carbonate `(CaCO_(3))` which reacts and neutralizes excess acid and forms precipitate of calcium sulphate which can be removed by filtration.
`H_(2)SO_(4)+CaCO_(3)overset("Neutralization")rarr CaSO_(4) darr +H_(2)O+CO_(2)`
Discussion
5.

Chalcogens belongs to p - block. Give reason.

Answer»

Solution :Chalcogens are ore forming ELEMENTS. Most of the ores are OXIDES and sulphides, therefore oxygen, sulphur and other group 16 elements are called Chalcogens. In O, S, Se, TE and `P_(o)` LAST electron enters to p - orbital. Therefore Chalcogens BELONGS to p - block.
Discussion
6.

Chalcogens belongs to p-block. Give reason.

Answer»

SOLUTION :Chalcogens are ore FORMING elements. Most of the ores are oxides and SULPHIDES, therefore oxygen, sulphur and other group 16 elements are called Chalcogens. In `O, Te and P_(o)` last electron enters t o p - orbital. Therefore Chalcogens BELONGS to p - block.
Discussion
7.

Chalcogens are

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Oxide FORMING ELEMENT
Ore forming element
Those having ability to catenate
Hydrocarbons

Answer :B
Discussion
8.

Chalcogens are :

Answer»

HYDROCARBONS
ORE formating elements
Oxide FORMING elements
Those having ability to catenate

Answer :B
Discussion
9.

Chair form of S_(6) rings are present in

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`alpha` - SULPHUR
`BETA`- sulphur
Engle's sulphur
`GAMMA` - sulphur

ANSWER :C
Discussion
10.

Chair form of cyclohexane is more stable than boat form because :

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In CHAIR form carbons are in staggered form and in boat form carbons are in eclipsed form
In chair form carbons are in eclipsed form and in boat form all the carbons are in eclipsed form
BOND ANGLE in CHIAR form is `111^(@)` and bond angle in boat form is `109.5^(@)`
Bond angle in chair form is `109.5^(@)` and in boat form `111^(@)`

Answer :A
Discussion
11.

Chain transfer reagent is

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`C Cl_4`
`CH_4`
`O_2`
`H_2`

ANSWER :A
Discussion
12.

Chain initiation and chain propagation steps are involved in

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all
only a, B and C
only a
only a and c

ANSWER :B
Discussion
13.

Chain growth polymerization may proceed by the following mechanism

Answer»

Condensation polymerization
Cationic polymerization
Anionic polymerization
Free radical polymerization

Solution :In chain growth polymerization, the mechanism is either free radical or ionic.
Free radical mechanism Initiation
`R-overset(O)overset(||)(C)-O-O-overset(O)overset(||)(C)-R overset(DELTA)2R -underset(O)underset(||)(C)-O^(.)`
`R-underset(O)underset(||)(C)-O^(.) to R^(.) +CO_(2)`
Propagation, `R^(.)+ nCH_(2) =CH_(2) to R-CH_(2)-CH_(2)`
`(-CH_(2)-CH_(2)-)_(n) CH_(2) overset(.)(C)H_(2)`
Termination, `overset(.)(R)+overset(.)(R) to R-R `
`2R-CH_(2)CH_(2)-(CH_(2)-CH_(2)-)_(n) CH_(2) overset(.)(C)H_(2) to R-CH_(2)CH_(2)-(-CH_(2)-CH_(2)-)_(n) CH_(2)CH_(2)R`
Ionic
These are initiated by `CuSO_(4).HF` in `H_(2)O` for cationic polymerization .
Initiation `H_(2)SO_(4)H^(+) +F^(-)`
`H^(+) +CH_(2) =CH_(2) to CH_(3) CH_(2) -(CH_(2)-CH_(2)-)_(n)CH_(2)-overset(o+)(C)H_(2)`
Termination

Hence choices (b),(c) and (d) are correct while (a) is incorrect.
Discussion
14.

Chain growth polymerisation is important reaction for ?

Answer»

PTFE
Nylon-26
polyester
Bakelite

ANSWER :A
Discussion
15.

CH_(4) underset(hv)overset(Cl_(2))rarr A overset(Na)rarr B underset(hv)overset(Cl_(2))rarr C underset(NaOH)overset("aqueous")rarr D overset((O))rarrE underset(K_(2)O_(2)O_(7)//H^(+))overset((O))rarr F overset(Ca(OH)_(2))rarr G overset("Heat")rarr H. What is the functional isomer of the product 'H'.

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SOLUTION :`C_(2)H_(5)CHO`
Discussion
16.

CH_(4) rarr C Cl_(4). In the above conversion what happens to the oxidation number of carbon

Answer»


ANSWER :INCREASES from -4 to +4
Discussion
17.

CH_4 is formed when

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SODIUM acetate is heated with sodalime
IODOMETHANE is reduced
Aluminium carbide REACTS with water
All of these

Solution :`underset"Sod.acetate"(CH_3COONa)+NaOHoverset"CAO"to CH_4+Na_2CO_3`
`underset"Iodomethane"(CH_3I)+2Hunderset"reduction"to CH_4+HI`
`underset"Aluminium carbide"(Al_4C_3 + 6H_2O)to 3CH_4 + 2Al_2O_3`
Discussion
18.

CH_4 gas is obtained in :- (a)Hydrolysis of Al_4C_3 (b)Hydrolysis of Be_2C (c )Hydrolysis of Mg_2C_3 (d) Hydrolysis of CaC_2

Answer»

only a, B, C
only a, b
only a, c
only b, c, d

Solution :`Al_2C_3 + 12H -OH to 4Al(OH)_3 + 3CH_4`
`Be_2C + 4H-OH to 2Be(OH)_2+CH_4`
Discussion
19.

CH_(4) (g) and O_(2) (g) react according to the given equation: CH_(4) (g) + 2O_(2) (g) rarr CO_(2) (g) + 2H_(2) O (l) Assuming that reaction take placed and goes to completion.If valve is opened then [Assume temperature remains constant 300 K throughout ]

Answer»

`CH_(4)` gas is left after the reaction
`O_(2)` gas is left the reaction.
Total pressure is `(1)/(3)` atm after the reaction .
After the reaction pressure in both the vessels will REMAIN same

Solution :`n_(CH_(4)) = (0.5 xx 2)/(R xx 300) = (1)/(300 R)`
`n_(O_(2)) = (1 xx 1)/(R xx 300) = (1)/(300 R)`
`{:(,CH_(4) (g),+,2O_(2) (g),RARR,CO_(2) (g),+,2H_(2) o (l),),("Mole initially",(1)/(300R),,(1)/(300 R),,-,,-,):}`
`O_(2)` is LR
`CH_(2)` will be left after the reaction
`{:("Mole at",(1)/(600 R),0,(1)/(600 R),-,),("Completion",,,,,):}`
Total moles after completion `= n_(CH_(4) + n_(CO_(2))`
`= (1)/(600 R) + (1)/(600 R)`
`(1)/(300 R)`
`P = (nRT)/(V) = (1)/(300 R) xx (R xx 300)/(3) = (1)/(3)` atm
Discussion
20.

CH_4+ Cl_2 underset(-HCl)overset(hv)(rarr) A underset(-HCl)overset(+Cl_2)(rarr)B underset(-HCl)overset(+Cl_2)(rarr) C C underset(-HCl)overset(+Cl_2)(rarr) D Correct order of Dipole moments is

Answer»

` D GT C gt B gt A `
` C gt B gt A gt D `
` A gt C gt B gt D `
` A gt B gt C gt D `

ANSWER :D
Discussion
21.

CH_(4)+Cl_(2)overset(hv)(to)CH_(3)Cl+HCl the order of this reaction is

Answer»

`0`
`1`
`2`
`3`

ANSWER :A
Discussion
22.

CH_3underset(CH_3)underset(|)oversetoverset(CH_3)|C-undersetunderset(OH)|CHCH_3 overset(HBr)to A(predominant), A is

Answer»

`(CH_3)_3C oversetoverset(BR)|CHCH_3`
`(CH_3)_2oversetoverset(Br)|C CH(CH_3)_2`
both 'a' and 'b'
none is correct

Answer :B
Discussion
23.

CH_(3)overset(O)overset(||)(C)-Cl overset(x)rarr CH_(3)CHO. CH_(3)-overset(O)overset(||)(C)-Cl overset(y)rarr CH_(3)-overset(O)overset(||)(C)-CHO What are x and y ?

Answer»

PD-`BaSO_(4)`/Quinoline, `(CH_(3))_(2)CD`
Pd-`BaSO_(4)`/Quinoline, DIBAL-H
DIBAL - H, `LiAlH_(4)`
DIBAL-H, `(CH_(3))_(2)Cd`

Answer :A
Discussion
24.

CH_(3)overset(O)overset(||)(C)CH_(2) overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)CHO overset(KOH,H_(2)O)underset(Delta)to product (C_(7)H_(10)O) :

Answer»




ANSWER :C
Discussion
25.

CH_(3)-overset(CH_(2)CH_(3))overset(|)(CH)CH=CHCH_(3)overset(H_(3)O^(+))rarr Major product of the reaction

Answer»

is an potical isomer
gives WHITE turbidity with with Lucas reagent immediately
is DEHYDRATED EASILY
All options are correct.

Solution :
The alcohol FORMED is:
Optically ACTIVE
Gives white turbidity with Lucas reagent immediately as it is a tertiary alcohol
is dehydrated easily
Discussion
26.

CH_(3)OH+ C_(6)OH+ C_(6)H_(5)COOH overset(H^(+)) hArr X+ H_(2)O : What is X?

Answer»

Phenyl methanol
Benzophenone
Methyl benzoate
Phenyl benzoate

Solution :`underset("Methanol")(CH_(3)OH)+ underset("BENZOIC ACID")(C_(6)H_(5)COOH) overset(H^(+))hArr underset("Methyl benzoate")(C_(6)H_(5)COOCH_(3))+ H_(2)O`
Discussion
27.

CH_3OCH_2CH_3 overset(+HI)(to) CH_3I + CH_3CH_2OHIt follows which mechanism ?

Answer»

`S_N1`
` S_N2`
` E_1`
`E_2`

ANSWER :B
Discussion
28.

CH_(3)OC_(2)H_(5) and (CH_(3))_(3)COCH_(3) are treated with hydriodic acid. The fragments after reaction obtained are:

Answer»

`CH_(3)I+HOC_(2)H_(5), (CH_(3))_(3)C-I+HOCH_(3)`
`CH_(3)OH+C_(2)H_(5)I,(CH_(3))_(3)C-I+HOCH_(3)`
`CH_(3)OH+C_(2)H_(5)I,(CH_(3))_(3)C-OH+CH_(3)I`
`CH_(3)I+HOC_(2)H_(5),CH_(3)I+(CH_(3))_(3)C-OH`

Solution :`CH_(3)OC_(2)H_(5)` undergoes CLEAVAGE by `S_(N)2` mechanism to give `CH_(3)I and C_(2)H_(5)OH` while `(CH_(3))_(3)COCH_(3)` undergoes cleavage by `S_(N)1` mechanism to give `(CH_(3))_(3)Cl and CH_(3)OH`
Discussion
29.

CH_(3)O-CH=CH_(2)underset(H^(+))overset(CH_(3)OH)rarrproduct formed is

Answer»

Aceta
Hemiacetal
Alcohol
aldehyde

Answer :A
Discussion
30.

CH_(3)O-CH_(3) is

Answer»

LEWIS acid
Arrhenius acid
Lewis base
Bronsted acid

Answer :C
Discussion
31.

CH_(3)NO_(2)overset(Sn_(+)HCl)rarrCH_(3)X, the 'X' contain

Answer»

`-NH_(2)`
`-COOH`
`-CHO`
`(CH_(3)CO)_(2)O`

SOLUTION :`CH_(3)NO_(2)+6Hunderset(HCl)overset(Sn)rarrCH_(3)NH_(2)+2H_(2)O`
Discussion
32.

CH_(3)NO_(2) overset(300^(@)C)rarr X + Y + Z In this sequence X + Y + Z are

Answer»

METHANE `+N_(2) + CO_(2)`
`CO_(2) + (3)/(2) H_(2) + (1)/(2) N_(2)`
`C_(2)H_(6) + N_(2) + H_(2)`
`CO_(2) + H_(2) + N_(2)`

Solution :`CH_(3)NO_(2) OVERSET(300^(@)C)(rarr) CO_(2)+3/2 H_(2)+1/2 N_(2)`
Discussion
33.

CH_3NO_2+6[H] overset(X?)(to)CH_3NH_2+2H_2O. 'X' is

Answer»

`Sn"/"HCl`
`ZN"/"NH_4Cl`
GLUCOSE `+NAOH`
`Na_3A_5O_3"/"NaOH`

ANSWER :A
Discussion
34.

CH_(3)NH_(2) overset((CH_(3))_(2)O)to (A) What is (A)? Explains why (A) is less reactive than methylamine?

Answer»

SOLUTION :
Discussion
35.

CH_3NH_2 in water act as :

Answer»

ACID
Base
Ester
Salt

Answer :B
Discussion
36.

CH_3NH_2 reacts with CH_3MgX to give:

Answer»

Acetone
Alcohol
Methane
Ethane

Answer :C
Discussion
37.

CH_(3)NH_(2) is obtained fromNH_(3) by

Answer»

Hoffmansreaction
Cannizzarosreaction
WURTZ REACTION
NONEOF these

ANSWER :A
Discussion
38.

CH_3NH_2+CHCl_3 + KOH to "Nitrogen containing compound" + KCl + H_2O The nitrogen containing compound is

Answer»

`CH_3-C-=H`
`CH_3-NH-NH_3`
`CH_2-barN=barC`
`CH_3-Noverset(to)(=)(C)`

ANSWER :D
Discussion
39.

CH_(3)NH_(2)+CHCI_(3)+KOHrarr nitrogen containing compound + KCI+H_(2)O . Nitrogen containing compound is

Answer»

`CH_(3)-C-=N`
`CH_(3)NH-CH_(3)`
`CH_(3)-N-=C^(+)`
`CH_(3)N^(+)-=C^(-)`

SOLUTION :`CH_(3)NH_(2)+CHCI_(3)+3KOH(ALC.) rarr CH_(3)N^(+) -=-= C+3KCI+3H_(2)O`
This is known as carbylamine reaction .
Discussion
40.

CH_3NH_2 + CH_3COCl rarr _____ + HCl

Answer»

SOLUTION :`CH_3CONHCH_3`
Discussion
41.

CH_(3)I overset(DMSO)rarr[X]. The major product [X] is

Answer»

`"["Me _(3)overset(+)S=O"]"I^(-)`
`"["Me _(2)overset(+)S-OMe"]"I^(-)`
both (a) and (b)
none of these.

Solution :`DMSO "(" Me_(2)overset(..)(S)=overset(..)(O)")"` is an ambident NUCLEOPHILE. i.e., the NUCLEOPHILES which have more than one ( generally two ) suitable atoms through which they can attack the substrate are known as ambident nucleophiles.
`:.` Methylation of DMSO with Mel gives two isomers (A) and (B) from S-methylation and from O-methylation, respectively.
Since .S. is better nucleophilic site ( because .O. is more electronegative than .s. ), (A) is the major product
Discussion
42.

CH_(3)COONH_(2) is a weaker base than CH_(3)CH_(2)NH_(2). Why?

Answer»

SOLUTION :Due to resonance, the lone pair of electrons on the nitrogen atom in `CH_(3)CONH_(2)` is delocalised over the keto group. There is no such EFFECT IP `CH_(3)CH_(2)NH_(2)`. Due to reduction in electron density on N-atom of `CH_(3)CONH_(2)` It is a weaker BASE than `CH_(3)CH_(2)NH_(2)`.
Discussion
43.

CH_(3)COOHoverset(LiAlH_(4))(to)X underset(300^(@)C)overset(Cu)(to) Y underset(NaOH)overset("dilut")(to)Z In the above reactionZ is

Answer»

Aldol
Ketol
Acetol
Butanol

Solution :`CH_(3)COOHoverset(liAlH_(4))(to)UNDERSET(X)(CH_(3)CH_(2)OH)underset(300^(@)C)overset(Cu)(to)`
`underset(Y)(CH_(3)CHO)overset(dil.NaOH)(to)CH_(3)-underset(Z)underset(OH)underset(|)(CH)-CH_(2)CHO`
Acetaldehyde (Y) UNDERGOES aldol condensation in presence of dilute caustic alkali to form aldol.
Discussion
44.

CH_(3)COOH underset(P_(2)O_(5))overset(Delta)toX. Identify X

Answer»

`CH_(3)COCH_(3)`
`CH_(3)CHO`
`(CH_(3)CO)_(2)O`
`CH_(4)`

SOLUTION :`CH_(3)COOH overset(Delta//P_(2)O_(5))to(CH_(3)CO)_(2)O`
Discussion
45.

CH_(3)"COOH" underset(Br_(2))overset("AgOH")(rarr)"[A]" overset("AgCN") [B] overset("HOH")(rarr) [ C] + [D], in reaction [C] & [D] are

Answer»

`(CH_(3))_(2) NH + H_(2)`O
`(CH_(3))_(2)` NH + HCOOH
`CH_(3)NH_(2) + ` HCOOH
`CH_(3)"COOH" + NH_(3)`

ANSWER :C
Discussion
46.

CH_3COOH reacts rapidly with :

Answer»

`CH_3CH_2OH`
`(CH_3)_2CHOH`
`(CH_3)_3COH`
All

ANSWER :A
Discussion
47.

CH_(3)COOH overset(LiAlH_(4))toA A+CH_(3)COOH overset(H_(3)O^(+))to B+H_(2)O In the above reaction 'A' and 'B' respectively are

Answer»

`CH_(3)COOC_(2)H_(5),C_(2)H_(5)OH`
`CH_(3)CHO,C_(2)H_(5)OH`
`C_(2)H_(5)OH,CH_(3)CHO`
`C_(2)H_(5)OH,CH_(3)COOC_(2)H_(5)`.

ANSWER :D
Discussion
48.

CH_(3)COOH overset(Delta)rarr CH_(3)COCl, What is A?

Answer»

`PCl_(5)`
`Cl_(2)`
`HCL`
`COCl_(2)`

SOLUTION :`CH_(3)COOHoverset(PCl_(5))rarr CH_(3)COCl+HCl`
`therefore` A is `PCl_(5)`. It can also be `SOCl_(2)`.
Discussion
49.

CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))to W+S Write the structure of X,Y,Z , W and S

Answer»


ANSWER :`X=Cl_(3)C-UNDERSET(O)underset(||)(C)-OH,Y=Cl_(3)C-underset(O)underset(||)(C)-Cl,Z=Cl_(3)C-underset(O)underset(||)(C)-H,W=CHCl_(3),S=HCOO^(Theta)`
Discussion
50.

CH_(3)COOH is weaker acid than H_(2)SO_(4). It is due to

Answer»

More IONIZATION
LESS ionization
Covalent bond
Electrovalent bond

Solution :The `CH_(3)COOH` is weaker ACID than `H_(2)SO_(4)`. The reason is that `CH_(3)COOH` is WEAKLY ionised in comparison with `H_(2)SO_(4)`.
Discussion