CH_3underset(CH_3)underset(|)oversetoverset(CH_3)|C-undersetunderset(O – InterviewSolution

1.	CH_3underset(CH_3)underset(\|)oversetoverset(CH_3)\|C-undersetunderset(OH)\|CHCH_3 overset(HBr)to A(predominant), A is
Answer» `(CH_3)_3C oversetoverset(BR)\|CHCH_3` `(CH_3)_2oversetoverset(Br)\|C CH(CH_3)_2` both 'a' and 'b' none is correct Answer :B

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